Answers
Answer:
A
Explanation:
Halogens have 7 electrons in their valence shell and requires just one electron to achieve their stable structure. Because of this they have high electron affinity and hence high electronegativity and they are strong oxidizing agents. Oxidation is the loss of electrons . Halogens have a high readiness to take electrons which a metal loses thereby oxidizing it. The other options are wrong as they involve compounds and not the elemental form as stated in the question.
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About 40 different substances called organophosphorus compounds are registered in the United States as insecticides. They are considered less damaging to the environment than some other insecticides because they breakdown relatively rapidly in the environment. The first of these organophosphorus insecticides to be produced was tetraethyl pyrophosphate, TEPP, which is 33.11% carbon, 6.95% hydrogen, 38.59% oxygen, and 21.35% phosphorus. It has a molecular mass of 290.190. What is the molecular formula for TEPP?
Identify the characteristics that describe how human proteins are assembled. Check all that apply.
Answers
Answer:
The number of protons in an atom is always equal to the atomic number.
Explanation:
Answers
Answer:
I think the second space is chemical bonds
B. ethyl alcohol
C.sulfuric acid
D.All chemicals are potentially dangerous
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Answer:
D.All chemicals are potentially dangerous
Explanation:
No chemical is toxicologically neutral
Answers
Answer:
226.2 kJ/mol
Explanation:
Let's consider the following thermochemical equation for the combustion of acetylene.
C₂H₂(g) + (5/2) O₂(g) → 2 CO₂(g) + H₂O(l), ΔH°rxn = –1299 kJ/mol.
We can also calculate the enthalpy of the reaction per mole of acetylene from the enthalpies of formation.
ΔH°rxn = 2 mol × ΔH°f(CO₂(g)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(C₂H₂(g)) - 1 mol × ΔH°f(O₂(g))
1 mol × ΔH°f(C₂H₂(g)) = 2 mol × ΔH°f(CO₂(g)) + 1 mol × ΔH°f(H₂O(l)) - ΔH°rxn - 1 mol × ΔH°f(O₂(g))
1 mol × ΔH°f(C₂H₂(g)) = 2 mol × (-393.5 kJ/mol) + 1 mol × (-285.8 kJ/mol) - (-1299 kJ) - 1 mol × (0 kJ/mol)
ΔH°f(C₂H₂(g)) = 226.2 kJ/mol
Answer:
The enthalpy of formation of acetylene is 226.2 kJ/mol
Explanation:
Step 1: Data given
C2H2 (g) + (5/2)O2 (g) → 2CO2 (g) + H2O (l) Heat of Reaction (Rxn) = -1299kJ/mol
Standard formation [CO2 (g)]= -393.5 kJ/mol
Standard formation [H2O (l)] = -285.8 kj/mol
Step 2: The balanced equation
The formation of acetylene is:
2C(s) + H2(g) → C2H2(g)
Step 3: Calculate the enthalpy of formation of acetylene
It doesn't matter if the process will happen in 1 step or in more steps. What matters is the final result. This is Hess' law of heat summation.
To have the reaction of the formation of acetylene we have to take:
⇒ the reverse equation of the combustion of acetylene
2CO2 (g) + H2O (l) → C2H2 (g) + (5/2)O2 (g)
⇒ The equation of formation of CO2 (multiplied by 2)
2C(s) + 2O2(g) → 2CO2(g)
⇒ the equation of formation of H2O
H2(g) + 1/2 O2(g) → H2O(l)
2CO2 (g) + H2O (l) + 2C(s) + 2O2(g) + H2(g) + 1/2 O2(g → C2H2 (g) + (5/2)O2 (g) + 2CO2(g) + H2O(l)
Final reaction = 2C(s) + H2(g) → C2H2(g)
Calculate the enthalpy of formation of acetylene =
ΔHf = 1299 kJ/mol + (2*-393.5) kJ/mol + (-285.8) kJ/mol
ΔHf = 226.2 kJ/mol
The enthalpy of formation of acetylene is 226.2 kJ/mol
Answers
Actually Welcome to the Concept of the Kinematics.
Here, we know that, Velocity = Distance / Time,
So here, Distance = 10km = 10×1000 = 10000 metres.
, Time = 14 min 30 sec = 870 seconds,
so now, we get velocity as,
=> V = 10000 ÷ 870 => 11.49 m/s .
Hence, Velocity is 11.49 m/s.
Answers
For a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
What is ion?
An atom or molecule is said to be an ion if one or more of whose valence electrons have been acquired or lost, providing it a net negative or positive electrical charge.
Faraday knew that metals disintegrated together into solution place at a single electrode and that a second metal was placed first from solution at the opposite electrode, as such matter had to be trying to move underneath the impact of an electrical current even though he was unable to identify the particles trying to move between the electrodes. For a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
Therefore, for a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
To learn more about ion, here:
#SPJ6
Answer:
as the charge of the ions increases, the lattice energy increases. as the size of the ions increases, the lattice energy decreases.