MATHEMATICS HIGH SCHOOL

Apertures for the diffraction studied in this chapter are __________. A. a single slit.B. a circle.
C. a square.
D. both A and B.
E. both A and C.

Answers

Answer 1
Answer:

Answer: the correct option is D

Step-by-step explanation:

Note: the chapter summary can be found in chapter 22 of the Pearson Education,Inc. (PDF format).

In the chapter, a single slit aperture diffraction and a circle aperture diffraction was discussed.

A circle aperture diffraction occurs when light pass through a tiny hole or aperture to produce a circular disc image. This disc is called Airy's disc.

To calculate the aperture diameter,d we can use the formula below;

d= m× λ/ sin θ. ------------------------------------------------------------------------------(1).

The single slit aperture diffraction is when light pass through a single slit to produce. The wavelength, λ is greater than the width of the aperture.

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Please help on my question

Answers

area of square=side legnth^2
area=121=legnth^2
121=l^2
sqare root both sides
11=legnth

11 yards=legnth



3.69=3.00+0.60+0.09 so the answer i s C

PLEASE HELP Polynomial Graph Studies Polynomials are great functions to use for modeling real-world scenarios where different intervals of increase and decrease happen. But polynomial equations and graphs can be trickier to work with than other function types. In mathematical modeling, we often create an equation to summarize data and make predictions for information not shown on the original display. In this activity, you’ll create an equation to fit this graph of a polynomial function. Part A Describe the type of function shown in the graph. Part B What are the standard form and the factored form of the function? Part C What are the zeros of the function? Part D Use the zeros to find all of the linear factors of the polynomial function. Part E Write the equation of the graphed function f(x), where a is the leading coefficient. Use the factors found in part D. Express the function as the product of its leading coefficient and the expanded form of the equation in standard form. Part F Use the y-intercept of the graph and your equation from part E to calculate the value of a. Part G Given what you found in all of the previous parts, write the equation for the function shown in the graph.

Answers

Answer:

Here's what I get  

Step-by-step explanation:

Part A

The graph shows a polynomial of odd degree. It is probably a third-degree polynomial — a cubic equation.

Part B

The standard form of a cubic equation is

y = ax³ + bx² + cx + d

The factored form of a cubic equation is

y = a(x - b₁)(x² + b₂x + b₃)

If you can factor the quadratic, the factored form becomes

y = a(x - c₁)(x - c₂)(x - c₃)

Part C

The zeros of the function are at x = -25, x = - 15, and x = 15.

Part D

The linear factors of the function are x + 25, x + 15, and x - 15.

Part E

y = a(x + 25)(x + 15)(x - 15) = a(x + 25)(x² - 225)  

y = a(x³ + 25x² - 225x - 5625)

Part F

When x = 0, y = 1.

1 = a[0³ +25(0)² - 225(0) - 5625] = a(0 + 0 - 0 -5625) = -5625a

a = -1/5625

Part G

y = -(1)/(5625)( x^(3) + 25x^(2) - 225x - 5625)\n\ny = \mathbf{ -(1)/(5625) x^(3) - (1)/(225)x^(2) + (1)/(25) x + 1}

Answer

Actually, the answer should be -0.0007(x+20)(x+5)(x-15)

Step-by-step explanation:

This is continuing off of the previous answer

PART C

The zeros should be (15,0), (-5,0), and (-20,0)

PART D

x - 15, x + 5, and x + 20

PART E

a(x - 15)(x + 5)(x + 20)

Standard: a(x^(3) + 10x^(2) -275x-1500)

PART F

The y-intercept is at (0,1), so we replace the x's with 0:

1 =[(0)x^(3) +10(0)x^(2) -275(0)-1500] and this gives us (0+0-0-1500) which also equals -1500

Then we do (1)/(-1500) which gives us -0.0006 repeating which rounds to -0.0007

a= -0.0007

PART G

Just place the numbers where they should go and your answer is

y =-0.0007(x + 20)(x + 5)(x - 15)  

the placement for (x + 20) (x + 5) and (x - 15) doesn't matter as long as they are behind -0.0007

True or false:A linear binomial has a degree of 0

A trinomial has a degree of 2

A constant has a degree of 1

A cubic monomial has a degree of 3

I will mark as the top answers of you help me!

Answers

Answer:

The degree of a binomial is zero. The product of two binomials is not a polynomial. The sum of two polynomials is a polynomial. A monomial containing ^2 has a degree of three

The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s). Examples: 5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

Names of Degrees

Degree Name Example

0 Constant 7

1 Linear x+3

2 Quadratic x2−x+2

3 Cubic x3−x2+5

The degree of a cubic monomial is three. A quadratic polynomial is a trinomial. The degree of a binomial is two.

Step-by-step explanation:

Identify the value of p.

p = 11
p = 10
p = 12
p = 13

Answers

Answer:

  (c)  p = 12

Step-by-step explanation:

You may recall that (5, 12, 13) is a Pythagorean triple. That would tell you ...

  p = 12

__

If you have not memorized a few useful Pythagorean triples, you can use the Pythagorean theorem to solve for p. The sum of squares of the sides is the square of the hypotenuse:

  5² +p² = (p+1)²

  p² +25 = p² +2p +1

  24 = 2p . . . . . . . . subtract p²+1 from both sides

  p = 12 . . . . . . divide by 2

_____

Additional comment

Some of the Pythagorean triples commonly seen in algebra and geometry problems are ...

  (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17), (9, 40, 41)

Of course, multiples of these are used, too. For example, (6, 8. 10) is a multiple of the (3, 4, 5) triple.

Answer:

12

Step-by-step explanation:

5^2 + p^2 = (p+1)^2

25 + p^2 = p^2 + 2p + 1

25 = 2p + 1

24 = 2p

12 = p

I need help with this !!!!!!!!!!!

Answers

the answer to this question is a

12x8+4-4=what is the answer?

Answers

12*8=96 add 4 then subract 4 keeps you at 96. ANSWER=96

Answer: 96

Step-by-step explanation:

12 x 8 = 96

4 - 4 = 0

96 + 0

= 96
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