What equation gives the position at a specific time for an object with constant acceleration?

Answers

Answer 1
Answer:

Answer:

x = x_(0)+v_(0)t+(1)/(2)at^(2)equation gives the position at a specific time for an object with constant acceleration

Explanation:

x = x_(0)+v_(0)t+(1)/(2)at^(2) equation gives the position at specific time for an object having constant acceleration. Constant acceleration is referred as the change of velocity with respect to the time is known as the acceleration, but when the velocity changes occurs at constant rate this rate is termed as the constant acceleration. The constant acceleration can never be zero. The velocity changes but that change occurs in the consistently. The acceleration is affected by the mass.


Related Questions

Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?
Which element was discovered by joseph priestley to be what his contemporaries called ""dephlogisticated air""?
CAN SOMEONE HELP ME PLEASE
radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. it is this radiation that causes dyes to fade and your skin to develop a sunburn. if you are bombarded with 1.00 mol of photons with a wavelength of 370. nm, what amount of energy, in kilojoules per mole of photons, are you being subjected to?
Which statements about velocity are true?Check all that apply. A. For velocity, you must have a number, a unit, and a direction. B. The SI units for velocity are m/s2. C. The symbol for velocity is . D. To calculate velocity, divide the displacement by time.

Martha and Mary are trying to move an old toy Barbie Jeep that is broken up a hill. Martha is applying 35 N of force and Mary is applying 20 N of force. What is the net. force being applied to the box and is it balanced or unbalanced

Answers

Answer: Net Force is 15 N towards Martha

Its an unbalanced force

Explanation:

What is the mass of a person weighing 600 N?

Answers


Weight = (person's mass) x (acceleration of gravity in the place where he is)

You can see that it all depends on where he was weighed, because
the same mass has different weights in different places.

If he was weighed on Earth, where gravity = 9.8 m/s², then

     600 N = (mass) x (9.8 m/s²)

     Mass  =  600 N / 9.8m/s²  =  61.22... kg (rounded)

What pressure, in millimeters of mercury (mm Hg), is equivalent to 2.13 atmospheres

Answers

The "Standard Atmosphere" is 760 mm Hg . 2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.

A rotating satellite has the same angular velocity as the earth. If the satellite is 5x10^7 m from the center of the earth, what is its tangential velocity

Answers

We will want to be using radians for this question so that we can calculate arc lengths easily.

The angular velocity of the earth is 360^(o)/24\ hr=(2\pi)/(24\ hr)=(\pi)/(12)/hr

The satellite tangential velocity is the distance from the earth times the angular velocity, which is
5*10^(7)\ m*(\pi)/(12)/hr\approx1.309*10^(7)\ m/hr

For meters per second, we divide by the number of seconds in an hour, which is 3600:
1.309*10^(7)\ m/hr*(1\ hr)/(3600\ s)\approx3636\ m/s

Final answer:

The tangential velocity of a satellite, with the same angular velocity as the Earth and 5x10^7 m distance from Earth's center, is calculated to be approximately 3650 m/s.

Explanation:

The tangential velocity of a satellite is given by the formula v = rω, where 'v' is the tangential velocity, 'r' is the radius (distance from the center of the Earth to the satellite), and 'ω' is the angular velocity. The referenced satellite's angular velocity is the same as that of the Earth, which is approximately 7.292 x 10^-5 rad/s. Given r = 5x10^7 m (the satellite's distance from Earth), we input these values into the formula:

v = (5x10^7 m)(7.292 x 10^-5 rad/s)

Upon calculation, we find that the satellite's tangential velocity is approximately 3650 m/s.

Learn more about Tangential Velocity here:

brainly.com/question/33443064

#SPJ6

Haloke does 176 J of work lifting himself 0.300m at a constant speed. What is Haloke's mass?

Answers

Since he's lifting himself at constant speed ... not accelerating ... the net vertical force on
him is zero, meaning that he must be lifting with force that's exactly equal to his weight.

Potential energy he added during the lift = (mass) x (gravity) x (height)

Mass = (energy) / (gravity x height) = 176 / (9.8 x 0.3) = 59.864 kg

A man is carrying a trolley of mass 6kg and having K.E. of 40 J . Calculate its velocity with which he is running .

Answers

The formula to find kinetic energy is -

K.E. = (1)/(2)*m* v^(2)

Where,

m = mass

and

v = velocity

So, putting the values in the formula we get -

40 = (1)/(2) *6*v^(2)

(40)/(3) = v^(2)

\sqrt (40)/(3) = 3.6514 m/s
As we know that K.E = 1/2 mv² so
 by arranging it 
K.E ×2÷6 = v²
now by putting values
v²=13.33 m²/s²
so
v= 3.65 m/s....