Write y= -3/4 x-6 in standard form using integers.

The product of (x – 3)(2x + 1) will be 2x² - 5x -3. Thus, option B is correct.

What is a Quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

Given

(x – 3)(2x + 1) is a expression.

How to find the quadratic equation?

The product of (x – 3)(2x + 1) will be.

(x – 3)(2x + 1)

2x² -6x + x - 3

2x² - 5x -3

The product of (x – 3)(2x + 1) will be 2x² - 5x -3.

Thus, option B is correct.

More about the quadratic equation link is given below.

brainly.com/question/2263981

All you have to do is to use the distributive property

(x)(2x)+(x)(1)+(-3)(2x)+(-3)(1)

= 2x² + x - 6x -3

= 2x² - 5x - 3

The answer is B

I hope that's help:0

Answer:

Is that all you need help with or you need help with more?

Step-by-step explanation:

Your answer should be 46.  

Hope it helps!

Answer:

x+8

Step-by-step explanation:

Simplify the numerator

list the factors of 16

16: 1, 2, 4, 8, 16

look for two factors that add up to the b value

in this case it is 18

by looking at the factors 2 and 8 add up 10

so you can rewrite the numerator as

Split the trinomial into two separate binomials each having one of the factors that add up to 10

So it should be

Factor both binomials

you can factor an x from the first one

Then it is x(x+2)

Factor an 8 from the second one

8(x+2)

So it should be

This can rewritten as (x+8)(x+2)

So now you have

simplify it by canceling out the two (x+2)'s

this is because (x+2)/(x+2) is 1

Finally you get x+8

Answer:

a) P ( T < 250 mins ) = 0.7695

b) P ( T > 260 mins ) = 0.1344

Step-by-step explanation:

- The RV from a sample has the following parameters that are mean = 5 mins, and standard deviation s = 4 mins.

- The entire population has n = 46 students.

- We will first compute the population mean u and population standard deviation σ as follows:

                            u = n*mean

                            u = 46*5 = 230 mins

                            σ = sqt ( n ) * s

                            σ = sqt ( 46 ) * 4

                            σ = 27.129 mins

- Approximating that the time taken T to grade the population of entire class follows a normal distribution with parameters u and σ as follows:

                            T~ N ( 230 , 27.129 )

Find:

- If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins?

- The total time till 6:50 PM to 11:00 PM is ( 4 hr and 10 mins ) = 250 mins.

- We will compute the Z-value as follows:

                        Z = ( 250 - 230 ) / 27.129

                        Z = 0.7372

- Then use the Z-Tables and determine the probability:

                        P ( T < 250 mins ) = P ( Z < 0.7372 )

                        P ( T < 250 mins ) = 0.7695

Find:

-  If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

- For the teacher to miss the sports report he must take more time than 6:50 PM to 11:10 P.M.

- The total time till 6:50 PM to 11:10 PM is ( 4 hr and 20 mins ) = 260 mins.

- We will compute the Z-value as follows:

                        Z = ( 260 - 230 ) / 27.129

                        Z = 1.10582

- Then use the Z-Tables and determine the probability:

                        P ( T > 260 mins ) = P ( Z > 1.10582 )

                        P ( T > 260 mins ) = 0.1344