PHYSICS HIGH SCHOOL

In a machine shop, a hydraulic lift is used to raise heavy equipment for repairs. The system has a small piston with a cross-sectional area of 0.075 m2 and a large piston with a cross-sectional area of 0.237 m2 . An engine weighing 3400 N rests on the large piston. What force must be applied to the small piston in order to lift the engine? Answer in units of N.

Answers

Answer 1

Answer:

Answer:

$F_s=1075.9493\ N$

Explanation:

Given:

area of piston on the smaller side of hydraulic lift, $a_s=0.075\ m^2$

area of piston on the larger side of hydraulic lift, $a_l=0.237\ m^2$

Weight of the engine on the larger side, $W_l=3400\ N$

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.

$P_s=P_l$

$(F_s)/(a_s)=(W_l)/(a_l)$

$(F_s)/(0.075) =(3400)/(0.237)$

$F_s=1075.9493\ N$ is the required effort force.

Answer 2

Answer:

Answer:

F = 1076 N

Explanation:

given,

small piston area, a = 0.075 m²

large piston area, A = 0.237 m²

weight on the large piston, W = 3400 N

force applied on the second piston, F = ?

using pascal law for the force calculation

$(F)/(W)=(a)/(A)$

$(F)/(3400)=(0.075)/(0.237)$

F = 0.3165 x 3400

F = 1076 N

The force applied to the small piston in order to lift the engine is equal to 1076 N.

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B. 0°C
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Answers

That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)

What type of force pulls in two opposite directions?a. tension (associated with normal faults)
b. normal (associated with longitudinal faults)
c. transform (associated with transform faults)
d. compression (associated with reverse faults)
Which is not a type of fault?
a. normal
b. reverse
c. diagonal
d. transform

Answers

Answer

a. tension (associated with normal faults)

c. diagonal

Explanation

A pull of spring or of string on both ends of an object is called tension. So for the question one, the answer is tension (associated with normal faults)

There are three types of faults. Faults are produced by stress or strain by moving plates. These faults are: normal faults, reverse faults and transcurrent or Strike-slip. Strike-slip faults can also be called transform fault. The answer to the second question is c. diagonal.

Answer:

Tension Force (associated with normal faults)

Explanation:

As we know that tension force is an internal force between the molecules which opposes the tendency of molecules to separate out.

The tension force of string is always in opposite directions at two ends of string and it is always along the length

Answer:

Diagonal

Explanation:

As we know that there are four types of vaults

1) Normal vaults

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3) Reverse vaults

4) Transform vaults

Read the following dream interpretation and answer the question that follows."I suspect that the patient's dream of being chased originates from his unresolved feelings of guilt during childhood."
What perspective of dream interpretation is being offered?
A. Freudian
B. activation-synthesis
C. Jungian
D. motivation

Answers

Answer:

Freudian

Explanation:

Answer:

Freudian

Explanation:

What is the new weight of a 10kg object on a planet that has twice the earths mass. (assume that the radius of the planet is the same as earths)

Answers

Weight = (mass) x (acceleration of gravity) .

Acceleration of gravity on a planet's surface is proportional to

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On Earth's surface, acceleration of gravity is 9.8 m/s² .

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Answers

Answer:

$a_c=246.5 (m)/(s^2)$

Explanation:

The formula for centripetal acceleration is:

$a_c=rw^2$

Where,

$r:$ radius.

$w:$ Angular speed.

Angular speed is defined by:

$w=(\Delta\theta)/(\Delta t)$

Where,

$\theta:$ position angle.

$t:$ time.

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You have to know that 1 revolution = $2\pi rad$ , then

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$\Delta\theta=20\pi rad\n\Delta t=4.0s$

in the formula of Angular speed:

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$a_c=1.0m(15.7(rad)/(s))^2\n\na_c=1.0(246.5)(m)/(s^2) \n\na_c=246.5(m)/(s^2)$

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$a_c=246.5 (m)/(s^2)$

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d. self-fulfilling prophecy

Answers

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Answer:

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Explanation:

Odyssey ware

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