A jet travels 590 miles in 5 hours. At this rate, how far could the jet fly in 10 hours? What is the rate of speed of the jet?

Answers

Answer 1
Answer:

Answer:

The jet would fly 1180 miles in 10 hours, and it is going 118 mph

Step-by-step explanation:

590 x 5= 1180

590 ÷ 5= 118


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Say two and count on by tens to 92

Answers

Hey There!

To answer this question, you have to add ten each time.

Solution-
2,12,22,32,42,52,62,72,82,92

Have A Brainly Day :)

2, 12, 22, 32, 42, 52, 62, 72, 82, 92,

Can I please get some help on these

Answers

Answer:

11.   10/9 = 80/72

12.  8/12 = 72/108

13.  22/99 = 2/9

14  4  41/123 = 4 1/3

15.  84/840 = 1/10

16. 6/14  vs 3/7    (cross multiply numerators and denominators)

      42   vs  42

    Therefore 6/14 = 3/7

17.  2/3 vs 5/7  (cross multiply numerators and denominators)

       14  vs  15

    Therefore 2/3 < 5/7

18.  1/5, 1/2, 1/4   (Change to decimals then compare)

      .20   .50   .25

Therefore increasing order is1/5, 1/4, 1/2

19.  5/7, 5/6, 7/9  (Change to decimals then compare)

     .71     .83    .77

Therefore increasing order is 5/7, 7/9, 5/6

Step-by-step explanation:

Evaluate 3x - 2y, if x = 5 and y = 3

Answers

3 time 5 equals 15
2 times 3 equals 6 
the equation is 15-6

don't forget to make my answer the brainliest also rate it 5 stars also thank me please- Justin
first you put the numbers in place of the letter so it looks like 3(5)-2(3)
now you do 3x times 5 which =15x and do -2y times 3 and you get -6y now it should be this 15-6=9

Jack crawled 4 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what is the total distance the two children crawled. (Write the answer in inches.)

Answers

Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
                                                                = (4 * 12) inches
                                                                = 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
                                                         = (3/4) * 48 inches
                                                         = 3 * 12 inches
                                                         = 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
                                                                             = 84 inches
So Jack and Christine together crawled a distance of 84 inches.

Christine crawled:
4 ft* (3/4)= 3 ft.

4 ft+ 3ft= 7ft.

The total distance the two children crawled is 7ft~

Pls HELPPPP!!!!!!!!!!

Answers

Hey!!!

here'syouranswer

Areaofrectangularfield=L*B

=9/10*1/2

=9/20squaremile

SotherightanswerisofoptionA

Hopeithelps...

Goodluckonyourassignment

I say the answer is a

What is the equal to 3^3.3^5 A. 3−2 B. 32 C. 38 D. 315

Answers

3^3 \cdot 3^5 = 3^(3+5) = 3^8\n\n\boxed{\bf{C)~3^8}}\n\n\na^b \cdot a^c = a^(b+c)