Which of the following integrals cannot be evaluated using a simple substitution? (4 points) Select one: a. the integral of the square root of the quantity x minus 1, dx
b. the integral of the quotient of 1 and the square root of the quantity 1 minus x squared, dx
c. the integral of the quotient of 1 and the square root of the quantity 1 minus x squared, dx
d. the integral of x times the square root of the quantity x squared minus 1, dx

Answers

Answer 1
Answer:

Answer:

B. and C.

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Integration

  • Integrals
  • Indefinite Integrals
  • Integration Constant C

U-Substitution

Step-by-step explanation:

*Note:

It seems like B and C are both the same answer.

Let's define our answer choices:

a.  \displaystyle \int {√(x - 1)} \, dx

b.  \displaystyle \int {(1)/(√(1 - x^2))} \, dx

c.  \displaystyle \int {(1)/(√(1 - x^2))} \, dx

d.  \displaystyle \int {x√(x^2 - 1)} \, dx

Let's run u-substitution through each of the answer choices:

a.  \displaystyle u = x - 1 \rightarrow du = dx \ \checkmark

∴ answer choice A can be evaluated with a simple substitution.

b.  \displaystyle u = 1 - x^2 \rightarrow du = -2x \ dx

We can see that this integral cannot be evaluated with a simple substitution. In fact, this is a setup for an arctrig integral.

∴ answer choice B cannot be evaluated using a simple substitution.

C.  \displaystyle u = 1 - x^2 \rightarrow du = -2x \ dx

We can see that this integral cannot be evaluated with a simple substitution. In fact, this is a setup for an arctrig integral.

∴ answer choice C cannot be evaluated using a simple substitution.

D.  \displaystyle u = x^2 - 1 \rightarrow du = 2x \ dx \ \checkmark

Using a little rewriting and integration properties, this integral can be evaluated using a simple substitution.

∴ answer choice D can be evaluated using a simple substitution.

Out of all the choices, we see that B and C cannot be evaluated using a simple substitution.

∴ our answer choices should be B and C.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e


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Answers

Answer:

The distance between the points (4, 3) and (0, 6) is 5 units

Step-by-step explanation:

Use the distance formula to plug in the coordinates of each point and solve

D = 5

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1/2
1/3
1/6

Answers

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Which polynomial can be simplified to a difference of squares? 10a2 + 3a – 3a – 16 16a2 – 4a + 4a – 1 25a2 + 6a – 6a + 36 24a2 – 9a + 9a + 4

Answers

16a² - 4a + 4a - 1 can be simplified to a difference of squares:

16a² - 4a + 4a - 1 =
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² - 1 =
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Answer:

2.16a^2-4a+4a-1

Step-by-step explanation:

We have to find the polynomial can be simplified to a difference of squares.

1.10a^2+3a-3a-16

Combine like terms

10a^2-16

10 in 10a^2 is not a perfect square number  because when a number end with one zero then the number is not perfect square number.

Therefore, it can not be simplified to a difference of squares.

2.16a^2-4a+4a-1

16a^2-1

Combine like terms

(4a)^2-(1)^2

Hence, the polynomial can be simplified as difference of squares.

3.25a^2+6a-6a+36

Combine like terms

25a^2+36

(5a)^2+(6)^2

Hence, the polynomial can not be simplified as  difference of squares because the polynomial can be  simplified as sum of squares.

4.24a^2-9a+9a+4

Combine like terms

24a^2+4

24a^2+(2)^2

24=2* 2* 3* 2

24 is not  a perfect square number because  when factorize 24 then 2 and 3 are not paired.

Hence, the polynomial can not be simplified as difference of squares.

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Answers

5 x 3  = 15 = 3 3/4 or 3.75 
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Answer:

3 3/4 or 3.75

Step-by-step explanation: I did it

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Answers

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Answers

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