What type of energy is formed when an object encounters friction?

Answers

Answer 1

Answer:

Answer:

thermal energy

Friction does negative work and removes some of the energy the person expends and converts it to thermal energy. The net work equals the sum of the work done by each individual force. The forces acting on the package are gravity, the normal force, the force of friction, and the applied force.

Explanation:

Answer 2

Answer:

Explanation:

Thermal energy due to heat coming in from rubbing like rubbing your hand and it feel warm

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1. If an object that stands 3 centimeters high is placed 12 centimeters in front of a planemirror, how far from the mirror is the image located? Explain your reasoning.

2. An object with a height of 0.3 meter is placed at a distance of 0.4 meter from a concave
spherical mirror. An image with a height of 0.1 meter is formed in front of the mirror.
How far from the mirror is the image located?

3. When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a
convex spherical mirror, the image will appear to be 0.06 meter behind the mirror.
What's the height of the image?

4. Compare and contrast the properties of the images formed by each mirror type in the
table.

Answers

Answer:

1. 12 cm

2. 0.133 m

3. 0.03 m

4. Plane mirror

Virtual image

Upright

Behind the mirror

The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Real image

Inverted image

In front of the the mirror

Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Virtual image

Upright image

Behind the the mirror

Enlarged

Convex mirror

Type = Virtual image

Appearance = Upright image

Placement = Behind the mirror

Size = Smaller than the object

Explanation:

1. For plane mirror, since there is no magnification, the virtual image distance from the mirror = object distance from the mirror = 12 cm behind the mirror

2. The height of the object = 0.3 m

The distance of the object from the mirror = 0.4 meters

Height of image formed = 0.1 meter

We have;

$Magnification, \ m = (Image \ height )/(Object \ height ) = (Image \ distance \ from \ mirror )/(Object\ distance \ from \ mirror )$

$m = (0.1)/(0.3 ) = (Image \ distance \ from \ mirror )/(0.4 )$

Image distance from the mirror = 0.1/0.3×0.4 = 2/15 = 0.133 m

Image distance from the mirror = 0.133 m

3. $m = (Image \ height)/(0.10 ) = (0.06 )/(0.20 )$

The image height = 0.06/0.2×0.1 = 3/100 = 0.03 meter

The image height = 0.03 meter

4. Plane mirror

Type = Virtual image

Appearance = Upright image with the left transformed to right

Placement = Behind the mirror

Size = The same size as the object

Concave mirror when the object is located a distance greater than the focal length from the mirror's surface

Type = Real image

Appearance = Inverted image

Placement = In front of the the mirror

Size = Diminished when the object is beyond the center of curvature

Same size as object when the object is placed at the center of curvature

Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror

Concave mirror when the object is located a distance less than the focal length from the mirror's surface

Type = Virtual image

Appearance = Upright image

Placement = Behind the the mirror

Size = Enlarged

Convex mirror

Type = Virtual image

Appearance = Upright image

Placement = Behind the mirror

Size = Smaller than the object.

Answer:

1. The mirror is 12 centimeters away from the image. This is a plane mirror with a flat reflecting surface. The distance between the object and the mirror surface is equal to the distance between the mirror surface and the image.

2. hiho=siso

0.1 m0.3 m=si0.4 m

Multiply each side of this equation by 0.4.

0.4×(0.10.3=si0.4)×0.4

si=0.40.3

si = 0.133 m

3. hiho=siso

hi0.10 m=0.06 m0.02 m

Multiply each side of this equation by 0.10.

0.10×(hi0.10=0.060.20)×0.10

hi=0.0060.20

hi = 0.03 m

Image Formation

Mirror Type Appearance Placement Size

Plane Virtual Erect (Upright); Appears to have left and right reversed Behind the mirror; the distance between the mirror and the image is equal to the distance between the mirror and the object Depends on the size of the mirror and placement of the object

Concave (when the object is located a distance greater than a focal length from mirror's surface) Real Inverted In front of the mirror Smaller than the object

Concave (when object is located a distance less than the focal length of the mirror) Virtual Erect (Upright) Behind the mirror Enlarged

Convex Virtual Erect (Upright) Behind the mirror Smaller than the object

Explanation:

PENN

Which of the following is not a way that oil production could potentially affect aquatic viability?

Answers

Since you have not presented any choices that would tell us which is NOT a way that oil production could potentially affect aquatic viability, I'll just go ahead and answer what are ways that oil could affect aquatic viability.

-Offshore drilling contaminates and disturbs habitats of aquatic creatures
-Transport of oil across seas or oceans might lead to oil spill
-Waste products from energy factories using oil still would disturb habitat

answer: c- interruption of water flow

arrange the stars based on their temperature. begin with the coolest star, and end with the hottest star

Answers

Answer:

Temperature – cooler stars are red, warmer ones are orange through yellow and white. The hottest stars shine with blue light. Age – As a star ages it produces different chemicals which burn at different temperatures.

Why is a car rounding a curve accelerating, even if it is moving at a constant speed?

Answers

Because "acceleration" does NOT mean "speeding up". It means ANY change in the speed OR direction of motion. Speeding up, slowing down, and changing direction are all 'accelerations'. If a car is not moving in a straight line, then its direction is changing and it is accelerating, even if its speed is constant.

Automobile speedometers give an instantaneous velocity. It is important to remember that because the velocity has a direction, a change in either the speed or the direction results in a change in velocity. This leads to an interesting fact, a car going around a curve can have a constant speed and yet still have a changing velocity. The car in the following diagram is traveling around a curve. Suppose the driver looks at his speedometer when the car is at points "A", "B", and "C". At each of these points he notices that the speedometer reads 30km/h. His speed is a constant 30km/h as he rounds the curve. Now look at what is happening to his direction of motion. As he goes around the curve, his direction changes from East to South. Because of this change in direction, we have to conclude that his velocity is changing even though his speed is constant.

Changes in the way atoms are ? together occur when compounds form

Answers

Atoms are basically tiny structures that make up everything. And a compound is something used in a scientific expirement. I don't get the question. You used improper grammar

A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?

Answers

Final answer:

If the force remains unchanged, pushing a box three times farther requires three times more work because work is directly proportional to distance in the work formula W = F × d.

Explanation:

The student is asking about the work required to push a box across a room. In Physics, work is defined as the product of the force applied to an object and the distance over which it is applied, assuming force and distance are in the same direction. The formula for work is W = F × d, where W is work, F is the constant force applied, and d is the distance the object moves.

Assuming the same constant force is applied to the box if a student needs to push the box three times farther, they would do three times more work. This is because work is linearly proportional to the distance if the force remains unchanged. To illustrate, if pushing the box over a certain distance requires W joules, then pushing it three times that distance requires 3W joules of work.