Electronegativity is :_______________a) electronegativity is the negative charge surrounding the nucleus of an atom.
b) the number of electrons in the outermost electron shell.
c) the attraction of an atom for the electrons in a covalent bond.
d) the repulsion of electrons in one atom for electrons in another atom.

Answers

Answer 1

Answer:

c) the attraction of an atom for the electrons in a covalent bond.

Explanation:

Electronegativity, symbol χ, is a chemical property describing an atom's ability of to attract a shared pair of electrons to itself. It is influenced by the atomic number of the atom and the distance between the valence electrons and the charged nucleus. As the electronegativity number of atoms increases, the more the atom attracts electrons towards itself.

Answer 2

Answer:

Final answer:

Electronegativity is the attraction of an atom for electrons in a covalent bond. It determines how strongly an atom pulls shared electrons towards itself in a molecule.

option c is correct

Explanation:

Electronegativity is the attraction of an atom for the electrons in a covalent bond. It is a measure of how strongly an atom pulls shared electrons towards itself when it forms a covalent bond with another atom.

For example, in a molecule of HCl, chlorine is more electronegative than hydrogen, so the chlorine atom pulls the shared electron pair towards itself, resulting in a partial negative charge on the chlorine atom and a partial positive charge on the hydrogen atom.

Electronegativity increases as you move across a row or period in the periodic table from left to right and decreases as you move down a column or group.

Learn more about Electronegativity here:

brainly.com/question/35593282

#SPJ11

Related Questions

Why did Rutherford conclude that the atom was mostly empty space?
Which provides evidence to support the big bang theory? A. the change in carbon dioxide levels in the atmosphere B. the composition of the sun C. the red-shift of distant galaxies D. the magnetization of rocks on the ocean floor
Which 5.0-milliliter sample of NH3 will take the shape of and completely fill a closed 100.0-milliliter container?(1) NH3(s) (3) NH3(g)(2) NH3(ℓ) (4)NH3(aq)
Which of the following has a positive enthalpy without a temperature change? condensing gas evaporating a liquid cooling a solid cooling a liquid
Which of the following best describes a mixture in which ionic compounds are dissociated in solution? a. ion solution b. aqueous solution c. hydraulic solution d. hydrochloric solution

When 70.4 g of benzamide (C,H,NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2.7 C lower than the freezing point of pure X. On the other hand, when 70.4 g of ammonium chloride (NH CI) are dissolved in the same mass of X, the freezing point of the solution is 9.9 °C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.

Answers

Answer:

1.60 is the van't Hoff factor for ammonium chloride in X.

Explanation:

$\Delta T_f=iK_f* m$

$Delta T_f=K_f* \frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{Mass of solvent in Kg}}$ ...(1)

where,

$\Delta T_f$ =Elevation in boiling point =

i = van't Hoff factor

$K_f$ = Freezing point constant

m = molality

1) When 70.4 g of benzamide are dissolved in 850. g of a certain mystery liquid X.

Mass of benzamide = 70.4 g

Molar mass of benzamide = 121 g/mol

i = 1 (organic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f$ = Freezing point constant of liquid X= ?

$\Delta T_f=2.7^oC$

Putting all value in a (1):

$2.7^oC=K_f* (70.4 g)/(121 g/mol* 0.850 kg)$

$K_f=3.944 ^oC kg/mol$

2) When 70.4 g of ammonium chloride are dissolved in 850. g of a certain mystery liquid X.

Mass of ammonium chloride= 70.4 g

Molar mass of ammonium chloride = 53.5 g/mol

i = ? (ionic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f=3.944 ^oC kg/mol$

$\Delta T_f=9.9^oC$

Putting all value in a (1):

$9.9^oC=i* 3.944^oC kg/mol* (70.4 g)/(53.5 g/mol* 0.850 kg)$

i = 1.6011 ≈ 1.60

1.60 is the van't Hoff factor for ammonium chloride in X.