The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line?y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)

Answers

Answer 1

Answer: The point-slope form in general is $y-y_1=m(x-x_1)$

With the coordinate (-2,-13) being $(x_1,y_1)$ , and the slope m, is 5, from y = 5x – 3,

$y-y_1=m(x-x_1)$
$y-(-13)=5(x-(-2))$
$y+13=5(x+2)$

Answer 2

Answer:

Answer:

its b :)

Step-by-step explanation:

i aint ever seen two pretty best friends

Greetings!

Answer:

Horseback riding costs $30 and parasailing costs $51, so B.

Step-by-step explanation:

This is answered by using simultaneous equations, let x be parasailing and y be horseback riding.

3y + 2x = 192

2y + 3x = 213

Multiply each equation by the number in front of the y of the other equation:

2 x (3y + 2x = 192)

3 x (2y + 3x = 213)

Which results in:

6y + 4x = 384

6y + 9x = 639

Simply minus the two equations to get rid of the y:

6y - 6y = 0

4x - 9x = -5x

384 - 639 = -255

The negatives cancel out which give a result:

5x = 255

x = $(255)/(5)$

x = 51

So parasailing costs $51

Now you can simply plug this value into one of the equations:

3y + (2 x 51) = 192

192 - 102 = 3y

90 = 3y

y = $(90)/(3)$

y = 30

So horseback riding costs $30!

Hope this helps.

Simplifying rational expressions1. (c+8)(c-8)/(c-8)(c+3)
2. n^2+4n-12/n^2+2n-8
3. 42x^2y^3/28x^3y
4. m^2-3m-10/m-5

Answers

1. $((c + 8)(c - 8))/((c - 8)(c + 3)),$
   $(c + 8)/(c + 3)$

2. $(n^(2) + 4n - 12)/(n^(2) + 2n - 8),$
   $(n^(2) + 6n - 2n - 12)/(n^(2) + 4n - 2n - 8),$
   $(n(n) + n(6) - 2(n) - 2(6))/(n(n) + n(4) - 2(n) - 2(4)),$
   $(n(n + 6) - 2(n + 6))/(n(n + 4) - 2(n + 4)),$
   $((n - 2)(n + 6))/((n - 2)(n + 4)),$
   $(n + 6)/(n + 4)$

3. $(42x^(2)y^(3))/(28x^(3)y),$
   $(3y^(2))/(2x)$

4. $(m^(2) - 3m - 10)/(m - 5),$
   $(m^(2) - 5m + 2m - 10)/(m - 5),$
   $(m(m) - m(5) + 2(m) - 2(5))/(m - 5),$
   $(m(m - 5) + 2(m - 5))/(m - 5),$
   $((m + 2)(m - 5))/(m - 5),$
   $m + 2$

Mrs. Eaton's class is participating in the "Box Tops for Education" campaign. On the first day, herclass collected 2 tops. On the third day, her class collected 8 tops. Let D represent each collection
day and N represent the number of tops collected on that day.
Based on the situation, John claims the number of tops collected can be modeled by an exponential
function. Riley disagrees and claims the number of tops can be modeled with a linear function. What
is the number of tops collected on the sixth day based on the exponential model? What is the
number of tops collected on the sixth day based on the linear model?

Answers

The exponential model would take the form:
$y=Ae^(kt)$
A, the initial value is 2, we will use 3 days and 8 tops to find k, or the rate.
$8 = 2e^(k*3)$
$k = (ln(4))/(3)$

Now, plugging in 6 days:
$y = 2e^{ (ln(4))/(3)*6}$
$y = 32$

The linear would take the form:
y = mx+b
First the slope would be: (8-2)/(3-1) = 3
And to find b we could plug in the point (8,3):
8 = 3(3)+b
b = 8-9
b = -1
y = 3x-1
At x=6
y = 3(6)-1
y = 17

Thus, the exponential is almost double the result of the linear! Hope that helps.

Answer:

Step-by-step explanation:

for the exponential it is actually 64

Which equation represents a nonlinear function?