During a nine-hour snowstorm, it snows at a rate of 2 inches per hour for the first 3 hours, at a rate of 3 inches per hour for the next 5 hours, and at a rate of 0.75 inch per hour for the final hour.How many inches of snow accumulated from the storm?

Answers

Answer 1
Answer:

Answer:

use f(x)=y=mx+b

let snow = S, time = t instead of y and x

S(t)=mt+b

The rate of inches per hour represents the slope of the graph, m.

The y-variable would be the amount of snow, S.

The x-variable would be the time, t, in hours.

The function has three pieces:

i) S(t)= 2t (slope = 2)

ii) S(t) = 3t (slope = 3)

iii) S(t) = 0.75t (slope = 0.75)

For the first piece, i), t=3, so the amount of snow is 6 inches.

For the second piece, ii) t=5, so the amount of snow is 15 inches.

For the third piece, iii) t=1, so the amount of snow is 0.75 inch.

In total, it snowed 21.75 inches.

total snow

Answer 2
Answer:

Final answer:

To find the total accumulation of snow during the nine-hour snowstorm, we calculate the snow accumulation for each hour and then sum them up. The total accumulation of snow from the storm is 21.75 inches.

Explanation:

To find the total accumulation of snow during the nine-hour snowstorm, we need to calculate the amount of snow that fell during each hour and then sum them up. First, we calculate the snow accumulation for each hour:

  1. For the first 3 hours, it snowed at a rate of 2 inches per hour, so the accumulation is 3 * 2 = 6 inches.
  2. For the next 5 hours, it snowed at a rate of 3 inches per hour, so the accumulation is 5 * 3 = 15 inches.
  3. For the final hour, it snowed at a rate of 0.75 inch per hour, so the accumulation is 1 * 0.75 = 0.75 inches.

Finally, we sum up the accumulations for each hour: 6 + 15 + 0.75 = 21.75 inches. Therefore, the total accumulation of snow from the storm is 21.75 inches.

Learn more about Snow accumulation here:

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Help with this problem (20 points)

Answers

Answer:

what problem? i dont see it

No problem here! Are you sure?

A person invests 4000 dollars in a bank. The bank pays 6.25% interest compoundedannually. To the nearest tenth of a year, how long must the person leave the money
in the bank until it reaches 9600 dollars?

Answers

Answer:

14.4

Step-by-step explanation:

Given that :

Principal = 4000

Interest (r) = 6.25% compounded annually

Calculate time, t, if final amount A = 9600

Using the compound interest formula :

A = P(1 + r/n)^n*t

A = final amount

n = number of times interest is applied per period

9600 = 4000(1 + 0.0625)^t

9600 = 4000(1.0625)^t

9600/4000 = 1.0625^t

2.4 = 1.0625^t

Take the log of both sides

0.3802112 = 0.0263289t

t = 0.3802112/0.0263289

t = 14.440811

t = 14.4 ( nearest tenth)

A large tank is filled to capacity with 600 gallons of pure water. Brine containing 5 pounds of salt per gallon is pumped into the tank at a rate of 6 gal/min. The well-mixed solution is pumped out at a rate of 12 gallons/min. Find the number A(t) of pounds of salt in the tank at time t. A(t)

Answers

Salt flows into the tank at a rate of

(5 lb/gal) * (6 gal/min) = 30 lb/min

The volume of solution in the tank after t min is

600 gal + (6 gal/min - 12 gal/min)*(t min) = 600 - 6t gal

which means salt flows out at a rate of

(A(t)/(600 - 6t) lb/gal) * (12 gal/min) = 2 A(t)/(100 - t) lb/min

Then the net rate of change of the salt content is modeled by the linear differential equation,

A'(t)=30-(2A(t))/(100-t)

Solve for A:

A'+(2A)/(100-t)=30

Multiply both sides by the integrating factor, \frac1{(100-t)^2}:

(A')/((100-t)^2)+(2A)/((100-t)^3)=(30)/((100-t)^2)

\left(\frac A{(100-t)^2}\right)'=(30)/((100-t)^2)

Integrate both sides:

\frac A{(100-t)^2}=(30)/(100-t)+C

\implies A(t)=30(100-t)+C(100-t)^2

The tank starts with no salt, so A(0) = 0 lb. This means

0=30(100)+C(100)^2\implies C=-\frac3{10}

and the particular solution to the ODE is

A(t)=30(100-t)-\frac3{10}(100-t)^2=\frac3{10}t(100-t)

What is (1/3) x (-2/3 )?

Answers

Answer:

-0.2222

Step-by-step explanation:

If its multiple choice choose an answer close to this. Or don't I can't tell what to do.

Answer: -2/9

Decimal form: -0.2

Step-by-step explanation:

I BET YOU CANT SOLVE THIS...

Answers

The answer is 61 7/20

QuestionGiven that tan(0) =5/12
and 0 is in Quadrant III. what is cos(0)? Write your answer in exact form. Do not round.
Provide your answer below:

Answers

Answer:

cosΘ = - (12)/(13)

Step-by-step explanation:

Given that Θ is in the third quadrant then cosΘ < 0

Given

tanΘ = (5)/(12) = (opposite)/(adjacent)

Then 5 and 12 are the legs of a right triangle (5- 12- 13 ) with hypotenuse = 13

Thus

cosΘ = - (adjacent)/(hypotenuse) = - (12)/(13)