Find the product of the complex number and its conjugate. 3 + 3i
Answers
First, we are going to find the conjugate of our complex number. Remember that to find the conjugate of a complex number we just need to keep the real part and change the sing of the imaginary part.
We can infer from our problem that the real part of our complex number is 3 and its imaginary part is . We are going to keep the real part 3 and change the imaginary part from positive to negative, so our conjugate is
.
Next, we are gong to multiply both the complex number and its conjugate using the distributive property:
Remember that , so:
We can conclude that the product of the multiplication of the complex number 3+3i and its conjugate, 3-3i, is 18.
Product of complex number and its conjugate will be 18 .
Complex number : x ± iy
Given , 3 + 3i
Conjugate pair of complex number = x ± iy
So, the complex conjugate pair are :
3 + 3i and 3 - 3i
Product of complex conjugate pair,
(3 + 3i) (3 - 3i)
Open the brackets,
= 9 - 9i + 9i - 9i²
Here, i = √-1 ; i² = -1
Substitute the value of iota(i),
= 9 -9i + 9i +9
= 18
Thus the product value is 18.
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How to solve this The minimum value of f is f×3=-5 and f×1=2
Answers
Answer:
THere ya go
Step-by-step explanation:
c[p(g)] = 0.896g
g[c(p)] = 1.92p
c(p) ⋅ p(g) = 0.896pg
Answers
p(g) = 0.8 * g
c(p) = 1.12 * p
1.12 * p = 1.12 * 0.8 * g = 0.896 * g = c(p(g)) = c[p(g)]
The correct result would be c[p(g)] = 0.896g.
Answer:
B c[p(g)] = 0.896g
Step-by-step explanation:
Answers
Answer: 1/169
The calculation would be (4/52)*(4/52) which is the same as (1/13)^2
The 4/52 refers to the fact there are 4 kings out of 52 cards total.
The 1/13 is the idea where there's 1 king in any given suit of 13 cards.
Answers
Answer:
the answer will be...
4.8!!!
Step-by-step explanation:
1/5 x (6 x 4) =
1/5 x 24 = 4.8
or.....
0.2 x 24 =
4.8
Answers
Therefore a = 7.1 / 6.3 = 1.13 m/sec^2
Answers
A 8 can go into 66 eight times, with a remainder of 2.
To calculate how many times 8 can go into 66, we need to perform long division.
Step 1: Set up the long division:
8 | 66
Step 2: Determine how many times 8 can go into the first digit of 66 (which is 6). It goes 8 times (8 x 8 = 64). Write 8 above the division bar.
8 | 66
8
Step 3: Subtract 64 from 66 to get the remainder. Bring down the next digit (which is 6).
8 | 66
8
---
26
Step 4: Determine how many times 8 can go into 26. It goes 3 times (8 x 3 = 24). Write 3 above the division bar.
8 | 66
8
---
26
24
Step 5: Subtract 24 from 26 to get the remainder. There is no more digit to bring down, so the division is complete.
8 | 66
8
---
26
24
---
2
The final result is 8 times with a remainder of 2. Therefore, 8 can go into 66 eight times, with a remainder of 2.
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