A researcher is using a repeated-measures study to evaluate the difference between two treatments. If the difference between the treatments is consistent from one participant to another, then the data should produce ______. A. a small variance for the difference scores and a small standard error
B. a small variance for the difference scores and a large standard error
C. a large variance for the difference scores and a small standard error
D. a large variance for the difference scores and a large standard error

Answers

Answer 1

Answer:

Answer:

A) a small variance for the difference scores and a small standard error

Step-by-step explanation:

Since the difference scores are obtained by subtracting one variable form another, if the difference scores are consistent between treatments, then the variance will be small. The higher the variance, the higher the standard error. So if the variance is small, then the standard error will also be small.

Related Questions

Set up the following addition using a vertical format and find the sum of the given polynomials. a - b + c, b - c + d, and c - d + e A a + c + e B a + 2b + 3c + 2d + e C b + d + e D a - c - e
The gcf of 135 225 270
Which of the following is equivalent to 6x 2 + x - 12 ?A. (2x + 3)(3x - 4) B. (2x - 3)(3x - 4) C. (2x + 3)(3x + 4) D. (6x + 3)(x - 12) E. (x + 3)(2x - 12) Please show me step by step how to solve this problem Thanks
I dont understand how to do thisits factoring quadratics
Event B is dependent on event A, and event A occurs before event B. Which expression is equal to the probability of event A?

Ex 3.7
12. find the area between the curve y=x³-2 and the y-axis between y= -1 and y=25

Answers

$y=x^3-2\nx^3=y+2\nx=\sqrt[3]{y+2}\n\n\int \limits_(-1)^(25)\sqrt[3]{y+2}\, dy=\n\int \limits_(-1)^(25)(y+2)^{\tfrac{1}{3}}\, dy=\n\left[\frac{(y+2)^{\tfrac{4}{3}}}{(4)/(3)} \right]_(-1)^(25)=\n$
$\left[(3)/(4)(y+2)^{\tfrac{4}{3}} \right]_(-1)^(25)=\n\left[(3)/(4)(y+2)\sqrt[3]{y+2} \right]_(-1)^(25)=\n(3)/(4)(25+2)\sqrt[3]{25+2}-\left((3)/(4)(-1+2)\sqrt[3]{-1+2}\right)=\n(3)/(4)\cdot27\sqrt[3]{27}-\left((3)/(4)\sqrt[3]{1}\right)=\n(3)/(4)\cdot27\cdot3-(3)/(4)=\n(3)/(4)(81-1)=\n(3)/(4)\cdot 80=\n3\cdot20=\n60$

Yeah, you'd have to use the inverse function to produce this result.

Let's get the inverse function first:

$y={ x }^( 3 )-2\n \n { x }^( 3 )=y+2\n \n x=\sqrt [ 3 ]{ y+2 }$

$\n \n \therefore \quad { f }^( -1 )\left( x \right) =\sqrt [ 3 ]{ x+2 }$

Now, we can solve the problem using:

$\int _( -1 )^( 25 ){ \sqrt [ 3 ]{ x+2 } } dx$

But to solve the problem more easily we make u=x+2, therefore du/dx=1, therefore du=dx.

When x=25, u=27.

When x=-1, u=1.

Now:

$\int _( 1 )^( 27 ){ { u }^{ \frac { 1 }{ 3 } } } du\n \n ={ \left[ \frac { 3 }{ 4 } { u }^{ \frac { 4 }{ 3 } } \right] }_( 1 )^( 27 )$

$\n \n =\frac { 3 }{ 4 } \cdot { 27 }^{ \frac { 4 }{ 3 } }-\frac { 3 }{ 4 } \cdot { 1 }^{ \frac { 4 }{ 3 } }\n \n =\frac { 3 }{ 4 } { \left( { 3 }^( 3 ) \right) }^{ \frac { 4 }{ 3 } }-\frac { 3 }{ 4 }$

$\n \n =\frac { 3 }{ 4 } \cdot { 3 }^( 4 )-\frac { 3 }{ 4 } \n \n =\frac { 3 }{ 4 } \left( { 3 }^( 4 )-1 \right)$

$\n \n =\frac { 3 }{ 4 } \cdot 80\n \n =60$

Answer: 60 units squared.

Find the slope of the line between the points (-2, 7) and (10, 3)

Answers

Answer:

m = -1/3

Step-by-step explanation:

Translate the following and explain where these examples could be found in real world.
a) “6 less than a number”
b) “2 times the quotient of a number and two”
c) “4 times the difference of a number and 8”

Answers

a) x-6; you have x amount of money and pay 6 dollars for a hat.
b) 2(x2);

Physics students drop a ball from the top of a 100 foot high building and model its height as a function time with the equation h(t) = 100 - 16t^2. Determine, to the nearest tenth of a second, when the ball hits the ground.

Answers

When the ball hits the ground, the height is 0.

0 = 100 - 16t²

0 = (10 - 4t)(10 + 4t)

0 = 10 - 4t or 0 = 10 + 4t

4t = 10 or -4t = 10

t = $(10)/(4)$ or t = $-(10)/(4)$

Time cannot be negative (unless you have a time machine) so disregard $-(10)/(4)$

Answer: t = $(5)/(2)$ = 2.5 seconds

Darin wrote 1 1/3 as a sum of three fractions.None of the fractions had a denominator of 2.What fractions might Darin have used?

Answers

The fractions Darin might have used are 1/3, 2/3 and 1/3.

What are fractions?

A fraction is a quantity that is not a whole number. In maths, a fraction usually has a numerator and a denominator. The numerator is the number above. While the denominator is the number below.

What could the fractions be?

The sum of the three fractions has to be 1 1/3. The possible fractions are 1/3, 2/3 and 1/3.

To learn more about fractions, please check: brainly.com/question/915789

Unsaved Find the surface area of a conical grain storage tank that has a height of 46 meters and a diameter of 16 meters. Round the answer to the nearest square meter.

Answers

The formula for the surface area of a cone is $SA= \pi r(r+ √(h^2+r^2) )$ . Filling in accordingly, we have $SA= \pi (8)(8+ √(46^2+8^2) )$ and $SA=8 \pi (8+ √(2116+64))$ . That will simplify to $SA=8 \pi (8+ √(2180) )$ and $SA=8 \pi (8+46.69047)$ . If we LEAVE pi in the answer you would have $437.5 \pi$ which rounds to $438 \pi$ . If you multiply pi in, you would have 1375.5 or, rounded, 1376. Of course those labels are all meters squared.

Other Questions

-x+y=4 3x-2y=-7 substitution

Solve for x:- 11x + 32.5 < 82

HELP PLEASE: 40 POINTS Match the following items by evaluating the expression for x = -3.x^ -2 x ^-1 x^0 x^ 1 x^2 AND THE OPTIONS FOR EACH ONE IS -1/3, 1, 9,1/9,-3

Janelle learns 4 new appetizer recipes during each week of culinary school. After9 weeks of culinary school, how many total appetizer recipes will Janelle know