CHEMISTRY HIGH SCHOOL

At -18.6 °C, a common temperature for household freezers, what is the maximum mass of sucralose (C₁₂H₁₉Cl₃O₈) in grams you can add to 2.00 kg of pure water and still have the solution freeze? Assume that sucralose is a molecular solid and does not ionize when it dissolves in water.
$K_f$ = 1.86 °C/m.

Answers

Answer 1

Answer:

Answer : The maximum mass of sucralose is, 7952.8 grams.

Explanation : Given,

Molal-freezing-point-depression constant $(K_f)$ for water = $1.86^oC/m$

Mass of water (solvent) = 2.00 kg

Molar mass of sucralose = 397.64 g/mole

Formula used :

$\Delta T_f=i* K_f* m\n\nT^o-T_s=i* K_f*\frac{\text{Mass of sucralose}}{\text{Molar mass of sucralose}* \text{Mass of water in Kg}}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution = $-18.6^oC$

$\Delta T^o$ = freezing point of water = $0^oC$

i = Van't Hoff factor = 1 (for sucralose non-electrolyte)

$K_f$ = freezing point constant for water = $1.86^oC/m$

m = molality

Now put all the given values in this formula, we get

$(0-(-18.6)^oC)=1* (1.86^oC/m)* \frac{\text{Mass of sucralose}}{397.64g/mol* 2.00kg}$

$\text{Mass of sucralose}=7952.8g$

Therefore, the maximum mass of sucralose is, 7952.8 grams.

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Look up the density of n-butyl chloride (1-chlorobutane). Assume that this alkyl halide was prepared instead of the bromide. Decide whether the alkyl chloride would appear as the upper or the lower phase at each stage of the separation procedure: after the reflux, after the addition of water, and after the addition of sodium bicarbonate.

Answers

Answer:

See explanation below

Explanation:

First, you need to know the density of each compound in order to know this.

The density of 1-chlorobutane is 0.88 g/mL,

The density of water is 1 g/mL

The density of sodium bicarbonate is 2.2 g/cm3.

therefore, the one that has a greater density will always go at the lower phase.

In this case, after the reflux, it will stay in the lower phase, basically because you don't have another solvent with a greater density than the butane.

After adding water, it will be in the upper phase, water has a greater density.

After adding bicarbonate, it will be in the upper phase too.

calculate the volume of hydrogen produced at s.t.p when 25g and zinc are added to excess dilute hydrochloric acid at 31 degrees and 778 mm Hg pressure ( H= 1 , Zn = 65 , cl = 35.5 , volume of gas at stop = 22.4 dm cube

Answers

Answer:

The volume of hydrogen gas produced at s.t.p. is 9.419 dm³

Explanation:

The balanced chemical equation for the reaction is given as follows;

Zn + 2HCl → ZnCl₂ + H₂

Therefore, we have;

One mole of Zn reacts with 2 moles of HCl to produce one mole of ZnCl₂ and one mole of H₂

Number of moles of Zn present = 25/65 = 5/13 = 0.385 moles

Therefore, number of moles of H₂ produced = 0.385 moles

The volume of hydrogen gas produced is given by the relation

PV = nRT, we have;

R = 8.3145 J/(mol·K)

V = nRT/P = 0.385 ×8.3145 ×298.15/(101325)= 0.009419 m³ = 9.419 dm³

The volume of hydrogen gas produced at s.t.p. = 9.419 dm³.

Physical activity and exercise typically lead to __________.a. increased stress
b. depression
c. higher energy levels
d. reduced quality of life

Answers

The answer is c - physical activity and exercise typically lead to higher energy levels. The endorphins and hormones released during periods of high activity actually help to combat stress and depression linked to a depletion in serotonin, and therefore can only increase the quality of life. The other possible answers to this question are therefore all incorrect.

the answer is c i just took the test

A 3.0 M HCl(aq) solution contains a total of(1) 3.0 grams of HCl per liter of water
(2) 3.0 grams of HCl per mole of solution
(3) 3.0 moles of HCl per liter of solution
(4) 3.0 moles of HCl per mole of water

Answers

Answer : The correct option is, (3) 3.0 moles of HCl per liter of solution

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of the solution. The S.I unit of molarity is mole per liter.

It is represented as,

$Molarity=\frac{\text{Moles of solute}}{V_(solution)(L)}$

where,

V = volume of solution in liter

As we are given 3.0 M HCl(aq) solution this means that 3.0 moles of HCl present in one liter of solution.

Hence, a 3.0 M HCl(aq) solution contains a total of 3.0 moles of HCl per liter of solution.

Molarity = number of moles / volume in liters solution

Answer (3)

hope this helps!

How many moles are in 30 grams of H3PO4?

Answers

Mass = Moles x GFM

mass = 30g so;

30 = mol x GFM

To calculate the GFM, you require a data booklet or similar.
Mine tells me that the GFMs are:

H: 1 H₃ so 3 x 1 = 3
P: 31 P so 1 x 31= 31
O:16 O₄ so 4 x 16 = 64
GFM = 64 + 31 + 3 = 98

30 = 98 x mol

mol = 30 / 98

mol = 0.31 mol

Final answer:

To find the number of moles in 30 grams of H3PO4, divide the mass by the molar mass. In this case, there are 0.306 moles of H3PO4.

Explanation:

To determine the number of moles in 30 grams of H3PO4, we need to use the molar mass of H3PO4. The molar mass of H3PO4 is 98.0 g/mol.

We can use the following conversion factor to convert grams to moles: 1 mole = molar mass (in grams).

Therefore, the number of moles in 30 grams of H3PO4 is calculated as:

30 grams x (1 mole / 98.0 grams) = 0.306 moles of H3PO4.

Learn more about moles here:

brainly.com/question/26416088

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Dermatological bases are classified according to?

Answers

Dermatological bases are classified according to structure and size. Dermatological bases are also classified based on the amount of water they can contain, whether they are water-washable and their method of preparation. I hope this helps you.

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