MATHEMATICS MIDDLE SCHOOL

PLEASE HELP!First determine the degree of each polynomial expression below. Explain how you determined this on each expression.Then organize the expressions from least to greatest based on their degree
I. 6x^2
II. 18x^3+5ab-6y
III.8a-5
IV. 4x^3y+3x^2-xy-4​

Answers

Answer 1
Answer:

Degree of polynomials:

6x^2 = 2\n\n18x^3+5ab-6y = 3\n\n4x^3y +3x^2-xy-4 = 4\n

Least to greatest based on degree:

6x^2

18x^3+5ab-6y

4x^3y +3x^2-xy-4

Solution:

The degree of the polynomial is the highest degree of any of the terms

Know that the degree of a constant is zero

Option I

6x^2

Here the highest degree is 2 ( x power 2)

In this case, degree of polynomial is 2

Option II

18x^3+5ab-6y

To find the degree of the polynomial, add up the exponents of each term and select the highest sum.

Degree\ of\ 18x^3 = 3

Degree\ of\ 5ab = 5a^1b^1 = 1+1 = 2

Degree\ of\ 6y = 6y^1 = 1

Thus the highest degree is 3

Option III

8a^(-5)

This is not a polynomial

A polynomial does not contain variables raised to negative

Option IV

4x^3y +3x^2-xy-4

To find the degree of the polynomial, add up the exponents of each term and select the highest sum.

Degree\ of\ 4x^3y = 4x^3y^1=3+1 = 4\n\nDegree\ of\ 3x^2 = 2\n\nDegree\ of\ xy = x^1y^1 = 1+1 = 2\n\nDegree\ of\ 4 = 0

Thus highest degree is 4

Then organize the expressions from least to greatest based on their degree

Least to greatest based on degree:

6x^2

18x^3+5ab-6y

4x^3y +3x^2-xy-4

Related Questions

Explain how to add decimals to the thousandths?
A Sports arena covers 710,430 square feet of ground. A newspaper reported that the arena covers about 700,000 square feet of ground. To what place value was the number rounded?
3. Which one doesn't belong? Give a reason why each square does not belong.B. 20%A. 15%D. 110%C. 8%
Raj bought a pair of basketball shoes for $70. The sales tax on the shoes was $5.60. Which represents the sales tax rate?
Which ordered pairs in the form (x, y) are solutions to the equation?Select each correct answer. (More than one c:) [A] (4, 10) [B] (7, 9) [C] (−6, −14) [D] (−1, −7)

Whats the answer to the problem ?

Answers

Answer:

could you give what the problem is



Step-by-step explanation:

16x²-81=0 solve the following quadratic equation

Answers

16x^2-81=0\n\n(4x)^2-9^2=0\n\n(4x-9)(4x+9)=0\iff4x-9=0\ \vee\ 4x+9=0\n\n4x=9\ \vee\ 4x=-9\n\nx=(9)/(4)\ \vee\ x=-(9)/(4)


or\n\n16x^2-81=0\n\n16x^2=81\ \ \ \ /:16\n\nx^2=(81)/(16)\n\nx=\pm\sqrt(81)/(16)\n\nx=-(√(81))/(√(16))\ \vee\ x=(√(81))/(√(16))\n\nx=-(9)/(4)\ \vee\ x=(9)/(4)
16x^2-81=0
(4x-9)(4x+9)
x=9/4 or x=-9/4

55% as a fraction or mixed number in simplest form

Answers

55/100 would be the easiest way to express 55% as a fraction.
55/100 would be as a fraction then you would simpilfy it to 11/20.

the earth rotates about its axis once every 23 h 56 min 4 s, and the radius of the earth is 3960 mile. find the linear speed of a point on the equator in mi/h

Answers

23h\ 56min\ 4s=\left(23+(56)/(60)+(4)/(3600)\right)h=\left((82800)/(3600)+(3360)/(3600)+(4)/(3600)\right)h\n\n=(86164)/(3600)h\approx23.93h\n\nL=2\pi R;\ R=3960mi\to L=2\pi\cdot3960mi=7920\pi mi\approx7920\cdot3.14mi\n\n=24868.8mi\n\nv=(24868.8)/(23.93)\ mi/h\approx1039.231\ mi/h\leftarrow answer

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

Answers

Let

A-----> (7)/(8)

B-----> (11)/(10)

C-----> 1

we know that

Point A-------> Multiply numerator and denominator by 10

(7*10)/(8*10) =(70)/(80)

Point B-------> Multiply numerator and denominator by 8

(11*8)/(10*8) =(88)/(80)

Point C-------> Multiply numerator and denominator by 80

(1*80)/(1*80) =(80)/(80)

Find the distance Point A to Point C

(80)/(80) -(70)/(80) =(10)/(80)

Find the distance Point B to Point C

(88)/(80) -(80)/(80) =(8)/(80)

therefore

(8)/(80) < (10)/(80)

Point B is closer to Point C

(11)/(10) is closer to 1

the answer is

(11)/(10) is closer to 1
You can also figure it out by knowing that 7/8 is 1/8 away from 1 and 11/10 is 1/10 away from 1. since 1/10 is smaller than 1/8, you know that 11/10 is closer to 1 than 7/8.

The length of a rectangle is twice its width. The perimeter of the rectangle is no more than 174 cm. What is the greatest possible value for the width? (a) Write an inequality to model the problem. Explain why the inequality models the problem.
(b) Solve the inequality. Show your work.
(c) Answer the question.

Answers

a.2x+4x≤174 or y+x≤174 or x≤174
This is because x stands the width and that the perimeter.
b. 6x≤174
x≤29
c. The greatest possible value is 29. 
Other Questions
Which pair of numbers is relatively prime? A.12 and 25B.24 and 45C.9 and 24D.18 and 39
What is the value of the 2 in 13721 compared to the value of the 2 in 11259
PLEASE HELP!How would you suggest they change their prices?1 ticket = .5012 tickets = $5.00 or .42/ticket25 tickets = $10.00 or .40/ticket50 tickets = $25.00 or .50/ticket120 tickets = $50.00 or .42/ticket
How many diagonals does a triangular prism have?