A skier pushes her ski poles against the ground. She begins to move across the snow. Earth does not seem to move. Identify the action and reac-tion forces in this example, and explain why the skier moves but Earth does not seem to.

Answers

Answer 1
Answer:

Answer:

The earth has a larger mass and therefore more inertia.

Explanation:


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D.
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Answers

The right answer for the question that is being asked and shown above is that: "B. condensation from the ocean and then evaporation into a cloud." a water molecule transfer from the ocean to form part of a cloud in the atmosphere is that condensation from the ocean and then evaporation into a cloud

Answer:

b

Explanation:

that to somebody who answered!

Humans can hear frequencies up to approximately 20,000 Hz, while dogs can hear frequencies up to around 60,000 Hz. What sound frequency would you expect to be emitted by a dog whistle, which can be heard by dogs but not by humans?

Answers

Answer:

Between 23,000 to 54,000 Hz

Final answer:

A dog whistle typically emits sound at frequencies above 20,000 Hz but below 60,000 Hz, which is a range humans cannot hear but dogs can.

Explanation:

The frequency of sound emitted by a dog whistle is typically above the range of human hearing, which upper limit is around 20,000 Hz. However, since dogs can hear up to about 60,000 Hz, you would expect a dog whistle to emit sound at frequencies above 20,000 Hz but below 60,000 Hz. So, a frequency anywhere within the range 20,000 Hz and 60,000Hz would be suitable for a dog whistle.

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how should the charge q be divided into two parts such that they experience maximum electrostatic repulsion

Answers

Answer:

To divide the charge q into two parts such that they experience maximum electrostatic repulsion, the charges should be equal in magnitude and opposite in sign. In other words, the charge q should be divided into two equal charges of -q/2 and +q/2. This arrangement will result in the maximum electrostatic repulsion between the charges, as like charges repel each other.

Explanation:

A radio wave has a frequency of 5.5 × 104 hertz and travels at a speed of 3.0 × 108 meters/second. what is its wavelength? a. 5.5 × 104 meters b. 5.0 × 103 meters c. 5.5 × 103 meters d. 3.0 × 108 meters

Answers

The wavelength of the radio wave is 5.5 × 10³ m. If the frequency of the wave is 5.5 × 10⁴ hertz and the speed of the wave is 3.0 × 10⁸ m/sec.

The speed(v) of a wave is the product of wavelength(λ) and the frequency(η). We can understand this relation by the definition of the speed, which is the distance travelled by the object in unit time. The unit of distance is meter, also the unit of the wavelength is meter. On the other hand the unit of frequency is sec⁻¹. So,

Speed of a wave(v) = wavelength(λ) × Frequency(η)

Wavelength(λ) = speed of the wave(v)/Frequency(η)

Wavelength(λ) = (3.0 × 10⁸)/(5.5 × 10⁴)

Wavelength(λ) = 5.5 × 10³ m

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Objects on the moon's surface have an acceleration due to gravity one-sixth that on the earth's. What would the 40 kg boy weigh on the moon? (Round answer to nearest tenth.)

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acceleration is the same as the gravitational force. On earth that is 9.81 m/s^2. F=ma so if the acceleration is 1/6, then so if the force (weight). 40/6 N is your answer.

A mass of 1.0 kg is initially held in place on a ramp of angle 45o at height of 20. meters above the ground. The mass is released and slides to the bottom of the ramp (h=0). There is friction between the mass and the ramp. At the bottom of the ramp, the object has a speed of 10. m/s. The thermal energy was generated by the friction as the mass slides down the ramp is closest to which value?

Answers

Answer:

The thermal energy generated by the friction as the mass slides down the ramp is \bf{146~J}.

Explanation:

Given:

The mass of the object is, m = 1.0~kg

The angle of the ramp is, \theta = 45^(0)

The initial height of the object on the ramp is, h = 20~m

The final velocity of the object is, v = 10~m/s

When the object is at rest on the ramp, its total energy is potential energy. When it moves down the ramp its kinetic energy is increased and potential energy is decreased and a part of its energy is lost to overcome the force of friction. Finally, when it is at the bottom of the ramp, its total energy becomes only kinetic energy.

The total energy of the object at a height 20~m on the ramp is given by

E_(1) &=& mgh\n~~~~&=& (1.0~kg)(9.8~m/s^(2))(20~m)\n~~~~&=& 196~J

When the object is at the bottom of the ramp, its total energy is given by

E_(2) &=& (1)/(2)mv^(2)\n~~~~&=& (1)/(2)(1.0~kg)(10~m/s)^(2)\n~~~~&=& 50~J

So, the energy that is lost as thermal energy is given by

E &=& E_(1) - E_(2)\n~~~~&=& 196~J - 50~J\n~~~~&=& 146~J