A certain analytical method for the determination of lead yields masses for lead that are low by 0.5 g. Calculate the percent relative error caused by this deviation for each measured mass of lead. Report the percent relative error with the correct number of significant figures.

Question Continuation

if the measured weight of lead in the sample is

a.) 764.9g lead

b.)226.3g lead

c.) 53.5g lead

Answer:

a.

Relative Error = 0.065

b.

Relative Error = 0.221

c.

Relative Error = 0.935

Step-by-step explanation:

Given

Absolute Error = 0.5g

Relative error = absolute error/magnitude of measurement.

Relative error % = Relative error * 100

a.

Relative Error = 0.5/764.9 * 100

Relative Error = 50/764.9

Relative Error = 0.065

b.

Relative Error = 0.5/226.3 * 100

Relative Error = 50/226.3

Relative Error = 0.221

c.

Relative Error = 0.5/53.5 * 100

Relative Error = 50/53.5

Relative Error = 0.935

Final answer:

In Chemistry, the percent relative error is calculated by taking the absolute value of the error divided by the original measurement, and then multiplying by 100%. In this case, for a measured value of lead, the percent relative error would be (0.5 g / measured mass) * 100%.

Explanation:

The percent relative error in any measurement is calculated by taking the absolute value of the error divided by the measured value, all multiplied by 100% to get the result in percent forms. In this case, the absolute error is always 0.5 g (which means the values are consistently 0.5 g less than expected). The percent relative error would be calculated as follows:

• For a measured value, say M grams, the percent relative error would be (0.5 g / M) * 100%.

Keep in mind, the relative error varies with each measured mass. Therefore, for each different measured mass of lead, you would substitute that value in place of M in the above formula to calculate the respective percent relative error.

Learn more about percent relative error here:

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