The quadrilaterals JkLM and PQRS are similar.find the length x of QR.

Answers

Answer 1

Answer: Two quadrilaterals are similar if corresponding sides taken in the same sequence (even if clockwise for one quadriateral and counterclockwise for the other) are proportional and corresponding angles taken in the same sequence are equal in measure.
If the quadrilaterals JKLM and PQRS are similar, then

$(JK)/(PQ) = (KL)/(QR) = (LM)/(RS) = (JM)/(PS)$ .
Hence
$(4)/(QR) = (3)/(4.8) = (5)/(8) = (3)/(4.8)$ and
$QR= (4\cdot 8)/(5) =6.4$ .

Answer 2

Answer: 3/4.8=4/x
3x=19.2
x=6.4

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Two computer technicians, Sue and Kiana, each counted the number of computers that she had repaired every day for 2 weeks. Their manager made line plots from these data.What is the degree of overlap of the two data sets’ distributions?

Answers

The correct to the question above would be high. If Sue and Kiana are counting the number of computers that they had repaired every day for 2 weeks and if their manager also made a line plot from these data, it would be a high degree of over of the two data sets' distributions.

the answer to the question is high

Rob has 40 coins, all dimes and quarters, worth $7.60. How many dimes and how many quarters does he have?

Answers

The required Rob has 16 dimes and 24 quarters as he has a total of 40 coins.

What are equation models?

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let x be the number of dimes that Rob has, and y be the number of quarters.

We know that he has a total of 40 coins, so,

x + y = 40 ( 1)

We also know that the value of all his coins is $7.60. The value of x dimes is 10x cents, and the value of y quarters is 25y cents. So,

10x + 25y = 760 ( 2)

Now we can solve for x and y. Let's start by solving equation 1 for one of the variables:

x + y = 40

y = 40 - x

Substitute this expression for y into equation 2:

10x + 25y = 760

10x + 25(40-x) = 760

10x + 1000 - 25x = 760

-15x = -240

x = 16

So Rob has 16 dimes. We can use equation 1 to find the number of quarters:

x + y = 40

16 + y = 40

y = 24

So Rob has 24 quarters.

Therefore, Rob has 16 dimes and 24 quarters.

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24 quarters and 16 dimes because 24*25=600 and 16*10=160 add them 2gether will be 760=$7.60

What is y= -x^2-2x+3 in vertex form

Answers

y = -x² - 2x + 3
  y - 3 = -x² - 2x + 3 - 3
  y - 3 = -x² - 2x
y - 3 - 1 = -x² - 2x - 1
  y - 4 = -(x²) - (2x) - (1)
  y - 4 = -(x² + 2x + 1)
  y - 4 = -(x² + x + x + 1)
  y - 4 = -(x(x) + x(1) + 1(x) + 1(1))
  y - 4 = -(x(x + 1) + 1(x + 1))
  y - 4 = -(x + 1)(x + 1)
  y - 4 = -(x + 1)²
y - 4 + 4 = -(x + 1)² + 4
y = -(x + 1)² + 4

Which equation is the rule for the pattern in the table?

Answers

Answer:

Step-by-step explanation:

Answer:

the answer is b

Step-by-step explanation:

You are driving home on a weekend from school at 55 mi/h for 110 miles. it then starts to snow and you slow to 35 mi/h. you arrive home after driving 4 hours and 15 minutes. how far is your hometown from school

Answers

The distance between hometown and school is 188.75 miles.

Given that, the person drive 110 miles at 55 miles/hour.

Average speed is calculated by dividing a quantity by the time required to obtain that quantity. Meters per second is the SI unit of speed. The formula $S = (d)/(t)$ , where S is the average speed, d is the total distance, and t is the total time, is used to determine average speed.

Due to snow, speed is slow down to 35 miles/hour.

Let x miles be travelled with 35 miles/hour.

Total time taken to travel is 4 hours and 15 minutes.

Here, $T_1=(110)/(55)$ and $T_2=(x)/(35)$

Now, $T=T_1+T_2$

$(110)/(55)+(x)/(35)=4(15)/(60)$

$((110*7+x*11))/(385)=4(1)/(4)$

$((770+11x))/(385)=(17)/(4)$

$4(770+11x)=385*17$

$3080+44x=6545$

$44x=6545-3080$

$44x=3465$

$x=78.75$ miles

Total distance = 110+78.75

= 188.75 miles

Therefore, the distance between hometown and school is 188.75 miles.

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Final answer:

The total distance from school to the student's hometown is calculated as the sum of distances covered at different speeds. The student spends 2 hours at 55 mi/h, covering 110 miles, and then 2.25 hours at 35 mi/h, covering 78.75 miles, making up a total of 188.75 miles.

Explanation:

The question pertains to the concepts of distance, speed and time in mathematics. In this scenario, the student drives at a speed of 55 mi/h for 110 miles and then slows down due to snowfall and drives at 35 mi/h. From this information, we can calculate the time spent at each speed.

Firstly, since Speed = Distance / Time, we can rearrange to find Time = Distance / Speed. For the first stretch of the journey, the time is 110 miles / 55 mi/h = 2 hours.

It is given that the total journey takes 4 hours and 15 minutes which is equivalent to 4.25 hours. So, the time spent driving at 35 mi/h is 4.25 hours (total trip time) - 2 hours (first stretch) = 2.25 hours.

The distance covered when it was snowing can be found by multiplying this time by the slower speed: 35 mi/h * 2.25 h = 78.75 miles.

Therefore, the total distance from school to the student's hometown is the sum of the distance traveled at each speed: 110 miles (at 55 mi/h) + 78.75 miles (at 35 mi/h) = 188.75 miles.

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AB¯¯¯¯¯ and BC¯¯¯¯¯ are tangent to ⊙ O. Identify BC.

Answers

Answer:

Step-by-step explanation:

$2(3x-7)=4x+8\nx=11\n4(11)+8=52$

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