Find the value of y.​
Find the value of y.​ - 1

Answers

Answer 1
Answer:

Answer:

y=            9x+55

                    4

Step-by-step explanation:

if 9x+42=4y-13

9x+42+13=4y

y=            9x+55

                    4


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14+x=46;x=32whats the answer im so stuck

Part 1: Create your own real world Pythagorean theorem problem. Write an equation you could use to find the length of the missing side of your right triangle. Then find the missing length. Show all your work. Round to the nearest tenth if necessary.And write a summary sentencePart 2: Draw a visual to represent your real world problem

Answers

A 20 foot ladder is leaned against a wall. If the base of the ladder is 8 feet from the wall,how high up the wall will the ladder reach? so do 20^2 + 8^2=c2 so 20 times 20 is 400 +64 equals 464 

3.79 rounded to the nearest tenth

Answers

3.79

Look at the hundredth place, see if it's 5 or higher or 4 or lower.
Since it is 5 or higher, we round the tenth place up.

3.8

Betsy is making a flag. She must choose 3 colors from red, blue, yellow and white. How many choices does she have?

Answers

red, blue yellow
red blue white
red yellow white
blue yellow white
so she has 4 choices

In a fish tank, the ratio of orange fish to blue fish is 4:3. Which statement is true?3/4 of the fish in the tank are blue
if there is a total of 56 fish in the tank,than 24 of the fish are orange
The number of orange fish is 1 1/3 times the number of blue fish.
If there are 12 blue fish in the tank, then there are 18 orange fish.

Answers

Answer:

b) The number of orange fish is 1 1/3 times the number of blue fish.    

Step-by-step explanation:

We are given the following information in the question:

In a fish tank, the ratio of orange fish to blue fish is 4:3.

Thus, we can write:

\displaystyle\frac{\text{Orange fish}}{\text{Blue fish}} = (4)/(3)

Thus, total number of fishes in the tank can be written as:

\text{Number of orange fish  + Number of blue fish}\n= 4x + 3x = 7x

a) False

If there is a total of 56 fish in the tank,than 32 of the fish are orange

Total number of fish = 56

7x = 56\nx = 8\n\text{Number of orange fish } = 4x = 32

b)True

\text{Number of orange fish} = 1\displaystyle(1)/(3)\text{Number of blue fish}\n\n\displaystyle\frac{\text{Orange fish}}{\text{Blue fish}} = 1(1)/(3) = (4)/(3)

c) False

If there are 12 blue fish in the tank, then there are 16 orange fish.

Number of blue fish  = 12

\displaystyle\frac{\text{Orange fish}}{\text{Blue fish}} = (4)/(3) \n\n\frac{\text{Number of Orange fish}}{12} = (4)/(3)\n\n\text{Number of orange fish} = 16

A ratio is seen as 4 vs 3 so out of 4+3=7, 4 are orange and 3 are blue.
4/7 are orange, 3/7 are blue
The number of orange fish is 1 1/3 times the number of blue bc 4/3 and 4/7÷3/7 equals 1 1/3

Simplify the expression below.
13y + x - 7y

Answers

\text{Simplify:}\n\n13y + x - 7y\n\n\text{Combine like terms}\n\n13y + x - 7y\n\n6x+y\n\n\text{Since you can't combine anything else, that will be your answer}\n\n\boxed{6y+x}


Answer: =x+6y
Explanation:

tickets to the fair cost $8 for children and $15 for adults on Thursday 177 people enter the fair and they collected $2053. what number of the children and what number of adults attended?

Answers

So,

Let

number of children tickets bought = c
number of adult tickets bought = a

We can now say that
c + a = 177
8c + 15a = 2053
because if you multiply c by the cost per child and a by the cost per adult, you will get the total revenue generated by all the tickets.

We now have a system of equations which can be solved by elimination (substitution).

Subtract a from both sides of the first equation.
c = 177 - a

Substitute 177 - a for c in the second equation.
8(177 - a) + 15a = 2053

Distribute.
1416 - 8a + 15a = 2053

Collect Like Terms.
1416 + 7a = 2053

Subtract 1416 from both sides.
7a = 637

Divide both sides by 7.
a = 91

Substitute 91 for a in the first modified equation.
c = 177 - 91
c = 86

Check.

The total number of people was 86 + 91 = 177 people.

The total revenue generated was 8(86) + 15(91) = 688 + 1365 = $2053.

There were 86 children and 91 adults.