You view your face in a concave mirror of focal length 20 cm and wish it to be magnified by a factor of 1.5. What should you do?

Answers

Answer 1
Answer:

Answer:

u = 6.667 cm

Explanation:

given,

Focal length of the concave mirror, f = 20 cm

magnification factor = 1.5  

we know,

M = (-v)/(u)

v is the distance of the image

u is the distance of the object

1.5 = (-v)/(u)

v = -1.5 u

Using mirror formula

(1)/(f)= (1)/(u) + (1)/(v)

(1)/(f)= (1)/(u) - (1)/(1.5u)

(1)/(20)=(1)/(3u)

3u = 20

u = 6.667 cm

distance of the person from the mirror is equal to 6.667 cm.


Related Questions

Imagine that you are sitting in a closed room (no windows, no doors) when, magically, it is lifted from Earth and sent accelerating through space with an acceleration of 1g (9.8 m/s2). According to Einstein's equivalence principle, which of the following is true?You won't feel any change and will have no way to know that you've left the earth.You'll feel a force that will cause your head to repeatedly bang into the ceiling.You'll know that you left the Earth because you'll be floating weightlessly in your room.You'll know that you left the Earth because when you drop a ball it will fall sideways.
Who first arranged the elements according to atomic mass and noticed a periodic recurrence of their physical and chemical properties?A. Henry Moseley B. Antoine Lavoisier C. John Dalton D. Dmitri Mendeleev
Tobacco use can negatively impact a person's health, family, and finances. True or false
A hydrogen atom has one proton, two neutrons, and no electrons. Is this atom neutrally charged? Explainyour answer.
Which of the following helps support the argument that light behaves like a particle? A. Sound, which travels in waves, can't travel through a vacuum. B. Interference is observed with light. C. Diffraction is observed with light. D. Unlike sound, light waves don't need a medium to self-propagate

Objects that are closer together have a stronger force of gravity between them.True
False

Answers

I think it's true because the force gets stronger as the two objects move closer together.

A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical components of its velocity after 5.5sI need shown work !

Answers

Answer:

v_x=34 m/s

v_y=53.9\ m/s

Explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

v_y=g.t

The horizontal component of the velocity is always the same:

v_x=34 m/s

The vertical component at t=5.5 s is:

v_y=9.8*5.5=53.9

v_y=53.9\ m/s

Which one of the following choices best describes an advantage of isometric exercise? A. Rapid strength improvement
B. Improved strength across the entire range of motion
C. Improved joint flexibility
D. Motivational

Answers

Answer: C. Improved joint flexibility

Explanation:

Isometric exercises are the exercises which involves the contraction of particular muscles or group of muscles. In these exercises the muscles do not change their length and the joints does not move. These are the exercises which are done in one position. These exercises are performed in order to obtain strength during training exercises during which the muscle length and joint angles do not basically change. These exercises are high intensity exercises and contributes to the building of muscles and burning of fat.

On the basis of the above information, A. Rapid strength improvement is the correct option.

Final answer:

The primary advantage of isometric exercise is rapid strength improvement in a specific area, not necessarily improved flexibility or range of motion.

Explanation:

The best answer that describes an advantage of isometric exercise is A. Rapid strength improvement. Isometric exercises are often used for rehabilitation and building strength, as they involve the contraction of a specific set of muscles in a static position. This type of exercise does not involve the muscle changing length or the joint angle changing, which allows for an increase in strength in a very focused manner.

This does not necessarily mean that isometric exercises enhance joint flexibility (C) or improve strength across the entire range of motion (B) as the movement is static. The motivation aspect (D)  can differ from person to person, but it's not a direct physical benefit of isometric exercises.

Learn more about isometric exercise
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All atoms of the same element must have the same number of

Answers

Explanation:

Atomic number is defined as the total number of protons present in an element.

Each element of the periodic table has different atomic number because each of them have different number of protons.

For example, atomic number of Na is 11, and atomic number of Ca is 20.

On the other hand, atomic mass is the sum of total number of protons and neutrons present in an atom.

For example, atomic mass of nitrogen is 14 that is, it contains 7 protons and 7 neutrons.

Thus, we can conclude that all atoms of the same element must have the same number of protons.

Answer: Protons

Explanation: The number of protons corresponds to the atomic number.

It would be appreciated if all questions were answered and have shown work. :)1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his momentum as he leaves the jump?


2. How fast would a 0.25 kg football have to be traveling to have the same momentum as a 0.05 kg bullet travelling 500 m/s?


3. Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her seat-belt stops her from flying forward, bringing her to rest in 0.5 seconds. How much force did the seat-belt put on Sarah?

Answers

1. The formula for momentum is:
p = mv
p =75(18) = 1350 kg-m/s

2. We equate the momentum of the two objects
0.25 v = 0.05 (500)
v = 100 m/s

3. We use the formula for impulse:
Δmv = FΔt
55(20) = F(0.5)
F = 2200 N

1)

P = mv  

P=75 (18) = 1350 kg-m/s


2)

0.25 v= 0.05 (500)

V= 100 m/s


3)

∆ mv = F∆t

55(20) =F(0.5)




A 5.00 kg pendulum swings back and forth. At the top of its arc, it reaches a height of 0.36 m. What is the velocity of the pendulum at the bottom of the arc?0m/s
2.7m/s
7.2m/s

Answers

Tools we'll use:

--     Gravitational potential energy = (mass) x (gravity) x (height)

--     Kinetic energy (of a moving object) = (1/2) (mass) x (speed)²

When the pendulum is at the top of its swing,
its potential energy is

                             (mass) x (gravity) x (height)

                         =  (5 kg) x (9.8 m/s²) x (0.36 m)

                         =      (5 x 9.8 x 0.36)        joules

                         =            17.64 joules .

Energy is conserved ... it doesn't appear or disappear ...
so that number is exactly the kinetic energy the pendulum
has at the bottom of the swing, only now, it's kinetic energy:

                   17.64 joules  =  (1/2) x (mass) x (speed)²

                   17.64 joules  =  (1/2) x (5 kg) x (speed)²

Divide each side by 2.5 kg:

                   17.64 joules / 2.5 kg  =  speed²

Write out the units of joules:

                   17.64 kg-m²/s²  /  2.5 kg  =  speed²

                   (17.64 / 2.5) (m²/s²)  =  speed²

                       7.056 m²/s²  =  speed²

Take the square root
of each side:              Speed = √(7.056 m²/s²)

                                           =    2.656 m/s .

Looking through the choices, we're overjoyed to see
that one if them is  ' 2.7 m/s '.  Surely that's IT !
_______________________________

Note:
The question asked for the pendulum's 'velocity', but our (my) calculation
only yielded the speed.

In order to describe a velocity, the direction of the motion must be known,
and the question doesn't give any information on exactly how the pendulum
is hanging, and how it's swinging. 

We know that at the bottom of its swing, the motion is completely horizontal,
but we have no clue as to what direction.  So all we can discuss is its speed.