MATHEMATICS HIGH SCHOOL

Angle A is in standard position and terminates in quadrant IV. If sec(A)=4/3, complete the steps to find cot(A).Use the identity_ to find the value of _(A).

Thank you in advance !!
Cheers, Z

Answers

Answer 1

Answer:

Answer:

Part A) Use the identity $tan^2(A)+1=sec^2(A)$

Part B) $cot(A)=-(3√(7))/(7)$

Step-by-step explanation:

we know that

$tan^2(A)+1=sec^2(A)$ ----> by trigonometric identity

we have

$sec(A)=(4)/(3)$

substitute in the expression above

$tan^2(A)+1=((4)/(3))^2$

solve for tan(A)

$tan^2(A)+1=(16)/(9)$

$tan^2(A)=(16)/(9)-1$

$tan^2(A)=(7)/(9)$

square root both sides

$tan(A)=\pm(√(7))/(3)$

Remember that Angle A terminates in quadrant IV

The value of tan(A) is negative

$tan(A)=-(√(7))/(3)$

Find the value of cot(A)

we know that

$cot(A)=(1)/(tan(A))$ ----> is the reciprocal

therefore

$cot(A)=-(3)/(√(7))$

simplify

$cot(A)=-(3√(7))/(7)$

Answer 2

Answer:

Answer:

First answer is A.

Second answer is: tan.

Third is answer C. sqrt7/3

Fourth answer is A. -3sqrt7/7

Step-by-step explanation:

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Someone help me PLZZ

Answers

Answer:

5/3

Step-by-step explanation:

The slope is the coefficient next to the x. Therefore, the slope is 5/3.

Answer:

m= 5/3

Step-by-step explanation:

Math wizzz

Worked it out

And online calculator verified!

Which equation can be used to represent six added to twice the sum of a number and four is equal to one-half of the difference of three and the number?

Answers

six added to twice the sum of a number and four is equal to one-half of the difference of thee and the number.

Let x be the number.

6 + 2(x + 4) = 1/2 * (3-x)

Find the value of x.

6 + 2x + 8 = 3/2 - x/2
2x + x/2 = 3/2 - 8 - 6
2x + x/2 = 3/2 - 14
2(2x + x/2) = 2(3/2 - 14)
4x + x = 3 - 28
5x = -25
x = -25/5
x = -5

To check: x = -5

6 + 2(x + 4) = 1/2 * (3-x)

6 + 2(-5+4) = 1/2 * (3 - (-5))
6 + 2 (-1) = 1/2 * (3 + 5)
6 - 2 = 1/2 (8)
4 = 4

Answer: Opion A

(A) 6 + 2(X + 4)= 1/2(3-X) <=========+ 100 %

Step-by-step explanation:

Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green balls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?A. 2/51
B. 3/20
C.1/10
D.4/153

Answers

b- 3/20. first, add up the number of balls in each urn.
urn 1- 10
urn 2- 8
then, make a fraction where the numerator is the number of blue balls in the urn and the denominator is the total number of balls
urn 1- 6/10 (simplified to 3/5)
urn 2- 2/8 (simplified to 1/4)
finally, multiply your two probabilities and simplify
1/4*3/5=3/20

Sequencing of rigid motions matters . true or false ?

Answers

Answer:

False.......................

Step-by-step explanation:

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f(x) = (x − 8)(x + 8)
f(x) = x(x − 8)^2
f(x) = x(x^2 − 8)