Answers
Answer:
When the jet reaches a speed of 181 m/s, its displacement is 296 m.
Explanation:
Hi there!
The equation of position and velocity of an object traveling with constant acceleration along a straight line are the following:
x = x0 + v0 · t + 1/2 · a · t²
v = v0 + a · t
Where:
x = position of the object at time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
v = velocity of the object at time t.
If we place the origin of the frame of reference at the point where the jet starts moving, then, x0 = 0. Since the jet starts from rest, v0 is also zero. Then the equations get reduced to the following:
x = 1/2 · a · t²
v = a · t
We know the acceleration and the final velocity of the jet. So, using the equation of velocity, we can find the time it takes the jet to reach that velocity. Then, we can calculate the position of the jet at that time. Since the initial position is zero, the final position of the jet will be equal to the displacement (because displacement = final position - initial position).
v = a · t
v/a = t
181 m/s / 55.3 m/s² = t
t = 3.27 s
The final position of the jet will be:
x = 1/2 · a · t²
x = 1/2 · 55.3 m/s² · (3.27 s)²
x = 296 m
When the jet reaches a speed of 181 m/s, its displacement is 296 m.
The displacement of the F-35 jet when it reaches a speed of 181 m/s is 16515 m.
To find displacement using constant acceleration,
we can use the following equation:
displacement = (final velocity)^2 - (initial velocity)^2 / 2 * acceleration.
In this case, the initial velocity is 0 m/s and the final velocity is 181 m/s.
The acceleration is given as 55.3 m/s^2.
Plugging in these values, we get:
displacement = (181)^2 - (0)^2 / 2 * 55.3 = 16515 m.
The displacement of the F-35 jet when it reaches a speed of 181 m/s is 16515 m.
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Answers
Answer:
The answers to the questions are;
(a) The velocity of the truck right after the collision is 20.884 m/s
(b) The change in mechanical energy of the car truck system in the collision is -9076.4384 J
(c) The change in mechanical energy is due to energy consumed by the collision process.
Explanation:
(a) From the principle of conservation of linear momentum, we have
m₁·v₁+m₂·v₂ = m₁·v₃ + m₂·v₄
Where:
m₁ = Mass of the car = 1225.0 kg
m₂ = Mass of the truck = 9700.0 kg
v₁ = Initial velocity of the car = 25.000 m/s
v₂ = Initial velocity of the truck = 20.000 m/s
v₃ = Final velocity of the car right after collision = 18.000 m/s
v₄ = Final velocity of the truck right after collision
Therefore
1225.0 kg × 25.000 m/s + 9700.0 kg × 20.000 m/s = 1225.0 kg × 18.000 m/s + 9700.0 kg × v₄
That is 30625 kg·m/s + 194000 kg·m/s = 22050 kg·m/s + 9700.0 kg × v₄
Making v₄ the subject of the formula yields
v₄ = (202575 kg·m/s)÷9700.0 kg = 20.884 m/s
The velocity of the truck right after the collision to five significant figures = 20.884 m/s
(b) The change in mechanical energy of the car truck system in the collision can be found by
The change in kinetic energy of the car truck system
Change in kinetic energy, ΔK.E. = Sum of final kinetic energy - Sum of initial kinetic energy
That is ΔK.E. = ∑ Final K.E -∑ Initial K.E.
ΔK.E. =
= (·1225·18²+
·9700·20.884²) - (
·1225·25²+
·9700·20²)
= 2313736.0616 kg·m²/s² - 2322812.5 kg·m²/s² = -9076.4384 kg·m²/s²
1 kg·m²/s² = 1 J ∴ -9076.4384 kg·m²/s² = -9076.4384 J
(c) The energy given off by way of the 9076.4384 J is energy transformed into other forms including
1) Frictional resistance between the tires and the road for the truck and car
2) Frictional resistance in the transmission system of the truck to increase its velocity
3) Sound energy, loud sound heard during the collision
4) Energy absorbed when the car and the truck outer frames are crushed
5) Heat energy in the form of raised temperatures at the collision points of the car and the truck.
6) Energy required to change the velocity of the car over a short distance.
Answers
E = hv, where v = the frequency and h = planck's constant.
So E = 5.20 x10^14 x 6.63 x 10^-34
= 3.45 x 10^-19 Joules
Answers
Answer:
C a position from which something is observed
om edu 2021
Explanation:
Answer: A system or frame of reference are those conventions used by an observer (usually standing at a point on the ground) to be able to measure the position and other physical magnitudes.
Answers
Answer:
* roller skates and ice skates.
* roller coaster
Explanation:
One of the best examples for this situation is when we are skating, in the initial part we must create work with a force, it compensates to move, after this the external force stops working and we continue movements with kinetic energy, if there are some ramps, we can going up, where the kinetic energy is transformed into potential energy and when going down again it is transformed into kinetic energy. This is true for both roller skates and ice skates.
Another example is the roller coaster, in this case the motor creates work to increase the energy of the car by raising it, when it reaches the top the motor is disconnected, and all the movement is carried out with changes in kinetic and potential energy. In the upper part the energy is almost all potential, it only has the kinetic energy necessary to continue the movement and in the lower part it is all kinetic; At the end of the tour, the brakes are applied that bring about the non-conservative forces that decrease the mechanical energy, transforming it into heat.
Answers
Answer:
m_cable = 2,676 kg
Explanation:
For this exercise we must look for the acceleration with the kinematic ce relations
v² = v₀² + 2 a x
since the block starts from rest, its initial velocity is vo = 0
a = v² / 2x
a = 4.2² /(2 2.0)
a = 4.41 m / s²
now we can use Newton's second law
Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.
F = (m + m_cable) a
m_cable = F / a -m
m_cable = 100 / 4.41 - 20
m_cable = 2,676 kg
Final answer:
Unfortunately, the information given does not provide enough data to determine the mass of the steel cable. This is because the force, acceleration, and distance information given only involve the mass of the block, not the cable.
Explanation:
The question is requesting the mass of the steel cable. However, given the information in the question, we don't actually have enough data to determine this. The application of the force, the acceleration of the block, and the distance it covers are all connected through Newton's second law (F = ma) and the equations of motion, but these only involve the mass of the block, not the mass of the cable. Even if we assumed the cable applies the entire 100 N force to the block, this would only allow us to solve for the acceleration of the block, not the mass of the cable. Therefore, the mass of the steel cable cannot be determined with the information provided in the question.
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Answers
Answer:
v = 4,244,699 m/s = (4.245 × 10⁶) m/s
Explanation:
The electric force on the proton is given by
F = qE
where q = charge on the proton = (1.602 × 10⁻¹⁹) C
E = Electric field = 720,000 N/C
F = (1.602 × 10⁻¹⁹ × 720000)
F = (1.153 × 10⁻¹³) N
But this force will accelerate the proton in this magnetic field in a form of trajectory motion.
We can obtain the acceleration using Newton's first law of motion relation
F = ma
m = mass of a proton = (1.673 × 10⁻²⁷) kg
a = (F/m)
a = (1.153 × 10⁻¹³)/(1.673 × 10⁻²⁷)
a = 68,944,411,237,298 m/s²
a = (6.894 × 10¹³) m/s²
This acceleration directs the proton from the positive plate to the negative plate, covering a distance of y = 0.006 m (the distance between the plates)
Using Equations of motion, we can obtain the time taken for the proton to move from the rest at the positive plate to the negative one.
u = initial velocity of the proton = 0 m/s
y = vertical distance covered by the proton = 0.006 m
a = acceleration of the proton in this direction = (6.894 × 10¹³) m/s²
t = time taken for the proton to complete this distance = ?
y = ut + (1/2) at²
0.006 = 0 + [(1/2)×(6.894 × 10¹³)×t²]
0.006 = (3.447 × 10¹³) t²
t² = (0.006)/(3.447 × 10¹³)
t² = 1.741 × 10⁻¹⁶
t = (1.32 × 10⁻⁸) s
Then we can then calculate the minimum speed to navigate the entire length of the plates without hitting the plates.
v = ?
x = 0.056 n
t = (1.32 × 10⁻⁸)
v = (x/t)
v = (0.056)/(1.32 × 10⁻⁸)
v = 4,244,699 m/s = (4.245 × 10⁶) m/s
Hope this Helps!!!
Answer:
v = 9.09×10⁵m/s
Explanation:
Given
d = the distance between plates = 0.6cm = 0.006
E = Electric field strength = 720000N/C
m =mass of the proton = 1.67 ×10-²⁷ kg
The
Electric potential energy of the field is converted into the the kinetic energy of the proton.
So
qV = 1/2mv²
But V = Ed
So q(Ed) = 1/2mv²
v² = 2qEd/m
v = √(2qEd/m)
v = √(2×1.6×10-¹⁹×720000×0.006/1.67×10-²⁷)
v = 9.09×10⁵m/s