Help ASAPSelect the two values of x that are roots of 7x - 15 = -2x.

A. x=-5
B. x=5
C. x= -3/2
D. x=3/2

Answers

Answer 1
Answer:

Answer:

x = 5/3

Step-by-step explanation:

Solve for x:

7 x - 15 = -2 x

Add 2 x to both sides:

7 x + 2 x - 15 = 2 x - 2 x

2 x - 2 x = 0:

7 x + 2 x - 15 = 0

7 x + 2 x = 9 x:

9 x - 15 = 0

Add 15 to both sides:

9 x + (15 - 15) = 15

15 - 15 = 0:

9 x = 15

Divide both sides of 9 x = 15 by 9:

(9 x)/9 = 15/9

9/9 = 1:

x = 15/9

The gcd of 15 and 9 is 3, so 15/9 = (3×5)/(3×3) = 3/3×5/3 = 5/3:

Answer: x = 5/3

Answer 2
Answer: 7x-15=-2x
+7 +7
-15=5x
-15 divided by 5 gives yu
X=-3

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A glacier advances toward the sea 0.004 mile anually. In 2010 the front of the glacier is 6.9 miles from the mouth of the sea. How far will it be from the sea in 2030.By the way if it helps, were learning how to identify hidden problems in multiple-step problems.. So its a multiple step problem, I really don't understand this so some help will really be appreciated.

Answers


You know where the glacier is now, and how far it moves in
one year.  The question is asking how close to the sea it will be
after many years.

Step-1 ... you have to find out how many years

Step-2 ... you have to figure out how far it moves in that many years

Step-3 ... you have to figure out where it is after it moves that far

The first time I worked this problem, I left out  the most important
step ...READ the problem carefully and make SURE you know
the real question.  The first time I worked the problem, I thought
I was done after Step-2. 

============================

Step-1:  How many years is it from 2010 to 2030 ?

               (2030  -  2010)  =  20 years .


Step-2:  How far will the glacier move in 20 years ? 

               It moves 0.004 mile in 1 year.

              In 20 years, it moves 0.004 mile 20 times

              0.004 x 20  = 0.08 mile


Step-3:How far will it be from the sea after all those years ?

              In 2010, when we started watching it, it was 6.9 miles
              from the sea.

              The glacier moves toward the sea.
               In 20 years, it will be  0.08 mile closer to the sea.
               How close will it be ?

               6.9 miles  -  0.08 mile  =  6.82 miles  (if it doesn't melt)

What is the inverse of the function f(x)= 15x+50/x+5

Answers

I think you mean

f(x) = (15x + 50)/(x + 5)

First, replace f(x) with y.

y = (15x + 50)/(x + 5)

Now, switch x and y.

x = (15y + 50)/(y + 5)

Now we solve for y.

x(y + 5) = 15y + 50

xy + 5x = 15y + 50

xy - 15y = -5x + 50

y(x - 15) = -5x + 50

y = (-5x+ 50)/(x - 15)

Now we replace y with f^(-1)(x).

f^(-1)(x) = (-5x+ 50)/(x - 15)

When is it helpful to round the quotient to the nearest hundredth

Answers

The correct answer is:

It is helpful to round to the hundredths when we are dealing with money.

Explanation:

Our monetary system has dollars and cents, and it takes 100 cents to make a dollar. This means we would have a measurement to the hundredth place for money. If we are dividing and get a quotient that goes past the hundredths place, if it is money, we should round it to the hundredths place.

Write two expressions where the solution is 41.

Answers

31 +10
21 + 20
23 + 18
21+20
31+10
just add 21 and 20
and just add 31 and 10 and youll have your 2 expressions

Helppppp plz 10points

Answers

A rise  is a line going upwards from left to right

a decrease is a line going downwards from left to right

Choice B

The answer is be because it show its progress dropping down.

Expression for: Triple 3 and then add double 8

Answers

(3x3)+(8x2)
x is a multiplication sign