The model is made of an ionic compound of aluminum and chlorine. Aluminum has an oxidation number of 3 and chlorine has an oxidation number of -1. Based on the evidence, predict the chemical formula, chemical name and properties of the compound between aluminum and chlorine.
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Answer:
Chemical Formula: AlCl₃
Chemical Name: Aluminium Chloride
Properties are given below.
Explanation:
Chemical Formula:
Chemical formula depicts the total number of elemants forming a particular compound. It is common that all compounds are neutral in nature despite of the internal charges they contain. As given Aluminium has a + 3 charge while Chlorine has a -1 charge, therefore, to make a neutral compound we will require 3 Cl⁻ ions to neutralize one Al³⁺ ion hence, the chemical formula will be AlCl₃.
Chemical Name:
According to rules ionic compounds are named by naming the positive part first followed by negative part. In this case Al³⁺ being is name d first followed by Cl⁻ (remember the -ine in anions is replaced by -ide) hence, this compound will be name as Aluminium Chloride.
Properties:
Few physical and chemical properties of AlCl₃ are;
(i) It melts at 192.4 °C
(ii) Highly Soluble in water
(iii) It has a density of 2.48 g/cm³
(iv) Poor conductor of electricity
(v) It is used as catalyst in many organic reactions
(vi) Reacts with silver nitrate to form silver chloride and Aluminium Nitrate
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B. R
C. O
D. C
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Answer:
B. R
Explanation:
A layer of partially weathered or unweathered rock is present in R soil horizon
Answer: Option (B)
Explanation: The R-layer represents the unweathered rocks that are located below the surface and is the lowest layer in the soil profile. Here, hard rocks are found which are difficult to break, and are breakable with heavy machineries only. This R-layer makes the foundation of the soil profile that supports the entire overlying series of layers.
Thus, the correct answer is option (B).
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B. 0.250 mole LiCl dissolved in 250 ml of solution
C. Both the same
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The higher concentrated solution is 0.250 mole LiCl dissolved in 250 ml of solution
( B).0.250mole of LiCl diluted in 250ml solution
Explanation:
Procedure to find the intensity of the solution:
To find the intensity of the solution, we have to use the following formula
M1V1=M2V2
250mL of a 0.500 M aqueous solution of LiCl is diluted with water
250 ml of a 0.250M aqueous solution of LiCl is diluted with water
Thus the PH level of a solution increases from ascending order, Therefore the Solution with 62.5M is a higher concentration than that of the solution with 125M.
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BECAUSE 5 DIVIDED BY 2 IS 2.5