Find a5: 0, 3, 8, 15, a5, 35, ... a. 20

b. 22

c. 24

d. 25

Answers

Answer 1

Answer: 1X1-1: 0
2X2-1: 3
3X3-1: 8
4X4-1: 15
5X5-1: 24
6X6-1: 35
7X7-1: 48
*8X8-1: 63*

Answer 2

Answer:

Final answer:

In the sequence 0, 3, 8, 15, a5, 35, the term a5 equals 24 as each term in the sequence is the square of its position minus 1.

Explanation:

To determine the value of a5 in the sequence 0, 3, 8, 15, a5, 35,... let's first analyze the pattern in the sequence. Each term equals the square of the term's position in the sequence minus 1. This implies that the first term is (1²-1)=0, the second term is (2²-1)=3, the third term is (3²-1)=8, and so on. Hence, the fifth term a5 would be (5²-1)=24. So, the answer is c. 24.

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Answers

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Answers

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Answers

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Answers

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Let

x------> the number

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$x>7$

Answer:

Let

x------> the number

The statement It must exceed seven, represent the inequality

Step-by-step explanation:

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Answers

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