A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of a 2.18 g sample burns in excess oxygen yields 3.94 g of CO2 and 1.89 g of H2O. A separate experiment shows that a 1.23 g sample contains 0.235 g of N. Calculate the moles of C in the sample.1. Calculate the moles of N for a 2.18 g sample (the sample size for the other analyses).
2. Calculate the moles of O in the sample.

Answers

Answer 1
Answer:

Answer:

The answers are

C = 0.0895 moles

1. 0.02975 moles of N

2. 0.0299 moles O

Explanation:

Mass of sample = 2.18 g

Combustion yields 3.94 g of CO₂ and 1.89 g of H₂O

1.23 g of sample contains 0.235 g of N

3.94 g of CO₂ which contains one mole of C and two moles of O

Molar mass of CO₂ = 44 mass fraction of C = 12/44 = 0.273, Therefore mass of  carbon in 2.18 g = 0.273×3.94 = 1.075 g

number of moles of C in sample = mass/(molar mass) = 1.075 g/(12.01 g/mol) = 0.0895 moles of C

(1) Mass of nitrogen, in 1.23 g of sample = 0.235

therefore mass in 2.18 g =0.235×2.18/1.23 = 0.4165 g

= 0.02975 moles of N

(2) To find the number of moles of oxygen in the sample we note that total mass of sample  = 2.18 g containing only nitrogen, hydrogen, oxygen and carbon

Mass of hydrogen can be fround from 2/18×1.89 = 0.21 g

Mass of oxygen therefore = 2.18 -(0.21+0.4165+1.075) = 0.4785  

number of moles = 0.475/16 = 0.0299 moles


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A sample of 0.3257 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of AgNO3. If the mass of the AgBr precipitate that forms is 0.7165 g, what is the percent by mass of Br in the original compound?

Answers

Answer:

Explanation:

Given parameters:

Mass of ionic compound = 0.3257g

Mass of AgBr precipitate = 0.7165g

Unknown:

Percent mass of Br in the original compound.

Solution

The percent mass of Br in original compound = (mass of  Br  in the sample)/(mass of sample)

Now we have to find the mass of Br⁻:

We must note that the same mass of Br⁻ would move through the ionic sample to form the precipitate.

Mass of Br in AgBr = (Atomic mass of Br)/(Molar mass of AgBr)  x mass of precipitate

Mass of Br =  (80)/(80 + 108)  x 0.7165

Mass of Br = 0.426 x 0.7165 = 0.305g

Percent mass of Br = (0.305)/(0.3257) x 100 = 93.7%

#1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal............... #2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ ..................#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................#5: In a calorimeter, 3.34 kJ of heat was absorbed when 10 g of ice melted. What is the enthalpy of fusion of the ice? A. 6.68 J/g / B. 334 J/g / C. 6.68 kJ/g/ D. 334 kJ/g

Answers

Among the choices, the unit of energy is calories. Answer in 1) is D. In 2) we are given with te mass , heat and temperature change. we just need to get the heat capacity and compare it with the following metals. The calculated heat capacity is 0.46 kJ/kg K. The answer is A. iron. In 3) we can compute the heat absorbed by the formula ΔH=mCpΔT. Cp of water is 4.18 J/g K. Answer of 3) is D. In 4) the formula used in Cp=ΔH/mΔT. Answer in 4) is A. The heat of enthalpy of fusion of ice is 80 cal/g. We convert this to J/g. Answer  in 5) is B.334 J/g.

Answer:

1. D. cal......

2.A. iron

3. D

4.2.44j/g°C   A

5,Lf=334J/g   B

Explanation:

1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal...............

calorie is the unit of energy

#2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................

Q=mcdt

1840=0.2*C*(45-25)

C=460J/KgK

if the specific heat capacity is the above then he substance is iron

#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ .................

Q=mcdT

Q=0.1*10*4180

Q=4180j. answer D

.#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................

Q=mcdT

1830=50/1000*C*15

C=2440j/kg/k

change it to j/g°C

2.44j/g°C   A

#5: In a calorimeter, 3.34 kJ of heat was absorbed when 10 g of ice melted. What is the enthalpy of fusion of the ice? A. 6.68 J/g / B. 334 J/g / C. 6.68 kJ/g/ D. 334 kJ/g

Q=mLf

Lf=enthalpy of fusion

3340/10=Lf

Lf=334J/g   B

Enthalpy of fusion quantity of heat to convert 1 unit mass of a solid to liquid without any noticeable change in temperature.

The image is of the formation of a fault-block mountain.Which of these most likely occurs to result in the
formation of these mountains?
O The crust is compressed
O The crust does not spread apart
The center block is forced upward.
The hanging walls from the two parallel faults slip down​

Answers

The Formation of these mountains will be caused by

  • The crust does not spread apart
  • The center block is forced upward.
  • The hanging walls from the two parallel faults slip down​

Options B, C, and D is correct.

What are mountains?

Generally, a mountain is simply defined as a body that rises dramatically above its surroundings and is distinguished by steep slopes.

In conclusion, Mountains are formed from the formation of rocks over years in an Environment.

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Answer:

d.

Explanation:

In what way would readings from a digital thermometer be preferable to those from a liquid-based thermometer?

Answers

A digital thermometer is more preferable than a liquid-based thermometer because it gives accurate data than the liquid thermometer. Liquid thermometer is affected by the temperature, and when it does, the liquid expands and so des the material covering the thermometer. For the digital thermometer, it has less error because it already has a sensor inside it that determines the temperature of the substance.

Which of the following elements is stable? A. Boron, atomic number 5
B. Neon, atomic number 10
C. Fluorine, atomic number 9
D. Carbon, atomic number 6

Answers

Answer: Option (B) is the correct answer.

Explanation:

An atom is stable when it has completely filled orbitals. This means that K shell have 2 electrons, L shell have 8 electrons, M shell have 18 electrons and so on.

Therefore, electronic distribution of given elements will be as follows.

Boron has electronic configuration 2, 3.

Neon has electronic configuration 2, 8.

Fluorine has electronic configuration 2, 7.

Carbon has electronic configuration 2, 4.

Therefore, out of the given elements neon is stable.

The element that is stable among the options given is B. Neon, with atomic number 10.

Which is stable element?

Stability in the context of elements refers to having a filled outer electron shell, typically with eight electrons, known as an octet. Neon, a noble gas, has a complete octet with two electrons in the first shell and eight electrons in the second shell.

In contrast, elements like Boron (atomic number 5), Fluorine (atomic number 9), and Carbon (atomic number 6) do not have a complete octet in their outermost electron shells. They tend to form chemical bonds and engage in chemical reactions to achieve a stable electron configuration. Option B

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In the third period of the periodic table, sodium is followed by magnesium, aluminum, silicon, and phosphorus. Which of these elements has the smallest atomic size?

Answers

Answer:  (E)       Phosphorus

Explanation: PLATO

Answer:

E.

Explanation:

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