In 1911, Ernest Rutherford and his assistants Geiger and Marsden conducted an experiment in which they scattered alpha particles (nuclei of helium atoms) from thin sheets of gold. An alpha particle, having charge 2e and mass 6.64 10-27 kg, is a product of certain radioactive decays. The results of the experiment led Rutherford to the idea that most of an atom's mass is in a very small nucleus, with electrons in orbit around it. Assume an alpha particle, initially very far from a stationary gold nucleus, is fired with a velocity of 1.50 107 m/s directly toward the nucleus (charge 79e). What is the smallest distance between the alpha particle and the nucleus before the alpha particle reverses direction?

Answer:

It is the gravity of the angles that connect with the egg and the angles of it

Answer: A-B-C-E-G-K-H-I

Explanation:

Ok, we start at A.

16 pints = x gallons.

We know that:

1 pint = 0.125 al

then:

16pint = 16*(0.125gal) = 2 gal.

The second letter is B.

Now we have:

12,320 yd = X mi

And we know that:

1 mi = 1760 yd.

Then 12,320yd = (12,320/1760) mi = 7mi

the letter is C.

Now we have:

432 cups = X gals

and:

1 cup = 0.0625 gal

then 432 cups = 432*(0.0625 gal) = 27 gal.

The next letter is E.

Now we have:

1/4 ton = X pounds.

And 1 ton = 2000 pounds

then 1/4 ton = (1/4)*2000 pounds = 500 pounds

The next letter is G.

Now we have:

3.5 gal = X ounces.

and we know that:

1 gal = 128 oz

Then:

3.5 gal = 3.5*(128oz) = 448oz

The next letter is K.

Now we have:

1/2 day = x minutes.

and we know that:

1 day = 24*60 min = 1440 min

then 1/2 day = (1/2)*1440 min = 720 min.

The next letter is H.

Now we have:

360 in = x yd

And we know that:

1yd = 36 inches.

then 360 in = (360/36) = 10 yd.

The next letter is I

Now we have:

56 cups = x quarts.

and we know that;

1cup = 0.25 quart

then: 56 cups = 56*0.25 quart = 14

So here this ends.

Then the code is:

A-B-C-E-G-K-H-I

Answer:

8.57 m/s

Explanation:

let's list out available parameters:

Initial velocity, u = 20 m/s

Time = 15 - 1 = 14 s

Distance, s = 200 m

Final velocity = ?

We are assuming a uniformly accelerated motion.

Using one of the equations of motion

m/s

Final answer:

To stop just as the light turns green, the motorist needs to decelerate in a controlled manner. The effective time to cover the distance after seeing the red light is 14 seconds, disregarding the 1 second it takes to react and press the brakes. Therefore, as she reaches the traffic signal when it turns green, her speed is 0 m/s.

Explanation:

This situation can be approached using the concept of kinematics in Physics. To solve it, we need to consider total time and total distance traveled. The motorist is driving towards the traffic light, which is 200m away, and the light stays green for 15 seconds. However, since it takes her 1 second to step on the brakes, effectively, she has 14 seconds to travel to the light.

Since she starts braking the car, she begins to decelerate. While decelerating, time is the only determinant of the distance covered, not the speed. As she reaches the light, the speed would be zero regardless of the initial speed or distance if the deceleration is constant. So, when the light turns green, her speed will be 0 m/s.

Learn more about Deceleration here:

brainly.com/question/32899180

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