The distribution of the annual incomes of a group of middle management employees approximated a normal distribution with a mean of $37,200 and a standard deviation of $800. About 68% of the incomes lie between what two incomes

Answers

Answer 1
Answer:

Answer:

68% of the incomes lie between $36,400 and $38,000.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  $37,200

Standard Deviation, σ = $800

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Empirical rule:

  • Almost all the data lies within three standard deviation of mean for a normally distributed data.
  • About 68% of data lies within one standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within three standard deviation of mean.

Thus, 68% of data lies within one standard deviation.

\mu \pm \sigma\n=37200 \pm 800\n=(36400,38000)

Thus, 68% of the incomes lie between $36,400 and $38,000.


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An arena receives $1,700 per event for 12 concerts. If the costs for this sponsorship total $14,000, what is the profit margin for the concert sponsorship?

Answers

Answer:

total profit margin for all 12 concert is $6,400.

profit margin for all one concert is  $533.33

Step-by-step explanation:

Amount of money received for one event = $1700

Total no of concert = 12

Total money received for 12 event = Amount of money received for one event * Total no of concert

Total money received for 12 event  = $1700 *12 = $20,400

Total cost of sponsorship = $14,000

Profit margin is the difference money invested and money earned.

here total investment is $14,000

Total money earned is  $20,400

Therefore profit margin = money earned - total investment

= $20,400 -  $14,000 = $6,400

Therefore total profit margin for all 12 concert is $6,400.

However to calculate profit margin for one concert we can simply divide the total profit margin for all 12 concert by no of concert (i.e 12)

profit margin for one concert = total profit margin for all 12 concert/total no of concert  = $6,400/12 = $533.33

profit margin for all one concert is  $533.33

a family buys 6 airline tickets online. the family buys travel insurance that costs 18 per ticket. the total cost is 1,044

Answers

Answer:

936

Step-by-step explanation:

Therefore you multiply 6 by 18 = 6×18= 108

1,044 - 108 = 936

So therefore the total is 936

Final answer:

The cost of each ticket before insurance is $156. This is obtained by subtracting the total cost of the insurance from the total amount spent and then dividing by the number of tickets.

Explanation:

The subject of this question seems to be an exercise in elementary algebra. If a family buys 6 airline tickets online and also purchases travel insurance that costs $18 per ticket, then the amount spent on insurance alone is $18 * 6 = $108. We know that the total cost, including the tickets and the insurance, is $1,044. Therefore, to find out the cost of the tickets alone, we subtract the cost of the insurance from the total cost: $1,044 - $108 = $936, which will be the cost for the tickets alone. So, the cost of each ticket is $936 / 6 = $156. Therefore, each ticket cost $156 before insurance.

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A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?A:
A)
17 inches
B)
2.4 inches
o
2.9 inches
D)
3.1 inches

Answers

Answer:

B) 2.4 inches

Step-by-step explanation:

The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in one month you need to divide the total by the amount of months. 28.8/12 = 2.4

If h = 12 units and r = 4 units, what is the volume of the cone shown above? Use 3.14 for .

Answers

Answer:

≈ 201

Step-by-step explanation:

V= πr²h/3

V= 3.14*4²*12/3= 200.96 ≈ 201

The volume of the cone is 201.06 units³.

The volume of a cone is given by the formula:

Volume = (1/3) * π * r² * h

where r is the radius of the base and h is the height of the cone.

In this case, r = 4 units and h = 12 units. Using 3.14 for π, we can calculate the volume of the cone as follows:

Volume = (1/3) * 3.14 * 4² * 12

Volume = 201.06 units³

Therefore, the volume of the cone is 201.06 units³.

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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experience that 1%, 3%, and 2% of the products made by each machine, respectively, are defective. A finished product is randomly selected and found to be non-defective, what is the probability that it was made by machine B1?

Answers

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = (P(B|A)P(A))/(P(B)) = (P(B|A)P(A))/(P(B|A)P(A) + P(B|a)P(a))

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =(P(N|B1)P(B1))/(P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)) = ((0.297)(0.3))/((0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)) = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

Identify the exponent in the term –3x 2 . A. 3 B. x C. 2 D. minus sign (–)

Answers

Answer:

Correct option is:

C. 2

Step-by-step explanation:

We have to find the exponent in the term -3x²

An exponent refers to the number of times a number is multiplied by itself.

Here, x is multiplied to itself 2 times

i.e. x* x=x^2

Hence, exponent in the term -3x² is:

2

So, the correct option is:

C. 2