The density of mercury is 13.5 g/cm3g
/
c
m
3
.
Part A
Part complete
What is this value in kilograms per cubic meter?
1.35×104
kg/m3
k
g
/
m
3

Answers

Answer 1
Answer:

If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit, then the density of the mercury would be 1.35×10⁴ in the kilograms per cubic meter

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

By using the above formula for density

ρ = mass / volume

As given in the problem If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit then we have to convert its value into kilograms per cubic meter.

1000 grams  = 1 kilogram

1 gram = 1/1000 kilograms

           =1×10⁻³ kilograms

10⁶ cubic centimeter = 1 cubic meter

1  cubic centimeter = 1/10⁶  cubic meter

                                = 1× 10⁻⁶ cubic meter

Given the density of the mercury  13.5 g/cm³

13.5 g/cm³ =  13.5 ×10⁻³ kilograms / 1× 10⁻⁶ cubic meter

                   = 1.35×10⁴ kilograms / cubic meter

Thus, we converted the density of mercury is 13.5 g/cm³ into 1.35×10⁴ kilograms / cubic meter

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Answer 2
Answer:

Answer:

DO IY.T

Explanation:


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A heavy object falls with the acceleration as a light object during free fall. Why?

What type of energy does fresh vegetables have?

Answers

Well it's energy comes from the sun since the sun gives it sunlight to help it grow
lazer light energy lots of protion helps them too they have it all

I need help on #9 (it's side ways sorry...)

Answers

All of these are directly proportional to each other, meaning that if one goes up or down, they all do the same.
So if the temperature increases so does the heat. If the heat increases then so does the thermal energy. If the temperature goes up then so does the thermal energy. ETC...
Temperature-Amount of heat or coldness an item has measured in degrees. the object.
Heat- Given off from thermal energy.
Thermal energy- what is given off when energy is lost.
Law of Conservation of Energy- Energy can neither be created or destroyed, it can only be transformed from one form to another.

SQUA is a square. If side SQ has endpoints S(-2,8) and Q(4,10), find the perimeter to two decimal places?HURRY!!

Answers

Answer : The perimeter of square is, 25.28 unit.

Step-by-step explanation :

First we have to calculate the distance of SQ.

Using distance formula:

d=√((x_2-x_1)^2+(y_2-y_1)^2)

where,

d = distance between the two coordinates

x and y are the coordinates.

To calculate the distance of SQ:

d=√((x_2-x_1)^2+(y_2-y_1)^2)

d=√((4-(-2))^2+(10-8)^2)

d=√((36)^2+(4)^2)

d=√(40)

d=6.32

As we know that SQUA is a square that means all sides are equal.

So, Side SQ = Side QU = Side UA = Side SA = 6.32

Now we have to calculate the perimeter of the square.

Perimeter of square = Side SQ + Side QU + Side UA + Side SA

Perimeter of square = 6.32 + 6.32 + 6.32 + 6.32

Perimeter of square = 25.28 unit.

Therefore, the perimeter of square is, 25.28 unit.

Final answer:

To find the perimeter of the square, calculate the length of one side using the distance formula and multiply it by 4.

Explanation:

To find the perimeter of a square, we need to know the length of one side and multiply it by the number of sides. In this case, the length of one side can be found using the distance formula, which is the square root of the sum of the squared differences in the x-coordinates and y-coordinates of the endpoints of the side. So, the length of side SQ is:

Length of SQ = √((-2 - 4)2 + (8 - 10)2) = √((-6)2 + (-2)2) = √(36 + 4) = √40 ≈ 6.32

The perimeter of the square is found by multiplying the length of one side by 4, since a square has 4 equal sides:

Perimeter = 4 * Length of SQ = 4 * 6.32 = 25.28

Therefore, the perimeter of the square to two decimal places is 25.28 units.

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A light bulb converts electrical energy into light energy and also some thermal energy. The amount of electrical energy is 50 Joules before the conversions.

Answers

If the amount of electrical energy is 50 Joules before the conversions, then it would be 50 Joules after the conversion.

According to law of conservation of energy, we cannot create or destroy energy so it remains constant

Hope this helps!

Which property of table salt is also a property of other ionic compoundsA). Has a low melting point

B). Does not dissolve in water

C). Forms crystal structures

D). Does not conduct electricity

Answers

Answer:

The answer is D

Explanation:

Ionic compounds have high melting and boiling points.They can dissolve in water.And they donot form crystal structurs by dissolving.And they donot conduct electricity.

Final answer:

Table salt (an ionic compound) forms crystal structures, similar to other ionic compounds, due to the strong electrostatic forces holding its ions in a well-organized lattice. So the correct option is C.

Explanation:

The property of table salt, which is also a property of other ionic compounds, is that it forms crystal structures. Table salt, like all ionic solids, exhibits a crystalline structure because its ions are held together by strong electrostatic forces of attraction in a rigid and well-organized lattice. In contrast, ionic compounds typically have high melting points, dissolve in water, and can conduct electricity when dissolved or molten because ions are free to move, allowing for the flow of electric charge.

Learn more about the Properties of Ionic Compounds here:

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A train is accelerating at a rate of 2 km/hr/s.  If its initial velocity is 20 km/hr, what is its velocity after 30 seconds?

Answers

Here it is. *WARNING* VERY LONG ANSWER

________________________________________... 
11) If Galileo had dropped a 5.0 kg cannon ball to the ground from a height of 12 m, the change in PE of the cannon ball would have been product of mass(m),acceleration(g)and height(h) 

The change in PE =mgh=5*9.8*12=588 J 
______________________________________... 
12.) The 2000 Belmont Stakes winner, Commendable, ran the horse race at an average speed = v = 15.98 m/s. 

Commendable and jockey Pat Day had a combined mass =M= 550.0 kg, 

Their KE as they crossed the line=(1/2)Mv^2 

Their KE as they crossed the line=0.5*550*(15.98)^2 

Their KE as they crossed the line is 70224.11 J 

______________________________________... 
13)Brittany is changing the tire of her car on a steep hill of height =H= 20.0 m 

She trips and drops the spare tire of mass = m = 10.0 kg, 

The tire rolls down the hill with an intial speed = u = 2.00 m/s. 

The height of top of the next hill = h = 5.00 m 

Initial total mechanical energy =PE+KE=mgH+(1/2)mu^2 

Initial total mechanical energy =mgH+(1/2)mu^2 

Suppose the final speed at the top of second hill is v 

Final total mechanical energy =PE+KE=mgh+(1/2)mv^2 

As mechanical energy is conserved, 

Final total mechanical energy =Initial total mechanical energy 

mgh+(1/2)mv^2=mgH+(1/2)mu^2 

v = sq rt [u^2+2g(H-h)] 

v = sq rt [4+2*9.8(20-5)] 

v = sq rt 298 

v =17.2627 m/s 

The speed of the tire at the top of the next hill is 17.2627 m/s 
______________________________________... 
14.) A Mexican jumping bean jumps with the aid of a small worm that lives inside the bean. 

a.)The mass of bean = m = 2.0 g 

Height up to which the been jumps = h = 1.0 cm from hand 

Potential energy gained in reaching its highest point= mgh=1.96*10^-4 J or 1960 erg 

b.) The speed as the bean lands back in the palm of your hand =v=sq rt2gh =sqrt 0.196 =0.4427 m/s or 44.27 cm/s 
_____________________________ 
15.) A 500.-kg horse is standing at the top of a muddy hill on a rainy day. The hill is 100.0 m long with a vertical drop of 30.0 m. The pig slips and begins to slide down the hill. 

The pig's speed a the bottom of the hill = sq rt 2gh = sq rt 2*9.8*30 =sq rt 588 =24.249 m/s 
__________________________________ 
16.) While on the moon, the Apollo astronauts Neil Armstrong jumped up with an intitial speed 'u'of 1.51 m/s to a height 'h' of 0.700 m, 

The gravitational acceleration he experienced = u^2/2h = 2.2801 /(2*0.7) = 1.629 m/s^2 
______________________________________... 

EDIT 
1.) A train is accelerating at a rate = a = 2.0 km/hr/s. 

Acceleration 

Initial velocity = u = 20 km/hr, 

Velocity after 30 seconds = v = u + at 

Velocity after 30 seconds = v = 20 km/hr + 2 (km/hr/s)*30s = 

Velocity after 30 seconds = v = 20 km/hr + 60 km/hr = 80 km/ hr 

Velocity after 30 seconds = v = 80 km/hr=22.22 m/s 
_______________________________- 
2.) A runner achieves a velocity of 11.1 m/s 9 s after he begins. 

His acceleration = a =11.1/9=1.233 m/s^2 

Distance he covered = s = (1/2)at^2=49.95 m