MATHEMATICS HIGH SCHOOL

9. Find the diagonal of a square with perimeter 28 meters.

Answers

Answer 1

Answer:

Answer:

diagonal of square = d = 9.899

Step-by-step explanation:

let side of square = x

diagonal of square = d

perimeter = P = 28

4 * x = P

x = 28/7

x = 7

By using Pythagorean theorem we get

x^2 + x^2 = d^2

7^2 + 7^2 = d^2

d^2 = 98

d = sqrt(98)

diagonal of square = d = 9.899

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Plan 1 . A flat rate of $7 per month plus $2.50 per video viewed Plan 2. $4 per video viewed What type of functions model this situation? Explain how you know?

Answers

Answer:they are both linear because Their slopes are constant.

Step-by-step explanation:

Describe how math in middle school differs from
high school math class?

Answers

high school math classes are more advanced than middle school math classes

High school math classes are a higher difficulty level, but most of what you learned in middle school math classes is used. It’s best to remember what you learned because you will end up using it in high school.

Match the expressions 21/25 60% 13/20 84% 2/5 75% 65% 3/4 3/5

Answers

Answer:

21/25 ---> 84%

13/20 ---> 65%

3/5 ---> 60%

3/4 --->75%

2/5 ---> 40%

Find the area of the trapezoid at the right. the left side is 5cm, the the top is 6cm, the side is 5.4cm, and the bottom on the right is 2cm.

Answers

Answer:

To find the area of a trapezoid, we can use the formula:

Area = (1/2) × (sum of bases) × (height)

In this case, the bases are 6 cm and 2 cm, and the height is the distance between them, which we can find using the Pythagorean theorem:

height² = (side)² - (difference of bases/2)²

height² = 5.4² - (2-6/2)²

height² = 29.16 - 9

height² = 20.16

height = √20.16

height ≈ 4.49 cm

Now we can plug in these values to find the area:

Area = (1/2) × (6 + 2) × 4.49

Area = 4 × 4.49

Area = 17.96 cm²

Therefore, the area of the trapezoid is approximately 17.96 square centimeters.

Step-by-step explanation:

Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction if needed.

Answers

Answer:

30/34

Step-by-step explanation:

What is a situation in which you might locate points on a coordinate grid?

Answers

A situation could be when you have a y=axsquared+bx+c equation. You'd find the X, or vertex, by doing x=-b divided by 2•a. Then you'd plug in x and find y. Now you have a point you can plot. To find another, you can find the y-intercept by plughing in 0 for x and finding another y.

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