Phytoplankton are microscopic photosynthesizing organisms that typically live in the upper layers of the ocean. What trophic level do phytoplankton belong to?

Answers

Answer 1
Answer:

Answer:

Primary producers

Explanation:

Phytoplankton belong to the primary producers trophic level. Beings of the other levels gain energy from phytoplankton. Phytoplankton are also capable of transforming inorganic carbon into protoplasm.


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48dm3 of a gas has a mass of 262g how many moles is this? What is the Mr? What must this element be?

Answers

n=(V)/(V_(0))\n\nV=48dm^(3)\nV_(0)=22.4(dm^(3))/(mol)\n\nn=(48dm^(3))/(22.4(dm^(3))/(mol))\approx2mol\n\nn=(m)/(M_(r)) \ \ \ \Rightarrow \ \ \ M_(r)=(m)/(n)\n\nm=262g\nn=2mol\n\nM_(r)=(262g)/(2mol)=131(g)/(mol)

This element must be xenon.

Final answer:

The number of moles is 1.49 and the molar mass is 176.124 g/mol.

Explanation:

To determine the number of moles, we can use the formula:



moles = mass / molar mass



Given that the mass of the gas is 262g and the molar mass is 176.124 g/mol, we can substitute these values into the formula:



moles = 262g / 176.124 g/mol = 1.49 moles (rounded to two decimal places).



Therefore, the number of moles is 1.49. The molar mass of the compound is 176.124 g/mol. In order to determine what element this is, we would need more information about the compound.

Learn more about molar mass here:

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Leutium-176 has a half-life of 3.85 mc012-1.jpg 1010 years. After 1.155 mc012-2.jpg 1011 years, how much leutium-176 will remain from an original 16.8-g sample?2.10 g
3.00 g
5.56 g
8.40 g

Answers

Answer : The amount left of leutium-176 will be, 2.10 g

Solution :

First we have to calculate the rate constant, we use the formula :

k=(0.693)/(t_(1/2))

k=\frac{0.693}{3.85* 10^(10)\text{years}}

k=0.18* 10^(-10)\text{years}^(-1)

Now we have to calculate the amount left of the sample.

Expression for rate law for first order kinetics is given by :

t=(2.303)/(k)\log(a)/(a-x)

where,

k = rate constant  = 0.18* 10^(-10)\text{years}^(-1)

t = decay time  = 1.155* 10^(11)\text{ years}

a = initial amount of the sample = 16.8 g

a - x = amount left after decay process  = ?

Now put all the given values in above equation, we get

1.155* 10^(11)\text{years}=\frac{2.303}{0.18* 10^(-10)\text{years}^(-1)}\log(16.8)/(a-x)

a-x=2.10g

Therefore, the amount left of leutium-176 will be, 2.10 g

Answer:

A.

Explanation:

Why are the atomic masses of elements usually decimal numbers? Provide an answer using 3 – 4 sentences in your own words.

Answers

Explanation: An element does not exist alone in the nature. It exist in the form of isotopes of its own. Atomic mass of that element is the average atomic masses of the isotopes.

Average atomic mass of the element is defined as the sum of atomic masses of isotopes each multiplied with their respective natural fractional abundance.

Mathematically,

\text{Average atomic mass}=\sum_(i=1)^n\text{(atomic mass of an isotopes)}_i* \text {(fractional abundance)}_i

This is the reason, why an element does not have a whole number atomic mass, but exist in decimal numbers.


The atomic masses of elements are usually written in decimal numbers because they are non-terminating. The numbers usually are rounded to the nearest thousandths place. The atomic masses are more exact in decimal numbers.

Which of these changes produces the greatestincrease in entropy?
(1) CaCO3(s) --> CaO(s) + CO2(g)
(2) 2 Mg(s) + O2(g) --> 2 MgO(s)
(3) H2O(g) --> H2O(l)
(4) CO2(g) --> CO2(s)

Answers

Answer:

Was this correct? I am pretty sure it is since you are going from a solid to a gas in the first reaction.

Explanation:

(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas ** most entropy here

(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid

(3) H2O(g) --> H2O(l) gas to a liquid

(4) CO2(g) --> CO2(s)   gas to a solid

As temperature rises and a substance transforms from a solid to a liquid to a gas, entropy increases. Because they have the most flexibility to move, gases have the highest entropy values. Here the first reaction has high entropy. The correct option is 1.

The level of unpredictability in a system is known as entropy. The degree of randomness is highest when comparing the three forms of matter solid, liquid, and gas because the gas particles move freely.

(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas - most entropy here

(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid

(3) H2O(g) --> H2O(l) gas to a liquid

(4) CO2(g) --> CO2(s)   gas to a solid

Thus the correct option is 1.

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Describe the difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl. Which molecule contains a polar covalent bond and which molecule contains a nonpolar covalent bond? Explain your reasoning alongside describing the differences between the types of bonds.

Answers

Polar covalent bonds are between atoms with different electronegativities, whereas nonpolar covalent bonds are between atoms with the same electronegativity.

This means that HCl is a polar covalent bond, whereas H2 is a nonpolar covalent bond.

At standard pressure when NaCl is added to water,the solution will have a

Answers

Answer: lower freezing point and a higher boiling point than water

Explanation:

Addition of a non volatile solute leads to elevation in boiling point and depression in freezing point.

This increase in boiling point arises because particles of the non-volatile solute occupy the surface of solution due to which solvent particles can not escape out of the solution.  Hence, high amount of heat is required for the solute particles to escape out of the solution. Therefore, an increase in boiling point will occur.

Also as vapor pressure of solution becomes less, the freezing point gets depressed as freezing point is the temperature at which vapor pressure of solid becomes equal to the vapor pressure of solution.

Thus at standard pressure when NaCl is added to water,the solution will have a lower freezing point and a higher boiling point than water

lower freezing point and a higher boiling point than water 
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