Unsaturated hydrocarbons react very slowly with bromine. true false

Answers

Answer 1
Answer: False.Alkenes or alkynes (unsaturated hydrocarbons) are susceptible toelectrophilic attack by electrophiles, resulting in electrophilicaddition reactions.

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Acetone is a common solvent and has a density of 0.7899 g/mL. What volume of acetone, in mL, has a mass of 29.3 g?

Answers

V (volume), M (mass), D (Density)
We get: M = 29.3, and D = 0.7899, And V = ? 
The formula to find the volume is: 
V =  (M)/(D)
So we get:
V =  (29.3)/(0.7899)
V = 37.09

So, the volume of acetone when it have a mass of 29.3 grams is about 37.09 milliliters

Hope this Helps! :)

One mole of ice at 0°C is added to two moles of water at 50°C under a constant external pressure of 1 atm. This process is carried out in a thermally insulated vessel, such that no heat can escape the vessel. When equilibrium is reached, all of the ice has melted. Given: Δ H f u s i o n ∘ ( H 2 O a t 0 ∘ C ) = 6.01 k J m o l C p ( H 2 O , l i q u i d ) = 75 J m o l K a) (7 Points) Calculate the final temperature of the mixture (in °C). Show all work to support your answer.

Answers

Answer:

T2 = 29.79°C

Explanation:

Equliibrium signifies that heat loss = heat gained

Heat gained by Ice;

H = ML

Mass, M = Number of moles * Molar mass = 1 * 18 = 18g

l = 6.01 k J m o l = 334 J/g

C = 4.186 J/g

H =  18(334)

H = 6012

Heat lost by water

H = MCΔT

H = 18 * 4.186 * (50 - T2)

H = 3767.4 - 75.348T2

Since H = H, we have;

6012 = 3767.4 - 75.348T2

- 75.348T2 = 3767 - 6012

T2 = 2245 / 75.348

T2 = 29.79°C

The bonds in BaO are best described ascovalent, because valence electrons are shared
covalent, because valence electrons are transferred
ionic, because valence electrons are shared
ionic, because valence electrons are transferred

Answers

In order to determine whether a bond is ionic or covalent, you need to know whether or not it is completely composed of nonmetal atoms or both metal and nonmetal ions.

Barium is a metal and Oxygen is a nonmetal, therefore there is no possible way they could bond unless they were attracted to opposite charges. Specifically, only if Barium becomes a cation and Oxygen becomes an anion then could they bond.

Now cation and anion both have the word "ion" in them, so therefore it must be an ionic bond.

Now we need to know the definition of a bond. A bond is formed when two elements are joined together by sharing their valence electrons.

Therefore, your answer should be:

Ionic, because valence electrons are shared.

Hydrogen peroxide decomposes to give water and oxygen gas according to the equation below. If 3.0 moles of hydrogen peroxide decompose, what volume of oxygen gas is produced at a pressure of 1.0 atm and a temperature of 23 °C? 2 H2O2(l) → 2 H2O(l) + O2(g)

Answers

When 3.0 moles of hydrogen peroxide decompose at 1.0 atm and 23°C, approximately 36.78 liters of oxygen gas are produced according to the ideal gas law.

What volume of oxygen gas is produced at a pressure of 1.0 atm and a temperature of 23 °C?

To find the volume of oxygen gas produced when 3.0 moles of hydrogen peroxide decompose at a pressure of 1.0 atm and a temperature of 23°C, you can use the ideal gas law:

PV = nRT

Where:

- P is the pressure (1.0 atm).

- V is the volume (what we want to find).

- n is the number of moles of gas (1.5 moles of O2 since 1 mole of O2 is produced for every 2 moles of H2O2).

- R is the ideal gas constant (approximately 0.0821 L.atm/mol.K).

- T is the temperature in Kelvin (23°C needs to be converted to Kelvin, which is 296.15 K).

First, calculate the number of moles of O2 produced:

n = 3.0 moles of H2O2 * (1 mole of O2 / 2 moles of H2O2) = 1.5 moles of O2

Now, plug in the values into the ideal gas law and solve for V:

1.0 atm * V = 1.5 moles * 0.0821 L·atm/mol·K * 296.15 K

Now, calculate the volume:

V = (1.5 moles * 0.0821 L·atm/mol·K * 296.15 K) / 1.0 atm

Calculate the volume:

V ≈ 36.78 L

So, the volume of oxygen gas produced when 3.0 moles of hydrogen peroxide decompose at 1.0 atm and 23°C is approximately 36.78 liters.

Learn more on ideal gas law here;

brainly.com/question/27870704

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First you need to use stoichiometry to find how many moles of oxygen is produced from the reaction.  To do this you need to multiply the number of moles of hydrogen peroxide by the molar ratio which is 1/2 since 1 mole of O₂ is produced from 1 mole of H₂O₂.  3mol H₂O₂x(1mol O₂/2mol H₂O₂)=1.5mol O₂
you you need to you the ideal gas law (PV=nRT) to find the volume of gas produced. V=nRT/P
n=1.5mol
R=0.08206atmL/molK
T=23°C (turn that into 296K)
P=1atm
V=(1.5molx0.08206atmL/molK)/1atm
V=0.1231L

I hope this helps.

How many molecules of glucose are in a 2.0 mL of a 1.02 mM solution of glucose

Answers

One way of expressing concentration is by molarity. It is the amount of solute per unit volume of the solution. Usually, it takes the unit mol/L. The calculation for this problem is as follows:

1.02 mM = (1.02 mol / mL) (2.0 mL) = 2.04 mol

Thus, the solution has 2.04 mol of glucose.

Differentiate between atoms, elements, molecules and compounds

*URGENT

Answers

Atoms are the simpliest form of matter. But an atom can be classified as an element and an element can be presented various substance. An element can be oxygen, hydrogen and so on. The combination of two or more elements is a compound. A compound can be a molecule, same as the atom to element.