PHYSICS HIGH SCHOOL

An observer on the earth sees a spaceship approaching at 0.54c. The ship then launches an exploration vehicle that, according to the earth observer, approaches at 0.82c. What is the velocity of the exploration vehicle relative to the spaceship? Give your answer as a decimal fraction of c, i.e. a β factor.

Answers

Answer 1
Answer:

Answer:

Explanation:

Expression for relative velocity

= (v_1+v_2)/(1+(v_1v_2)/(c^2) )

= (.54 + .82 )c/ 1+ (.54 *.82)/(1)

= 1.36 c / 1.4428

= .94 c

β = .94

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An electromagnetic wave is composed of electrical and magnetic energy. true or false
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Any formation in which groundwater Rises on its own under pressure is a

Answers

The answer is an artesian well. Any formation in which groundwater rises on its own under pressure is an artesian well. An artesian well is simply a well that doesn't require any effort to pump the water up to the surface in which this occur when there's enough pressure in the aquifer. 

Water is a nonpolar molecule true or false​

Answers

Answer:

Water is non-polar molecule False

Water is polar molecule because the electronegativity of Oxygen is much greater than electronegativity of hydrogen and it has also a bend shape that is why it is polar molecule.

Explanation:

I hope this will help you :)

False. Water is a polar molecule.

About water

Water (H2O) consists of two hydrogen atoms and one oxygen atom. The oxygen atom has a higher electronegativity, meaning it attracts electrons more strongly than hydrogen.

As a result, the shared electrons in the covalent bonds between hydrogen and oxygen are pulled closer to the oxygen atom, creating an uneven distribution of charge.

This leads to a partial negative charge (δ-) on the oxygen atom and partial positive charges (δ+) on the hydrogen atoms, making water a polar molecule.

More on polarity of water can be found here: brainly.com/question/30530422

#SPJ6

Ocean waves are examples of:
transverse waves
longitudinal waves
circular waves

Answers

Circular is correct.
ocean waves could be the example of both circular and transverse waves. sometimes, ocean waves could move in an up and down (~~~~~~~) wave. sometimes the ocean waves could move in circular waves, [((((O))))] so it depends on the movement. I would mostly choose transverse waves, though, since most of the time, 'ocean waves' are meant to be such kind of movement [~~~~~~~~~~~~~~].

What does the atomic number of an element represent? Question 21 options: A. the number of protons in an atom B. the number of neutrons in an atom the mass of an atom C. the total number of protons, neutrons, and electrons in an atom D. the order in which the element was discovered

Answers

Answer:

A. the number of protons in an atom

Explanation:

The atomic number (also known as the proton number) is the number of protons found in the nucleus of an atom.

Answer:

A. the number of protons in an atom

Explanation:

on a small planet, an astronaut uses a vertical force of 175 newton to lift an 87.5 kg boulder at constant velocity to height of 0.350 meter above the planet's surface. What is the magnitude of the gravitation field strenght on the surface of the planet

Answers


                                                         Weight =  (mass)  x  (gravity)

                                                          175 N  =  (87.5 kg) x (gravity)

Divide each side by  87.5 kg :      Gravity = (175 N) / (87.5 kg)

                                                                      =  2 m/s²

We don't care how far he lifted it.

A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launches a horizontal shot that lands in the hole on the fly. The gallery erupts in cheers.

Answers

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_(o)cos \theta t----------------------(1)

y=y_(o)+V_(o) sin \theta t - (1)/(2)gt^(2)---------(2)

V=V_(o)-gt ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

V_(o) is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

y_(o) is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

t=\sqrt{(2 y_(o))/(g)}

t=\sqrt{(2 (12.5 m))/(9.8 m/s^(2))}

t=1.597s

Substituting (6) in (1):

67.1 =V_(o) cos(0\°) 1.597-------------------(4)

Step 2:  Finding V_(o):

From equation(4)

67.1 =V_(o)(1) 1.597

V_0 = (6.71)/(1.597)

V_(o)=42.01 m/s (8)  

Substituting V_(o) in (3):

V=42.01 -(9.8)(1.597)

v =42 .01 - 15.3566  

V=26.359 m/s
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