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You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measurements are listed below:53 47 51 54 43 39 61 57 55 46 44 43

If you doubled every measurement in this dataset (e.g., 106, 94, 102, ...), what would the new IQR equal? (Think about the SD too!)

Answers

Answer 1
Answer:

Answer:

The new IQR is 22.    

Step-by-step explanation:

We are given the following data of  length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

IQR = Q_3 - Q_1\nQ_3 = \text{upper median},\nQ_1 = \text{ lower median}

Median:\n\text{If n is odd, then}\n\nMedian = \displaystyle(n+1)/(2)th ~term \n\n\text{If n is even, then}\n\nMedian = \displaystyle((n)/(2)th~term + ((n)/(2)+1)th~term)/(2)  

Median ==(6^(th)+7^(th))/(2) (47+51)/(2) = 49

Q_1 =(3^(rd)+4^(th))/(2) = (43 + 44)/(2) = 43.5\n\nQ_3 =(9^(th)+10^(th))/(2)= (54 + 55)/(2) = 54.5

IQR = Q_3 -Q_1 =54.5-43.5= 11

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

2* \text{IQR}\n=2\TIMES 11\n=22

Thus, the new IQR is 22.

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So i just learned multiplying negative number and i have to put them on a number line pls help here is the Qustion
-2 x 5 =
please explain

Answers

Answer:

-10

Step-by-step explanation:

Alright, let me explain negative multiplcation.

A negative number multiplied by another negative number becomes a positive number.  But a negative number multiplied by a positive number is still negative. Every pair of 2 negatives become positive. This is important. Make sure to remember that.

That's it! If you need more help then reach out to your teacher. I'm sure that they will be more than happy to help!

Hope this helped!  :)

Answer:

the awnswer is -10

Step-by-step explanation:

Remember a negative times a negative is the only time the answer will be positive. When a negative is multiplied by a positive it will always be negative.

ex:

-2 x 5

since this is a negative and a positive the answer will be negative. knowing that just multiply 2x5=10 then add the negative -10.

Find the slope using the formula.
(4, 19) and (2, 11)

Answers

Answer:

m=4

General Formulas and Concepts:

Pre-Algebra

  • Order of Operations: BPEMDAS

Algebra I

  • Slope Formula: m=(y_2-y_1)/(x_2-x_1)

Step-by-step explanation:

Step 1: Define

(4, 19)

(2, 11)

Step 2: Find slope m

  1. Substitute:                    m=(11-19)/(2-4)
  2. Subtract:                       m=(-8)/(-2)
  3. Divide:                          m=4

Question 2 Unsaved
A square has a side length of 2x+1. If the perimeter is 28, what is x?

Answers

bearing in mind that a square has 4 equal sides, and the perimeter is the sum of all sides.

Which of the following expression are equivalent to 2x+4 select three answers?A.6x
B.1/3(18x)
c.1/3(6x+12)
d.2/3(3x+6)
e.2(x+4)
f.4(1/2x+1)

Answers

Answer:

A.6x

Step-by-step explanation:

hope i helped!! ...............

In a sample of 1200 U.S.​ adults, 191 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S.​ adults, complete parts​ (a) through​ (d). ​Required:a. Find the probability that both adults dine out more than once per week. b. Find the probability that neither adult dines out more than once per week. c. Find the probability that at least one of the two adults dines out more than once per week. d. Which of the events can be considered unusual? Explain.

Answers

Answer:

a) The probability that both adults dine out more than once per week = 0.0253

b) The probability that neither adult dines out more than once per week = 0.7069

c) The probability that at least one of the two adults dines out more than once per week = 0.2931

d) Of the three events described, the event that can be considered unusual because of its low probability of occurring, 0.0253 (2.53%), is the event that the two randomly selected adults both dine out more than once per week.

Step-by-step explanation:

In a sample of 1200 U.S. adults, 191 dine out at a restaurant more than once per week.

Assuming this sample.is a random sample and is representative of the proportion of all U.S. adults, the probability of a randomly picked U.S. adult dining out at a restaurant more than once per week = (191/1200) = 0.1591666667 = 0.1592

Now, assuming this probability per person is independent of each other.

Two adults are picked at random from the entire population of U.S. adults, with no replacement, thereby making sure these two are picked at absolute random.

a) The probability that both adults dine out more than once per week.

Probability that adult A dines out more than once per week = P(A) = 0.1592

Probability that adult B dines out more than once per week = P(B) = 0.1592

Probability that adult A and adult B dine out more than once per week = P(A n B)

= P(A) × P(B) (since the probability for each person is independent of the other person)

= 0.1592 × 0.1592

= 0.02534464 = 0.0253 to 4 d.p.

b) The probability that neither adult dines out more than once per week.

Probability that adult A dines out more than once per week = P(A) = 0.1592

Probability that adult A does NOT dine out more than once per week = P(A') = 1 - P(A) = 1 - 0.1592 = 0.8408

Probability that adult B dines out more than once per week = P(B) = 0.1592

Probability that adult B does NOT dine out more than once per week = P(B') = 1 - P(B) = 1 - 0.1592 = 0.8408

Probability that neither adult dines out more than once per week = P(A' n B')

= P(A') × P(B')

= 0.8408 × 0.8408

= 0.70694464 = 0.7069 to 4 d.p.

c) The probability that at least one of the two adults dines out more than once per week.

Probability that adult A dines out more than once per week = P(A) = 0.1592

Probability that adult A does NOT dine out more than once per week = P(A') = 1 - P(A) = 1 - 0.1592 = 0.8408

Probability that adult B dines out more than once per week = P(B) = 0.1592

Probability that adult B does NOT dine out more than once per week = P(B') = 1 - P(B) = 1 - 0.1592 = 0.8408

The probability that at least one of the two adults dines out more than once per week

= P(A n B') + P(A' n B) + P(A n B)

= [P(A) × P(B')] + [P(A') × P(B)] + [P(A) × P(B)]

= (0.1592 × 0.8408) + (0.8408 × 0.1592) + (0.1592 × 0.1592)

= 0.13385536 + 0.13385536 + 0.02534464

= 0.29305536 = 0.2931 to 4 d.p.

d) Which of the events can be considered unusual? Explain.

The event that can be considered as unusual is the event that has very low probabilities of occurring, probabilities of values less than 5% (0.05).

And of the three events described, the event that can be considered unusual because of its low probability of occurring, 0.0253 (2.53%), is the event that the two randomly selected adults both dine out more than once per week.

Hope this Helps!!!

An investigative bureau uses a laboratory method to match the lead in a bullet found at a crime scene with unexpended lead cartridges found in the possession of a suspect. The value of this evidence depends on the chance of a false positive positive that is the probability that the bureau finds a match given that the lead at the crime scene and the lead in the possession of the suspect are actually from two differant melts or sources. To estimate the false positive rate the bureau collected 1851 bullets that the agency was confident all came from differant melts. The using its established ctireria the bureau examined every possible pair of bullets and found 658 matches. Use this info to to compute the chance of a false positive.

Answers

Answer:

Step-by-step explanation:

Given that, we have 1851 bullets that we KNOW are NOT MATCHES of one another. One by one they examine two bullets at a time.

So, there are 1851 bullets but each time we choose 2.

We have, N choose K = N! / K! (N-k)!

Here, N = 1851 and K = 2

Therefore, 1851 choose 2 = 1851! / 2! (1851-2)!

                                         = 1851! / 2! * 1849!

                                         = 1712175 Possible Combinations

Out of these 653 are false positive.

The chance of getting false positive is = 658 / 1712175

                                                            = 0.000384

                                                           = 0.0384 %

Therefore, The correct option is

The chance of false positive is 0.0384% Because this probability is sufficiently small (< or = 1%) There is high confidence in the agency's forensic evidence.
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