CHEMISTRY MIDDLE SCHOOL

6. What is SEAgel?a lightweight foam insulation
a skin conditioner made from seaweed
a semi-liquid semiconductor

Answers

Answer 1

Answer: The answer that you are looking for would be a

Answer 2

Answer:

Answer:

a lightweight foam insulation

Explanation:

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The energy for protein synthesis is generated by the _____. A. Golgi body

B. mitochondria

C. rough ER

D. ribosome

Answers

Answer:

b. mitochondria

Explanation:

Most of the ATP produced in the cells, come from the mitochondria, or even in the cytoplasm. In the case of the protein synthesis, since the process starts inside the nucleus of the cell and ends in the cytoplasm, the energy used during the process are obtained mainly from the mitochondria.

The answer is B. mitochondria

What is an object with a very high resistance classified as?

Answers

If the resistance is electrical, then that substance is an 'insulator'.

Does lead rust? help

Answers

No it doesn't lead oxidizes

Lead oxidizes.
no
Nope, cant rust as lead like copper /brass /bronze /muntz metals are non ferrous thus NO rusting is possible
PLEASE HIT TANKS

10 compounds that use the following elements

Answers

Sodium Hydroxide: NaHO

Calcium Chloride: CaCl2

Methane: CH4

Ethanol: C2H5OH

Calcium Sulfate: CaSO4

Calcium Nitrate: Ca(NO3)2

Carbon Monoxide: CO

Ammonia: NH3

Water: H2O

Carbon Dioxide: CO2

3. For the following reaction, calculate how many grams of each product are formed when 4.05 gof water is used.
2 H2O → 2 H2 + O2

Answers

Answer:

$\large \boxed{\text{0.453 g of H$_(2)$; 3.60 g of O$_(2)$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

MM: 2.016 32.00

2H₂O ⟶ 2H₂ + O₂

m/g: 4.05

1. Mass of hydrogen

(a) Moles of H₂O

$\text{Moles of H$_(2)$O} = \text{4.05 g H$_(2)$O}* \frac{\text{1 mol H$_(2)$O}}{\text{18.02 g H$_(2)$O }}= \text{0.2248 mol H$_(2)$O}$

(b) Moles of H₂

$\text{Moles of H$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{2 mol H$_(2)$}}{\text{2 mol H$_(2)$O }} = \text{0.2248 mol H$_(2)$}$

(c) Mass of H₂

$\text{Mass of H$_(2)$} =\text{0.2248 mol H$_(2)$} * \frac{\text{2.016 g H$_(2)$}}{\text{1 mol H$_(2)$}} = \textbf{0.453 g H$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g}}$ of H$_(2)$}$

2. Mass of oxygen

(a) Moles of O₂

$\text{Moles of O$_(2)$} = \text{0.2248 mol H$_(2)$O } * \frac{\text{1 mol O$_(2)$}}{\text{2 mol H$_(2)$O}} = \text{0.1124 mol O$_(2)$}$

(b) Mass of O₂

$\text{Mass of O$_(2)$} =\text{0.1124 mol O$_(2)$} * \frac{\text{32.00 g O$_(2)$}}{\text{1 mol O$_(2)$}} = \textbf{3.60 g O$_(2)$}\n\n\text{The reaction produces $\large \boxed{\textbf{0.453 g of H$_(2)$ and 3.60 g of O$_(2)$}}$}$

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