Which of the following is the solution to 9|x+4|>54 ?

Answers

Answer 1
Answer:

Answer:

x < -10, x > 2

Step-by-step explanation:

9|x+4| > 54

|x+4| > 6

Split the absolute value into two equation, positive and negative.

1.)POSITIVE

x+4 > 6

x > 2

2.)NEGATIVE

-(x+4) > 6

-x - 4 > 6

-x > 10

x < -10

Answer 2
Answer:

Answer:

\large\boxed{x<-10\ \vee\ x>2\to x\in(-\infty,\ -10)\ \cup\ (2,\ \infty)}

Step-by-step explanation:

9|x+4|>54\qquad\text{divide both sides by 9}\n\n(9|x+4|)/(9)>(54)/(9)\n\n|x+4|>6\iff x+4>6\ \vee\ x+4<-6\n\nx+4>6\qquad\text{subtract 4 from both sides}\n\nx+4-4>6-4\n\nx>2\n\nx+4<-6\qquad\text{subtract 4 from both sides}\n\nx+4-4<-6-4\n\nx<-10


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If 3/7 of a pizza is eaten for lunch and 2/5 is eaten for dinner , how much of the pizza is eatten ?

Answers

29/35 of the pizza was eaten
3/7 + 2/5 = 29/35 Is the answer

1. Renting a bicycle costs $30 for the first day and $10 for each additional day.a. Write an equation in simplified form to find the total cost C for a bike rental ithe number of days d it was rented.b. Find the cost of renting a bike for 5 days.Answer:

Answers

Part a:  30+10d  That is your equation.  30 for the start and 10 more for each additional day.
Part b:  So there are 4 additional days. Let's fill in the equation and solve.
30+10*4
30+40
$70
The answer is $70

b) Your sister says that the angles ∠DCA and ∠BCA are supplementary angles. Is she correct? Explain your reasoning. (1 point)

Answers

Answer:

She is incorrect.

Step-by-step explanation:

ABCD is a quadrilateral. Angle C measures less than 180 degrees. The sum of the measures of two supplementary angles equals 180 degrees. The sum of the measures of angles DCA and BCA equals the measure of angle C, but angle C measures less than 180 degrees, so the angles are not supplementary.

Answer:

incorrect

Step-by-step explanation:

Sin 2x=check all that apply
A. 2sin x cos x
B. 1-2 sin^2 x
C. 2cos x sin x
D. 2sin x +2cos x

Answers

Answer:

A,C

Step-by-step explanation:

sin 2x=sin (x+x)=sinx cos x+cos x sin x=2 sin x cos x

or =2 cos x sin x

[sinx cox=cos x sin x ]

The edge of one cube is 4 m shorter than the edge of a second cube. The volumes of the two cubes differ by 1216 m^3. Find the edge of the smaller cube.

Answers

Volume of cube, V = edge^3
Let edge of cube#1 = (x-4) m, therefore volume of cube#1, v1 = (x-4)^3 m
Let edge of cube#2 = x m, therefore volume of cube#2, v2 = x^3 m
Diff. in volume (in m) = 1216 = v2-v1 = [ x^3 - (x-4)^3 ] 
= x^3 - [(x-4)(x-4)(x-4)]
= x^3  - [x^2 - 8x +16(x - 4)]
 x^3 - [ x^3 - 12x^2 + 48x - 64 ]
= 12x^2 - 48x + 64
= 4 (3x^2 - 12x + 16)
Therefore 4 (3^2 - 12x + 16) = 1216
3x^2 - 12x + 16 = 1216/4 = 304
3x^2 - 12x - 288 = 0
3 (x^2 - 4x - 96) = 0
(x^2 - 4x - 96) = 0
(x - 12) (x + 8) =0
(x-12) = 0
Therefore x = 12 m 
Edge of cube#2 = x m = 12m
Edge of cube#1 = (x-4) m = 8m
a- the\ edge\ of\ the\ smaller\ cube\ \ \ \wedge\ \ \ a>0\nV_a-the\ volume\ of\ the\ smaller\ cube\ \ \ \Rightarrow\ \ \ V_a=a^3\n \n(a+4)^3-a^3=1216\ \ \ \wedge\ \ \ (x+y)^3=x^3+3x^2\cdot y+3x\cdot y^2+y^3\n \na^3+3a^2\cdot 4+3a\cdot 4^2+4^3-a^3=1216\n \n12a^2+48a+64-1216=0\ \ \ \Rightarrow\ \ \ 12a^2+48a-1152=0\ /:12\n \na^2-4a-96=0\ \ \ \Rightarrow\ \ \ \Delta=(-4)^2-4\cdot 1\cdot(-96)=16+384=400\n \n √(\Delta) =20\n \na_1= (4-20)/(2\cdot1) =-8<0,\ \ \ a_2= (4+20)/(2\cdot1) =12>0

Ans.\ The\ edge\ of\ the\ smaller\ cube=12\ m

The sum of two numbers is 38. The greater number is 5 more than twice the lesser number. What is the greater of the two numbers?

Answers

Have the first number be x and the other number be y.

Write the first equation: The sum is 38:

x+y=38

Then the second equation: x is 5 more than than 2y:

x=2y+5

Take the first equation and make it y=38-x

Then substitute it in for the 2nd equation to find x:

x=2(38-x)+5

x=76-2x+5

3x=81

x=27

Then substitute that into the 1st equation to find y:

(27)+y=38

y=11

The first number (x) is greater than the second number (y) because 27 is greater than 11