How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude E = 46.0 N/C if the dipole moment has a magnitude of p = 3.02 × 10−25 C·m and the initial angle is 64°?

Answers

Answer 1

Answer:

Answer:

$W=1.22*10^(-23)J$

Explanation:

Torque and energy of an electric dipole in an electric field we find:

$W=U(\alpha_(o)+\pi )-U(\alpha_(o) )=-pE(cos(\alpha_(o)+\pi )-cos(\alpha_(o) ))\nW=2pECos\alpha_(o)\n W=2(3.02*10^(-25)C.m )(46.oN/C)Cos64\nW=1.22*10^(-23)J$

Answer 2

Answer:

Final answer:

The work required to turn an electric dipole 180° in a uniform electric field is -4.89 × 10^-24 J.

Explanation:

To calculate the work required to turn an electric dipole 180° in a uniform electric field, we can use the formula:

W = -pE(1 - cosθ)

where W is the work done, p is the dipole moment, E is the electric field strength, and θ is the angle between the dipole moment and the electric field.

Plugging in the given values:

W = - (3.02 × 10-25 C·m)(46.0 N/C)(1 - cos(180° - 64°))

Simplifying the equation gives the work done to be -4.89 × 10-24 J.

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B.
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Answer:

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Explanation:

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Answers

Answer;

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Explanation;

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A graduated cylinder has 20 ml (cm3) of water placed in it. An irregularly shaped rock is then dropped in the graduated cylinder and the volume of the rock and water in the cylinder now reads 30 ml (cm3). The mass of the rock dropped into the graduated cylinder is 23 grams.a.) Find the volume of the rock dropped into the graduated cylinder.
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Answers

A) Volume = displacement
Therefore the rock has a volume of 10mL
B) density = Mass/ Volume
Therefore density = 23/10 = 2.3 per unit volume

Final answer:

The volume of the rock dropped into the graduated cylinder is 10 ml. The density of the rock is 2.3 g/ml.

Explanation:

We first determine the volume of the rock dropped into the graduated cylinder. The initial volume of water in the cylinder is 20 ml, and after placing the rock, the total volume increases to 30 ml. Therefore, the volume of the rock is the total volume minus the initial volume of the water, which is 30 ml - 20 ml = 10 ml.

Next, we find the density of the rock. The formula for density is mass/volume. Given that the mass of the rock is 23 grams and the volume is 10 ml, the density of the rock would be mass/volume = 23 grams / 10 ml = 2.3 g/ml.

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Answers

Answer:

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Explanation:

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Answers

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Explanation:

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