An airplane pilot fell 370 m after jumping without his parachute opening. He landed in a snowbank, creating a crater 1.5 m deep, but survived with only minor injuries. Assume that the pilot's mass was 84 kg and his terminal velocity was 50 m/s.estimate

Answers

Answer 1

Answer:

Answer:

he ded

Step-by-step explanation:

\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \tohe no alive because ⇆ω⇆π⊂∴∨α∈\neq \lim_{n \to \infty} a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta x_{12 \lim_{n \to $\neq \lim_(n \to \infty) a_n \pi \left \{ {{y=2} \atop {x=2}} \right. \leq \neq \beta \beta \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \geq \leq \leq \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \lim_(n \to \infty) a_n \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\n4&5&6\n7&8&9\end{array}\right] \beta x_{12 \lim_{n \to$

Related Questions

Rewrite in simplest radical form x^5/6 x^1/6 . Show each step of your process.
If gross pay increases by $500, total employee benefits increase by $200 and total job expenses decrease by $300, then total employment compensation
help ! Find the volume of cylinder with a diameter of 8 inches and a height that is three times the radius. Use 3.14 for pi and round your answer to the nearest hundredth.( only numerical answers ! )
Because a square is a kite, it must have
What is the perimeter of a rectangle 33 sq m by 3 m

Which point is a solution of x + 2y ≤ 4?(2, 4)

(1, 1)

(3, 5)

(-1, 5)

Answers

Answer:

The point that is a solution of x + 2y ≤ 4, is (1,1)

Step-by-step explanation:

Given x + 2y ≤ 4, to teste if a point is a solution of the inequation you have to replace each par of values in the inequation and see the result.

So,

(2,4) ⇒ 2 + 2·4 ≤ 4 ⇒ 8 ≤ 4, this is not correct.

(1,1) ⇒ 1 + 2·1 ≤ 4 ⇒ 3 ≤ 4, is correct.

(3,5) ⇒ 3 + 2·5 ≤ 4 ⇒ 13 ≤ 4, this is not correct.

(-1,5) ⇒ -1 + 2·5 ≤ 4 ⇒ 9 ≤ 4, this is not correct.

Summarizing the only point that is solution of x + 2y ≤ 4, is (1,1)

(1,1) because x + 2y <4
=1 + 2(1)
= 3 which is less than 4

Solve for x. (Round to the nearest thousandth.)
3x - 8 = 15

Answers

Answer:x = 7.667

Step-by-step explanation:

3x - 8 = 15

+ 8 = 23

3x = 23

divide 3 by 3 and 23 so you get x by itself

answer = 7.667

Answer:

x = 7.667

Step-by-step explanation:

3x - 8 = 15 (Rearrange expression)

-8 - 15 = -3x (Combine like terms)

-23 = -3x (Divide)

x = 7.667

What is 7/8 closest to

Answers

Answer:

Step-by-step explanation:

The question seems incomplete so rounding to the nearest whole number I’m guessing your answer is 1

E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best charges a flat rate of $25 per month and $5.95 for each pay per view. Using the given equations, how many pay per views will generate equal monthly bills from the two companies?

Answers

E-Z View: 40 + 4.95x
View the best: 25 + 5.95x

Equal monthly bills:

40 + 4.95x = 25 + 5.95x

5.95x - 4.95x = 40 - 25

x = 15

Answer: 15

Final answer:

The number of pay-per-view movies that would generate an equal monthly bill from both E-Z View cable company and View the Best company is 15 movies. This is found by setting up and solving a linear equation based on the monthly charges of each company.

Explanation:

This question is about using linear equations to solve a real-world problem. Let's say 'x' is the number of pay-per-view movies. Therefore, we can form two equations:

E-Z View cable company: 40 + 4.95x = monthly cost
View the Best company: 25 + 5.95x = monthly cost.

To find the number of pay-per-view movies that would make the two monthly costs equal, set the two equations equal to each other and solve for x.

40 + 4.95x = 25 + 5.95x
Subtract 4.95x from both sides: 15 = 1x
So, '15' pay-per-view movies would generate equal monthly bills from the two companies.

Learn more about Linear Equations here:

brainly.com/question/32634451

#SPJ11

Make x the subject of the formula $r = \sqrt{ (ax - p)/(q + bx) }$

Answers

Answer:

$\boxed{x = \frac{p + q {r}^(2) }{a - b {r}^(2) } }$

Step-by-step explanation:

$Solve \: for \: x: \n = > r = \sqrt{ (ax - p)/(q + bx) } \n \n </p><p>r = \sqrt{ (ax - p)/(q + bx) } \: is \: equivalent \: to \: \sqrt{ (ax - p)/(q + bx) } = r :\n = > \sqrt{ (ax - p)/(q + bx) } = r \n \n Raise \: both \: sides \: to \: the \: power \: of \: two: \n = > (ax - p)/(q + bx) = {r}^(2) \n \n Multiply \: both \: sides \: by \: (q + b x): \n = > ax - p = {r}^(2) (q + bx) \n \n Expand \: out \: terms \: of \: the \: right \: hand \: side: \n = > ax - p = q {r}^(2) + b {r}^(2)x \n \n Subtract \: b {r}^(2)x - p \: from \: both \: sides: \n = > x(a - b {r}^(2) ) = p + q {r}^(2) \n \n Divide \: both \: sides \: by \: a - b {r}^(2) : \n = > x = \frac{p + q {r}^(2) }{a - b {r}^(2) }$

Sam rotated parallelogram ABCD 90° clockwise around the origin. If angle A is 130° and angle B is 50°, what is the degree measurement of angle A'?

Answers

Answer-

The measurement of angle A' will be 130° .

Solution-

Transformations like - rotations, reflections, and translations are isometric. That means that these transformations do not change the size of the figure. If the size and shape of the figure is not changed, then the figures are congruent.

It doesn't matter the order or how much degree of rotation has taken place, the final image will be congruent to the original image.

So, even after the rotation of 90° clockwise around the origin, the measurement of angle A will be 130° and so do all the rest of the angles.

Answer:

B, 130 degrees.

Step-by-step explanation:

Other Questions

Solve the conjunction and describe the solution set. -5 ≤ 3m + 1 < 4 A: m ≥ -2 and m < 1 B: m ≤ -2 or m > 1 C m ≥ -4/3 and m < 5/3 D: m ≥ - 4/3 or m < 5/3

Groucho, Harpo, Chico, Zeppo, and Gummo have won 2 tickets to the opera. They will randomly choose which two of them have to attend. How many different 2-person groups are possible?

Evaluate the expresson when n=8 The product of one fourth and a number increased by 3

The formula P = 2L + 2w represents the perimeter of a rectangle. In this formula,L is the length of the rectangle and w is the width. Solve the formula for L. Find the length when the width is 4 meters and the perimeter is 36 meters.