CHEMISTRY COLLEGE

Consider the following reaction: Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)If you react an excess of Pb(NO3)2with 26.3 g of NaCl, and you isolate 52.1 g of PbCl2, what is your percent yield?

Answers

Answer 1
Answer:

Answer:

\large \boxed{84.7 \, \%}

Explanation:

Mᵣ:                          58.44      278.11

           Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ + 2NaNO₃

m/g:                         26.3

1. Moles of NaCl

\text{Moles of NaCl} = \text{26.3 g NaCl} * \frac{\text{1 mol NaCl}}{\text{58.44 g NaCl}} = \text{0.4505 mol NaCl}

(b) Moles of PbCl₂

\text{Moles of PbCl${_2}$} = \text{0.4505 mol NaCl} * \frac{\text{1 mol PbCl${_2}$}}{\text{2 mol NaCl}} = \text{0.2253 mol PbCl${_2}$}

(c) Theoretical yield of PbCl₂

\text{Mass of PbCl${_2}$} = \text{0.2253 mol PbCl${_2}$} * \frac{\text{278.11 g PbCl${_2}$}}{\text{1 mol PbCl${_2}$}} = \text{61.52 g PbCl${_2}$}

(d) Percent yield

\text{Percent yield} = \frac{\text{ actual yield}}{\text{ theoretical yield}} * 100 \,\% = \frac{\text{52.1 g}}{\text{61.52 g}} * 100 \, \% = \mathbf{84.7 \,\%}\n\n\text{The percent yield is $\large \boxed{\mathbf{84.7 \, \% }}$}

Related Questions

the hydrogen gas generated when calcium metal reacts with water is collected over water at 20 degrees C. The volume of the gas is 641 mL and the pressure is 988mmHg. What is the mass in grams of the hydrogen gas obtained? The vapor pressure of water at 20 degrees C is 17.54 mmHg.
A geochemist in the field takes a 13.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 16.° C, and caps the sample carefully. Back in the lab, the geochemist filters the sample and then evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.143 gRequired:Using only the information above, can you calculate the solubility of X in water at 15°C ? If you said yes, calculate it.
All voltmeters have two probes attached to make a measurement explain why you cannot make a voltmeter with a single probe to measure the voltage of a wire
What will the pressure of the gas be if the temperature rises to 87°C?A. 60 kPaB. 161 kPaC. 16 kPaD. 41 kPa
For the reaction, calculate how many moles of the product form when 2.73 mol of h2 completely reacts. assume that there is more than enough of the other reactant. h2(g)+cl2(g)→2hcl(g)

When a solution of an acid reacts with a solution of a base, hydrogen ions react with hydroxide ions to form?

Answers

water
hydrogen ions+hydroxide=water
which can be verified by dark reaction of photosynthesis

Answer:

water and salt

Explanation:

In the FLVS salt will be your answer but technaically when a acid reacts with a base it can create salt and water

For the combustion reaction of C9H12 in O2: how many moles of O2 is required to react with 0.67 mol C9H12?

Answers

Answer:

8.0 mol O₂

Explanation:

Let's consider the complete combustion reaction of C₉H₁₂.

C₉H₁₂ + 12 O₂ → 9 CO₂ + 6 H₂O

The molar ratio of C₉H₁₂ to O₂ is 1:12. The moles of O₂ required to react with 0.67 moles of C₉H₁₂ are:

0.67 mol C₉H₁₂ × (12 mol O₂/1 mol C₉H₁₂) = 8.0 mol O₂

8.0 moles of O₂ are required to completely react with 0.67 moles of C₉H₁₂.

Answer:

To react with 0.67 moles C9H12 we need 8.04 moles of O2

Explanation:

Step 1: Data given

Number of moles C9H12 = 0.67 moles

Step 2: The balanced equation

C9H12 + 12O2 → 9CO2 + 6H2O

Step 3: Calculate moles of O2 required

For 1 mol C9H12 we need 12 moles of O2 to produce 9 moles of CO2 and 6 moles of H2O

For 0.67 moles of C9H12 we need 12 *0.67 = 8.04 moles of O2

To produce 9*0.67 = 6.03 moles of CO2 and 6*0.67 = 4.02 moles H2O

To react with 0.67 moles C9H12 we need 8.04 moles of O2

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 9.84 g of hydrochloric acid is mixed with 3.1 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answers

Answer:

1.4 g H₂O

Explanation:

In a reaction, the reactants are usually not present in exactstoichiometric amounts, that is, in the proportions indicated by the balanced equation. Frequently a large excess of one reactant is supplied to ensure that the more expensive reactant is completely converted to the desired product. Consequently, some reactant will be left over at the end of the reaction. The reactant used up first in a reaction is called the limiting reagent, because the maximum amount of product formed depends on how much of this reactant was originally present. When this reactant is used up, no more product can be formed.

Fatty acids are carboxylic acids with a long, unbranched hydrocarbon chain. There are three main classes of fatty acids. Classify the fatty acids as saturated, monounsaturated, or polyunsaturated.

Answers

Answer:

Coconut oil, Olive oil and Sunflower oil

Explanation:

Fatty acids are carboxylic acids with a long unbranched chain of carbon and hydrogen atoms.

There are three main classes of fatty acids which are explained as under:

1. Saturated Fatty acids: These fatty acids have long carbon chain with two hydrogen atoms bonded to each carbon atom. This saturation of fatty acids make the fatty acids more stable towards high temperature. These fatty acids becomes solid at room temperature. Coconut oil and butter are the examples of saturated fatty acids.

2. Monounsaturated Fatty Acids: In a long carbon chain, if there is a carbon atom which is double bonded with another carbon atom and rest is saturated with hydrogen atoms, because of this single double-bond, the fatty acid is termed as monounsaturated fatty acids. These fatty acids are liquid at room temperature but solidify in refrigerator. Olive oil is an example of such fatty acids.

3. Polyunsaturated Fatty Acids: In a long carbon chain, if there are two or more than two carbon atoms which are double bonded with each other and rest is saturated with hydrogen atoms, because of multiple double bonds, such fatty acids are termed as polyunsaturated fatty acids. Because of higher unsaturation, these fatty acids are liquid in both normal room temperature and in refrigerator. Such unsaturation also make them unfit for cooking purposes. Sunflower oil, Soyabean oil and Flaxseed oil are examples of polyunsaturated fatty acids.

Weathering and erosion can turn metamorphic rock into sediment. Which of the following processes would turn that sediment into sedimentary rock? * 10 points weathering and erosion compaction and cementation heat and pressure melting

Answers

Answer:

compaction and cementation

Explanation:

sedimentary rock is layered rock, in order to become sedimentary it most be compacted to form layers and cemented to become hard. This is what i think. Hope i can help :)

What is the mass of oxygen in 250 go of sulfiric acid, H2CO4

Answers

Hope this helps you.

Your answer is 160 grams I hope this helps
Other Questions
Choose the option below that is a characteristic of ketones. a. They contain a carbonyl group that exhibits sp hybridization around the carbon atom. b. They contain a carbonyl group with a nonpolar carbon-oxygen bond. c. The functional group of this type of compound must always be on the end of a carbon chain. d. The functional group of this type of compound must always be in the middle of a carbon chain.
Problem Page Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.)CaCl2 (aq) + H2O(l) →
How many atoms does 6H2O contain
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2 g of water are obtained. Determine the percent yield of the reaction.