Describe in detail what you know about the enthalpy, entropy, and free energy changes when a sample of gas condenses to a liquid. How does temperature affect these changes?.

Answers

Answer 1
Answer:

When a gas condenses to liquid the process is exothermic with the release energy and the enthalpy change is negative. As liquid has more ordered structure than gas, the entropy, which is the measure of disorder decreases or ∆ S has a negative value.  

Free energy is given by the Gibb's free energy equation,  

∆G = ∆H –T∆S

For a process to be spontaneous ∆ G must be negative.

∆H is negative and ∆S is negative, so the magnitude of |T∆S| should be less than the magnitude of |∆H| in that way ∆G is always negative.

|T∆S| should be less than the magnitude of |∆H|, so to favor that T should be low. The process is spontaneous at a lower temperature than at a higher temperature.  


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A sample of ethanol has a volume of 7.5 mL and a mass of 5.85 g. A sample of benzene also has a volume of 7.5 ml,but has a mass of 6.60 g. Which liquid is denser

Answers

Answer:

Benzene is denser than ethanol.

Explanation:

Given data:

Volume of ethanol = 7.5 mL

Mass of ethanol = 5.85 g

Volume of benzene = 7.5 mL

Mass of benzene = 6.60 g

Which is denser = ?

Solution:

First of all we will calculate the density of both substances.

Density of ethanol:

d = m/v

d = 5.85 g/ 7.5 mL

d = 0.78 g/mL

Density of benzene:

d = m/v

d = 6.60 g/ 7.5 mL

d = 0.88 g/mL

The density of benzene is higher thus it is denser than ethanol.

Answer:

Benzene

Explanation:

You need to calculate the densities for each compound.

EtOH = 5.85/7.5 = 0.78 g/mL

Benzene = 6.60/7.5 = 0.88 g/mL

0.88 > 0.78, thus benzene is denser than ethanol.

Describe the specific location where the head of the caudate nucleus is continuous with its body within the brain. What is the significance of this continuity, and how does it relate to the functions associated with the caudate nucleus?

Answers

Final Answer:

The head of the caudate nucleus blends with its body along the lateral wall of the lateral ventricles. This continuity enables integration with neighboring brain regions, crucial for motor, cognitive, and emotional functions.

Explanation:

The caudate nucleus, a C-shaped structure within the brain, consists of a head, body, and tail. The head of the caudate nucleus, situated at the anterior end, smoothly transitions into its body. This junction occurs along the lateral wall of the lateral ventricles, which are fluid-filled cavities that play a role in cerebrospinal fluid circulation.

The significance of this continuity lies in the structural integration it provides. This seamless connection allows the caudate nucleus to interact with neighboring brain regions, such as the putamen, globus pallidus, and cerebral cortex. These connections form part of the basal ganglia, a complex network involved in motor control, cognition, and emotional regulation.

Through these intricate interconnections, the caudate nucleus contributes to various functions. It plays a pivotal role in motor planning and execution, facilitating smooth, coordinated movements. Additionally, it participates in cognitive processes, including learning, memory, and decision-making. Moreover, the caudate nucleus is implicated in emotional regulation, influencing aspects of motivation and reward processing.

In summary, the seamless continuity between the head and body of the caudate nucleus along the lateral ventricles is essential for its functional integration with neighboring brain regions. This integration underpins the caudate nucleus's involvement in motor, cognitive, and emotional processes, highlighting its significance in overall brain function.

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Explanation:

The head of the caudate nucleus is continuous with its body at a specific location called the genu of the internal capsule. The genu of the internal capsule is a bend or curve in the white matter fibers that connect different regions of the brain.

The significance of this continuity between the head and body of the caudate nucleus at the genu of the internal capsule lies in the anatomical connectivity it provides. The genu of the internal capsule serves as a major pathway for communication between the cortex and the subcortical structures, including the caudate nucleus.

This continuity allows for bidirectional communication between the cortex and the caudate nucleus, facilitating the integration of information related to motor control, cognition, and emotion. It enables the caudate nucleus to receive input from various cortical regions, especially the prefrontal cortex, which is involved in executive functions and decision-making.

The caudate nucleus, including its head and body, is implicated in various functions such as motor control, learning, memory, reward processing, and cognitive flexibility. The continuity at the genu of the internal capsule ensures that signals from the cortex can be transmitted to the caudate nucleus, allowing it to integrate and modulate these functions.

Furthermore, disruptions or lesions at the genu of the internal capsule can lead to motor and cognitive impairments, as the communication between the cortex and the caudate nucleus gets compromised. This highlights the importance of the continuity between the head and body of the caudate nucleus at this specific location for the proper functioning of the brain and its associated functions.

Hope this helps!

Reaction rate is the speed with which reactants are converted to products in a chemical reaction. True or False?

Answers

True. Except that it is per unit of time. Units are important in order for our chemical reactions speed to be determined properly. 

Final answer:

The statement is true; reaction rate in chemistry refers to the speed at which reactants are transformed into products. Its rate is influenced by factors like concentration, temperature, and the presence of catalysts.

Explanation:

"Reaction rate is the speed with which reactants are converted to products in a chemical reaction," as stated above, is correct. In chemistry, the term Reaction Rate is used to describe how rapidly or slowly changes occur in a chemical reaction. It essentially provides information about how quickly reactants are transformed into products. Factors such as concentration, temperature, and presence of catalysts can influence the rate of a reaction.

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Which Pair Of Compounds Are Isomers?1) CH3CH2CH3 and CH2CHCH3
2) CH2CH2 and CH3COCH3
3) Ch3OCH3 and CH3COCH3
4) CH3COCH3 and CH3CH2CHO

I'd like to know the steps to answering this question. Thanks!

Answers

The correct pair of compounds that are isomers is CH₃COCH₃ and CH₃CH₂CHO and the correct option is option 4.

Isomers are compounds that have the same molecular formula but different structural arrangements or connectivity of atoms.

Among the given options, the pair of compounds that are isomers is CH₃COCH₃ (acetone) and CH₃CH₃CHO (propanal). Both compounds have the molecular formula C₃H₆O, but they differ in their structural arrangement.

Acetone is a ketone, with a carbonyl group located in the middle of the carbon chain, while propanal is an aldehyde, with the carbonyl group located at the end of the carbon chain.

These structural differences result in distinct chemical properties and reactivities of the compounds.

Thus, the ideal selection is option 4.

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The Pair Of Compounds that Are Isomers are CH3COCH3 and CH3CH2CHO. The answer is number 4. Isomers have the same formula but different structures. In number 4, both compounds contains three carbon atoms, one oxygen and 6 hydrogen atoms that makes them isomers.

A __________ is a large molecule consisting of many repeating structural units.a. monomer
c. polymer
b. isomer
d. elements

Answers

C. polymer it a large molecule consisting of many repeating structural units.

Final answer:

A polymer is a large molecule consisting of many repeating structural units or monomers. The process of formation is called polymerization.

Explanation:

The correct answer to this question is c. polymer. Polymers are large molecules made up of repeating subunits known as monomers. The process in which these monomers connect to form a polymer is called polymerization. An example of a polymer is plastic, which consists of many repeating units of smaller molecules.

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A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature?A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.

Answers

The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.

Final answer:

By using the ideal gas law and molar mass calculations, the final volumes are found to be A. 65.0 L, B. 8.75 L, and C. 27.5 L.

Explanation:

To calculate the final volume when additional O2 is added or when some O2 is removed, we can use the concept of the molar mass and the ideal gas law that states that volume is directly proportional to the amount of gas, assuming pressure and temperature is constant.

The molar mass of O2 is approximately 32.00 g/mol.

A. 0.500 moles of O2 is added. This equals 0.500 * 32 g = 16 g. The total mass in the system is now 20.8 g. If the original 15.0 L represented 4.80 g, now 20.8 g would represent 15.0 L * 20.8/4.80 = 65.0 L.

B. 2.00 g of O2 is removed. So, the total mass in the system is now 2.80 g. If the original 15.0 L represented 4.80 g, now 2.80 g would represent 15.0 L * 2.80/4.80 = 8.75 L.

C. 4.00 g of O2 is added. So, the total mass in the system is now 8.80 g. If the original 15.0 L represented 4.80 g, now 8.80 g would represent 15.0 L * 8.80/4.80 = 27.5 L.

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