A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs at 12.42 mL of added NaOH. What volume of added NaOH corresponds to the half-equivalence point?

Answers

Answer 1
Answer:

Answer:

(Incomplete question)

Assuming the molarity of the weak acid is 17.4 M, the answer would be 52.4mL.

Explanation:

Equivalence point is defined as the point where moles of titrant = moles of titrand (analyte).

At equivalence point,

# moles of NaOH = # moles of weak acid

# moles of NaOH = 0.1236 (mol)/(L) × 12.43 mL

= 0.1236 mol/L × 0.01242 L

= 0.00153511 moles of NaOH

= 0.00153511 moles of weak acid.

Since the concentration of acid is not stated in your question, we will assume the concentration of the acid to be 17.4 M.

concentration = no. of moles ÷ volume

⇒ vol. = no. of moles ÷ conc.

= 0.00153511 mol ÷ 17.4 mol/L

= 0.0267 L ≈ 26.7 mL

This means that the total volume of the solution at the half equivalence point will be:

26.7 mL + 26.7 ml

= 52.4 mL.  

N.B: Confirm missing variable from question: it could be concentration or volume of acid,but it is impossible to have two unknowns. Also, incase its pH of acid that's given, you can solve problem using Henderson-Hasslebauch equation.


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A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with distilled water. What is the final molarity of the dilute solution?

Answers

A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with distilled water. the final molarity of the dilute solution is 0.102 M.

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5 mL

Molarity of stock solution (M₁) = 5.103 M

Volume of diluted solution (V₂) = 250 mL

Molarity of diluted solution (M₂) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

5.103 × 5 = M2 × 250

25.515 = M2 × 250

Divide both side by 250

M2 = 25.515 / 250

M2 = 0.102 M

Thus, the molarity of the diluted solution is 0.102 M.

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Answer:

0.102 M.

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5 mL

Molarity of stock solution (M1) = 5.103 M

Volume of diluted solution (V2) = 250 mL

Molarity of diluted solution (V2) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M1V1 = M2V2

5.103 × 5 = M2 × 250

25.515 = M2 × 250

Divide both side by 250

M2 = 25.515 / 250

M2 = 0.102 M

Thus, the molarity of the diluted solution is 0.102 M.

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.1 kg

Explanation:

To obtain the total mass of the sample, we must first express each mass of the sample in the same unit of measurement.

Since the SI unit of mass is kilogram (kg), we shall express the total mass of the samples in kilogram (kg).

This is illustrated below:

Mass of the samples are:

M1 = 0.6160959 kg

M2 = 3.225 mg

M3 = 5480.7 g.

Conversion of 3.225 mg to kg

1 mg = 1×10¯⁶ kg

Therefore,

3.225 mg = 3.225 × 1×10¯⁶

3.225 mg = 3.225×10¯⁶ kg

Conversion of 5480.7 g to kg

1000 g = 1 kg

Therefore,

5480.7 g = 5480.7 /1000

5480.7 g = 5.4807 kg

Thus, we can obtain the total mass of the samples as follow:

M1 = 0.6160959 kg

M2 = 3.225×10¯⁶ kg

M3 = 5.4807 kg

Total mass =?

Total mass = M1 + M2 + M3

Total mass = 0.6160959 + 3.225×10¯⁶ + 5.4807

Total mass = 6.096799125 ≈ 6.1 kg

Therefore, the total mass of the samples is approximately 6.1 kg.

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Answer: Lithium and Ethanol

Explanation: As lithium and ethanol both have a density of under

1.000g/ml, they can be supported by the water. Blood and Magnesium are denser than the water and will therefore sink as the water can not support it them.

Predict the products and write balanced net ionic equations for the following reactions. (g) SnCl2 is added to KMnO4 solution (acidic) forming Mn2

Answers

The product and balanced net ionic equations for the following reactions are SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

What is the net ionic equation?

Ionic equations are those equations that happened in an aqueous solution. The chemical equation is expressed in an electrolyte solution is expressed and dissociates ions.

In these reactions, each element or ion is dissociated into differently charged ions in a solution. Each of the ions is shown with different charges.

SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂. In the reaction, the tin chloride, and potassium magnesium oxide. It dissociates into charged ions, like potassium chloride and tin magnesium oxide. The chlorine will acquire a negative charge and magnesium oxide get a positive charge.

Thus, the net ionic equation is SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

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Answer:

The answer to your question is:

Explanation:

Reaction

                  SnCl₂    +    2KMnO₄     ⇒    2 KCl     +    Sn(MnO₄)₂

                                               1 ----   Sn ----  1

                                               2 ----   K  ----- 2

                                               2 ----  Mn ----  2

                                               8 ----    O ----  8

                                               2 ----   Cl ----  2

Why do organisms evolve?Organisms make changes to help them survive and reproduce in their environment

Organisms with traits that help them survive and reproduce in their environment pass on those traits.

Changes in the environment cause organisms to change.
Organisms naturally select traits that help them survive and reproduce

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In an ecosystem, organisms evolve to make changes to help them survive and reproduce in their environment.

What is an ecosystem?

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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MEASUREMENT AND MATTER Interconverting temperatures in Celsius and Kelvins The metal osmium becomes superconducting at temperatures below 655.mk Calculate the temperature at which osmium becomes superconducting in degrees Celsius. Be sure your answer has the correct number of significant digits. Ac

Answers

Answer: -272^0C.

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C and K  

These units of temperature are inter convertible.

We are given:

Temperature of the gas = 655mK=0.655K    (1mK=0.001 K)

Converting this unit of temperature into ^0C by using conversion factor:

(t-273.15)^0C=tK

273.15K=0^0C

Thus 0.655K=(0.655-273.15)^0C=-272^0C

Thus the temperature is -272^0C.

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