Identify the independent and dependent variables in the following hypothesis: "People who exercise regularly are more likely to have normal or below normal weight." Exercise is the ________ variable and weight is the _________ variable

Answers

Answer 1
Answer:

Exercise will be the independent variable while weight will be the dependent variable.

Nowadays most of us do exercise in order to burn extra calories, that in turn, reduce the weight of a person. Some exercises even increase the weight of a person.

What if we do not do the exercise?

Our weight will increase or will remain constant. In a few cases, it will decrease the weight.

So it is clear that weight depends on many factors. one of those factors is exercise.

So weight is the dependent variable while exercise will be an independent variable.

Therefore, exercise will be the independent variable while weight will be the dependent variable.

To get more about variables refer to the link,

brainly.com/question/1429012

Answer 2
Answer:

Answer:

Independent

dependent

Step-by-step explanation:

The scenario illustrates that the weight for people who exercises regularly tends is normal or below normal. It means that the weight of a person depends on how much a person exercises i.e. if person exercises more the weight is reduced and if not then weight will be gained. Thus, exercise is the independent variable while weight is dependent variable.


Related Questions

A die is rolled twice.What is the probability that the first roll was a 6 and the second roll was an odd number?
If a car travels at a constant speed of 45km/hr how long will a journey of 270km take?​
There are 45 new houses being built in a neighborhood. Last month, 2/3 of them were sold. This month 2/5, of the remaining houses were sold. How many houses are left to be sold?
Gabriella swims 2 laps per minute. What is the associated rate? ___ minute per lapA.2B.4C.1/4D.1/2ANSWER QUICKKK
In a certain online dating service, participants are given a 4-statement survey to determine their compatibility with other participants. Based on the questionnaire, each participant is notified if they are compatible with another participant. Each question is multiple choice with the possible responses of "Agree" or "Disagree," and these are assigned the numbers 1 or −1, respectively. Participant’s responses to the survey are encoded as a vector in R4, where coordinates correspond to their answers to each question. Here are the questions:

Can someone pls help me here I really need it…

Answers

Answer:

it is 24fl is 78q and 8 gal is 196t

Step-by-step explanation:

i used my trick to do this

You can use both the t statistic and the z statistic to test hypotheses about the mean of population. The test that uses the t statistic is typically referred to as a t test, while the test that uses z statistic is commonly called a z test. Which of the following statements are true of the t statistic? Check all that apply. The t statistic uses the same formula as the z statistic except that the t statistic uses the estimated standard error in the denominator. The t statistic provides an excellent estimate of z, particularly with small sample sizes. The formula for the t statistic is t = (M – μ) / σM. The t statistic does not require any knowledge of the population standard deviation.

Answers

Using the concepts of the t-statistic and the z-statistic, it is found that the correct option is:

The t-statistic does not require any knowledge of the population standard deviation.

The z-statistic is given by:

z = (X - \mu)/((\sigma)/(√(n)))

In which:

  • X is the sample mean.
  • \mu is the population mean.
  • \sigma is the population standard deviation.
  • n is the sample size.
  • The standard error is S_e = (\sigma)/(√(n)).

The t-statistic is similar to the z-statistic, the difference is that the sample standard deviation is used, not the population. Thus:

t = (X - \mu)/((s)/(√(n)))

In which:

  • X is the sample mean.
  • \mu is the population mean.
  • s is the sample standard deviation.
  • n is the sample size.
  • The standard error is S_e = (s)/(√(n)).

For large sample sizes, the sample and population standard deviations are close, thus t is a good estimate of z.

Thus, the correct option is:

The t-statistic does not require any knowledge of the population standard deviation.

A similar problem is given at brainly.com/question/16194574

Answer:

Detailed elaborated answer is given below:

The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.

Answers

Answer:

-5 \to -24

-1 \to -4

2 \to 11

3 \to 16

4 \to 21

Step-by-step explanation:

Given

f(x) = 5x + 1

Required

Complete the table (see attachment)

When x = -5

f(-5) = 5 * -5 + 1 = -24

When x = -1

f(-1) = 5 * -1 + 1 = -4

When x = 2

f(2) = 5 * 2 + 1 = 11

When x = 3

f(3) = 5 * 3 + 1 = 16

When x = 4

f(4) = 5 * 4 + 1 = 21

So, the table is:

-5 \to -24

-1 \to -4

2 \to 11

3 \to 16

4 \to 21

Find the average value of the function over the given interval. (Round your answer to three decimal places.) f(x) = −sin x, [0, π] Find all values of x in the interval for which the function equals its average value. (Enter your answers as a comma-separated list. Round your answers to three decimal places.)

Answers

The average value of the function is -(2)/(\pi).

Average value :

The average value of the function is given as,

                    Average=(1)/(\pi) \int\limits^\pi_0 {f(x)} \, dx

Given function is, f(x)=-sinx

Substitute values in above relation.

                Average=(1)/(\pi) \int\limits^\pi_0 {-sinx} \, dx\n\nAverage=(1)/(\pi) (cosx)^(\pi) _(0)\n\nAverage=(1)/(\pi)(cos\pi - cos 0)\n\nAverage=(1)/(\pi)(-1-1)\n\nAverage=-(2)/(\pi)

The values of x in the interval for which the function equals its average value is,

              -sinx=-(2)/(\pi)\n \nx=sin^(-1) ((2)/(\pi) )=39.56

Learn more about the average value of function here:

brainly.com/question/20118982

Answer with Step-by-step explanation:

We are given that

f(x)=-sin x

[0,\infty]]

Average value of the function is given gy

f_(avg)=(1)/(b-a)\int_(a)^(b)f(x)dx=(1)/(\pi-0)\int_(0)^(\pi)-sinx dx

f_(avg)=(1)/(\pi)[cosx]^(\pi)_(0)

Using the formula

\int sin xdx=-cos x

f_(avg)=(1)/(\pi)(cos\pi-cos0)

f_(avg)=(1)/(\pi)(-1-1)=-(2)/(\pi)

f(x)=f_(avg)

-sinx=-(2)/(\pi)

sinx=(2)/(\pi)

x=sin^(-1)((2)/(\pi))=0.69radian

Members of a softball team raised $2039.50 to go to a tournament. They rented a bus for $1157.50 and budgeted $49 per player for meals. Write and solve an equation which can be used to determine xx, the number of players the team can bring to the tournament.

Answers

Answer:

18 = number of players

Step-by-step explanation:

Giving the following information:

Members of a softball team raised $2039.50 to go to a tournament. They rented a bus for $1157.50 and budgeted $49 per player for meals.

To calculate the total number of players they can bring, we need to use the following formula:

Total amount of money= fixed cost + unitary variable cost*number of players

2,039.5= 1,157.5 + 49*number of players

882/49= number of players

18 = number of players

The team can bring a maximum of 18 players to the tournament given the amount they raised and the budgeted expenses.

Let's use "x" to represent the number of players the team can bring to the tournament.

The total amount raised by the team is $2039.50,

and they rented a bus for $1157.50. Each player's meal will cost $49.

The total amount spent on the bus and meals for x players can be represented as follows:

Total Expenses = Bus Cost + (Number of Players) * (Cost per Player's Meal)

                           = $1157.50 + x * $49

Since the team's total expenses should not exceed the total amount raised,

$2039.50 ≥ $1157.50 + x * $49

$2039.50 - $1157.50 ≥ x * $49

$882 ≥ x * $49

Now, divide both sides by $49 to solve for x:

x ≤ $882 / $49

x ≤ 18

So, the team can bring a maximum of 18 players.

Learn more about Inequality here:

brainly.com/question/20383699

#SPJ3

Write this fraction in the simplest form 15/25

Answers

15/25  Divididing numerator and denominator by 5 we get:

3 / 5


If 15/25 is 0.6 you can then convert it to a 3/5