The number x of stereo speakers a retail chain is willing to sell per week at a price of p dollars is given by. Find the supply and instantaneous rate of change of supply when the price is 75 dollars?

Answers

Answer 1
Answer:

Answer:

Please find below the complete question:

The number  x  of stereo speakers a retail chain is willing to sell per week at a price of  p  dollars is given by  x  =  80√(p+27)  −  410.  Find the supply and instantaneous rate of change of supply when the price is  75  dollars.

Supply = 398

Instantaneous rate of change of supply=3.96

Step-by-step explanation:

x=80√(p+27) -410

Supply when price = $75

x=80√(75+27) -410 = x=80√(102) -410\n\nx = 80(10.1) -410= 808-410\n\nx = 398

Supply = 398 stereo speakers

To get the instantaneous rate of supply, we differentiate the supply, x, with respect to price, p

(dx)/(dp) = (d)/(dp)(80√(p+27) -410)\n\n(dx)/(dp) = (d)/(dp)(80(p+27)^(1/2) -410)

Using chain rule, we have

(x)/(y) (dx)/(dp)=(d)/(dp)( 80(p+27)^(1/2)) - (d)/(dp)(410) \n\n(dx)/(dp)=80((1)/(2))(p+27)^(-1/2) - 0\n\n(dx)/(dp)=(40)/(√(p+27) ) \n

At p = $75

(dx)/(dp)=(40)/(√(75+27) )=(40)/(√(102) )\n\n(dx)/(dp)=(40)/(10.1) = 3.96\n\n(dx)/(dp)=3.96

Answer 2
Answer:

The question is not complete and the complete question says:

The number  x  of stereo speakers a retail chain is willing to sell per week at a price of  p  dollars is given by x=80√(p+27) − 410 Find the supply and instantaneous rate of change of supply when the price is  75  dollars

Answer:

A) Approximately 398 stereo speakers

B) Instantaneous rate of change = 3.961

Step-by-step explanation:

From the question, the number of speakers is given as;

x=80√(p+27) − 410

A) Thus at a price of $75,

The amount supplied will be;

x = 80√(75+27) − 410

x = 80√(102) - 410

x = (80 x 10.0995) - 410

x = 807.96 - 410 = 397.96 ≈ 398 stereo speakers

B) The instantaneous rate of change is given as;

dx/dp of the supply equation.

Thus, let's rearrange the supply equation first before differentiating.

So, x = 80√(p+27) − 410

x = 80[(p +27)^(1/2)] - 410

So, dx/dp = [(80 x 1/2) (p + 27)^(-1/2)]

dx/dp = 40/√(p+27)

So, at price of $75,

dx/dp = 40/√(75+27) = 40/√102

= 40/10.0995 = 3.961


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Answers

Answer:

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Step-by-step explanation:

As per the statement:

Cost Price of the camera = $50  

Selling price of the camera = $45

We have to find the profit that you will earn.

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Then;

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