1. Straight-in spaces can leave you a safer out if.
A. you're able to pull through facing out
B. you're able to park farther away from the building
C. you're able to reverse out of the parking spot
D. they are located in a parking garage

Answers

Answer 1

Answer:

Option (A) is correct

Straight-in spaces can leave you a safer out if you're able to pull through facing out

Straight-in parking:

Straight-in parking is a method to park a vehicle where the vehicle is guided and parked safely in between the guiding lines.

Each car is provided a separate slot for parking. It thus helps to prevent blockage of cars. Each car can move in and out freely without any congestion.

Straight-in parking is the most traditional approach of parking which saves time for drivers, allows for two-way traffic as well.

The driver can line up from multiple angles. But the safest way to leave out the Straight-in parking is to pull through facing out.

So option A is the most suitable option in the provided case.

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Answer 2

Answer:

Answer: A. You're able to pull through facing out

Explanation: DriversED

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During what intervals was jenny negatively accelerating

Answers

Jenny's acceleration was negative during the intervals of time when her speed was decreasing.

That's really all we can tell, because you really haven't given us any information except her name.

Final answer:

Negative acceleration refers to times when Jenny was slowing down in her motion. Exact intervals cannot be given without further information on her motion timeline or graphical representation.

Explanation:

The periods during which Jenny was negatively accelerating would be the time intervals during her motion when her speed was decreasing. In a physics context, negative acceleration (or deceleration) means that the object (in this case, Jenny) is slowing down. For instance, if Jenny was running and began to slow down, the period from when she began slowing to when she stopped would be an interval of negative acceleration. However, without specific timelines or a graphical description of Jenny's motion, it's impossible to determine the exact intervals of negative acceleration.

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5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up aramp inclined to the horizontal by 15.0°. In both cases, you apply a force of 100.N parallel to the
surface (parallel to the floor or parallel to the ramp). Calculate the work done by:
a) the gravitational force as the box is pushed across the flat ground
b) the gravitational force as the box is pushed up the ramp
c) the force you apply as the box is pushed across the flat ground
d) the force you apply as the box is pushed up the ramp

Answers

a) The work done by the gravitational force on the flat surface is zero

b) The work done by the gravitational force on the ramp is -634 J

c) The work done by the applied force on the flat surface is 500 J

d) The work done by the applied force on up along the ramp is 500 J

Explanation:

The work done by a force is given by the equation

$W=Fdcos \theta$

where

F is the magnitude of the force

d is the dispalcement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.

We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is $90^(\circ)$ ; this means that $cos 90^(\circ)=0$ , and therefore, the work done is zero:

$W=0$

In this case, the box is pushed along the ramp. We have:

$F=mg=(50.0)(9.8)=490 N$ is the magnitude of the force of gravity, where

m = 50.0 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration of gravity

d = 5.00 m is the displacement of the box along the ramp

The ramp is inclined to the horizontal by $15.0^(\circ)$ , therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:

$\theta=90^(\circ)+15^(\circ)=105^(\circ)$

Therefore, the work done by gravity in this case is:

$W=(490)(5.00)(cos 105^(\circ))=-634 J$

In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.

Here we have:

F = 100.0 N (force applied)

d = 5.00 m (displacement of the box)

$\theta=0^(\circ)$ (the force is applied parallel to the flat surface, therefore force and displacement have same direction)

Therefore, the work done by the force you apply on the flat ground is:

$W=(100.0)(5.00)(cos 0^(\circ))=500 J$

In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.

This time we have:

F = 100.0 N (force applied is the same)

d = 5.00 m (displacement of the box is also the same)

$\theta=0^(\circ)$ (the force is applied parallel to the ramp, therefore force and displacement have again same direction)

Therefore, the work done by the force you apply while pushing the box along the ramp is:

$W=(100.0)(5.00)(cos 0^(\circ))=500 J$

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A car with loud bass speakers drives by a house. The windows of the house vibrate significantly. What term best describes why the windows vibrate?

Answers

The term best describes why the windows vibrate when a car with loud bass speakers drives by a house is Resonance.

What is resonance?

Resonance is a system's or object's relatively strong selective response to an outside oscillatory force that causes it to vibrate in step or phase. The vibration that is caused in a violin or piano string of a specific pitch when a musical note of the same pitch is sung or performed nearby is an example of acoustical resonance.

Resonance is the word that best describes the cause of the windows' vibration. It occurs when a vibrating system or outside stimulus causes another system to oscillate more violently and at a certain preferred frequency. Because of this, the house's windows vibrate a lot. On the nuclear scale, a type of resonance that resembles a particular kind of mechanical resonance has been discovered.

Therefore, the term best describes why the windows vibrate when a car with loud bass speakers drives by a house is Resonance.

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The term that best describes why the windows vibrate is resonance. It is described when a vibrating system or external force drives another system to oscillate with greater amplitude at a specific preferential frequency. That is why the windows of the house vibrate significantly.

Identify each of the cell structures in the figure

Answers

Fair enough ! Where's the figure ?

Explain whether smoke filling up a room is diffusion or not

Answers

Yes, it is diffusion !

Diffusion is the process in which gas, through random movement of particles, tends to fill up the whole volume of the container in which it is placed. So a similar process would lead the smoke, which is in form of gas (or light particles), to fill in the whole room in which it is contained.

5 letter word foramount of work done per second

Answers

The rate of work, or any other form of energy, is power .

The number of joules of work or other energy in 1 second
is the number of watts of power.

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