PHYSICS COLLEGE

(a) How fast and in what direction must galaxy A be moving if an absorption line found at 550 nm (green) for a stationary galaxy is shifted to 450 nm (blue) for A? (b) How fast and in what direction is galaxy B moving if it shows the same line shifted to 700 nm (red)?

Answers

Answer 1
Answer:

Explanation:

For Part (a)

Since the apparent wavelength decreases hence galaxy moving towards the stationary observer.

Δλ/λ=v/c

=(v)/(c)\n v=(550-450)/(550)*3*10^(8)\n v=5.4545*10^(7)m/s

For Part (b)

Since the apparent wavelength increases hence galaxy moving towards the stationary observer.

Δλ/λ=v/c

=(v)/(c)\n v=(700-550)/(550)*3*10^(8)\n v=8.1818*10^(7)m/s

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A train travels 64 kilometers in 5hours and then 93 kilometers in 2hours. What is it’s average speed?
A particular string resonates in four loops at a frequency of 320 Hz . Name at least three other (smaller) frequencies at which it will resonate. Express your answers using two significant figures separated by commas.
What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.​
A small grinding wheel is attached to the shaft of an electric motor which has a rated speed of 3600 rpm. When the power is turned on, the unit reaches its rated speed in 5 s, and when the power is turned off, the unit coasts to rest in 70 s. Assuming uniformly accelerated motion, determine the number of revolutions that the motor executes (a) in reaching its rated speed, (b) in coasting to rest.

What is the speed of an airplane that travels 4500 miles in 6 hours?

Answers

Answer:

750 miles / hour

Explanation:

velocity = distance / time

             = 4500 miles / 6 hours

             = 750 miles / hour

Given:-

  • Speed of the airplane (s) = 4500miles
  • Time taken (t) = 6h

ToFind:Speed (v) of the particle (airplane).

We know,

s=vt

where,

  • s = Distance,
  • v = Speed &
  • t = Time taken.

Similarly,

v=s/t

→ v = (4500 miles)/(6 hours)

→ v = 750 miles/hour ...(Ans.)

Which one of these are true about scale models? a. A map may have a scale model with the proportion of one centimeter to one kilometer. b. A scale model is always smaller than the object it represents, c. A model may be built to different scales.

Answers

Answer:

Option A is true

Explanation:

For option A, it's true because a map that has a scale model with the proportion of one centimeter to one kilometer is known as verbal scale which is a type of scale.

For option B, it's not true because though a scale model is most times always smaller than the object it represents, there are sometimes when the scale model is an enlarged view/representation of a small object.

For option C, it's true because there is no one scale that is confined to just a model. A model can use different scales to depict an object.

Which sling can the crane use to lift the 1000kg pipe?A.
800kg rated sling
B. 1000kg rated sling
C. 2000kg rated sling
D. Band C

Answers

Answer:

C. 2000kg rated sling

Explanation:

ensures better safety and can carry twice more mass than current mass.

Talia is on a road trip with some friends. In the first 2 hours, they travel 100 miles. Then they hit traffic and go only 30 miles in the next hour. The last hour of their trip, they drive 75 miles.Calculate the average speed of Talia’s car during the trip. Give your answer to the nearest whole number.

Answers

Answer:

51 mph

Explanation:
Since Speed, V = Distance/Time
Average speed = Total Distance/Total Time

From the given data, Total Distance = 100 + 30 + 75 miles
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How many joules of work are done on an object when a force of 10 N pushes it 5 m?A) 2 J
B) 5 J
C) 50 J
D) 1 J
E) 10 J

Answers

Answer:

option C

Explanation:

given,                            

Force on the object = 10 N

distance of push = 5 m

Work done = ?              

we know,              

work done is equal to Force into displacement.

W = F . s            

W = 10 x 5              

W = 50 J                

Work done by the object when 10 N force is applied is equal to 50 J

Hence, the correct answer is option C

Final answer:

The work done on an object when a force of 10 N pushes it 5 m is 50 Joules, calculated by multiplying the force and the displacement. So, the correct option is C.

Explanation:

The question is asking about work, which in physics is the result of a force causing a displacement. The formula for work is defined as the product of the force (in Newtons) and the displacement (in meters) the force causes. If a force of 10 N pushes an object a distance of 5 m, the work done is calculated by multiplying the force and the displacement (10 N * 5 m), yielding 50 Joules of work.

Therefore, the correct answer is 50 J (C).

Learn more about Work here:

brainly.com/question/31965083

#SPJ6

Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the compressor if the inlet volumetric flow rate is 0.15 m3/s. Use constant specific heats evaluated at 300 K.

Answers

Answer:

\dot W_(in) = 49.386\,kW

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

\dot W_(in) + \dot m \cdot c_(p)\cdot (T_(1)-T_(2)) = 0

The power consumed by the compressor can be calculated by the following expression:

\dot W_(in) = \dot m \cdot c_(v)\cdot (T_(2)-T_(1))

Let consider that air behaves ideally. The density of air at inlet is:

P\cdot V = n\cdot R_(u)\cdot T

P\cdot V = (m)/(M)\cdot R_(u)\cdot T

\rho = (P\cdot M)/(R_(u)\cdot T)

\rho = ((104\,kPa)\cdot (28.02\,(kg)/(kmol)))/((8.315\,(kPa\cdot m^(3))/(kmol\cdot K) )\cdot (292\,K))

\rho = 1.2\,(kg)/(m^(3))

The mass flow through compressor is:

\dot m = \rho \cdot \dot V

\dot m = (1.2\,(kg)/(m^(3)))\cdot (0.15\,(m^(3))/(s) )

\dot m = 0.18\,(kg)/(s)

The work input is:

\dot W_(in) = (0.18\,(kg)/(s) )\cdot (1.005\,(kJ)/(kg\cdot K))\cdot (565\,K-292\,K)

\dot W_(in) = 49.386\,kW
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