Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm3. If the combustion of this mixture releases 950. J of energy, to what volume will the gases expand against a constant pressure of 650. torr if all the energy of combustion is converted into work to push back the piston
Answers
The given system is a constant pressure systemwhere the work done is the product of the pressure and the volume change.
- The volume to which the gas expands to is approximately 11 liters
Reasons:
Given parameters;
The original volume, V₁ = 40 cm³
The energy released, E = 950 J
Constant pressure applied, P = 650 torr.
Condition: All energy is converted to work to push back the piston
Required:
The volume to which the gas will expand
Solution;
The work done, W = Energy releases, E = 950 J
Work done at constant pressure, W = P·(V₂ - V₁)
Where;
V₂ - The volume to which the gas will expand
Converting the volume to from cm³ to m³ gives;
V₁ = 40 cm³ = 0.00004 m³
Converting the pressure given in torr to Pascals gives;
650 torr. = 86659.54 Pa.
Therefore, we get;
950 J = 86659.54 Pa. × (V₂ - 0.00004 m³)
Converting to liters gives;
- The volume to which the gas expands, V₂ ≈ 11 liters.
Learn more here:
Answer:
The volume needed to expand the gas is = 11 Lit = 11000 
Explanation:
Given :
Initial volume Lit.
Energy J = 9.38 Lit × atm. ⇒ ( 1 Lit×atm. = 101.325 J )
Pressure 650 torr = 0.855 atm. ⇒ ( 1 torr = 0.00132 atm )
In this example we have to be aware of unit conversion system.
From the laws of thermodynamics,
Here in this example, all the energy of combustion is converted into work to push back the piston
Lit =
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