"An airplane traveling at one third the speed of sound (i.e., 114 m/s) emits a sound of frequency 3.65 kHz. At what frequency does a stationary listener hear the sound as the plane approaches? Answer in units of kHz."
Answers
The frequency at which the stationary listener will hear the sound of the plane as it approaches is 5.54 KHz
Data obtained from the question
- velocity of source (vₛ) = 114 m/s
- original frequency (f₀) = 3.65 KHz
- velocity of observer (v₀) = 0 m/s
- velocity of sound (v) = 334 m/s
- Observer's frequency (f₀) =?
How to determine the the observer's frequency
Applying the equation of Doppler effect, the observer's frequency can be obtained as follow:
f₀ = [(v + v₀) / (v – vₛ)]f
f₀ = [(334 + 0) / (334 – 114)] × 3.65
f₀ = [334 / 220] × 3.65
f₀ = 5.54 KHz
Learn more about Doppler effect:
Answer:
Explanation:
velocity of source, Vs = 114 m/s
original frequency, f = 3.65 kHz
velocity of observer , Vo = 0 m/s
velocity of sound, v = 334 m/s
let the frequency is f'.
The formula for the doppler effect is given by
where, v is the velocity of sound.
f' = 5.54 kHz
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Blocking/staging
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Answer:
R = 0.6 ohms
Explanation:
We have,
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281 Hz
322 Hz
Answers
Answer:
322 Hz
Explanation:
v = speed of train approaching the railroad crossing = 80 km/h = 80 x 1000/3600 m/s = 22.22 m/s
V = speed of sound of the horn of train = 331.5 m/s
f = actual frequency of the sound from the horn = 300.0 Hz
f' = observed frequency of the horn
Using Doppler's effect, observed frequency is given as
f' = V f/(V - v)
inserting the values
f' = (331.5) (300.0)/(331.5 - 22.22)
f' = 322 Hz
h
b. False
Answers
Answers
Answer:
Explanation:
Torque and energy of an electric dipole in an electric field we find:
Final answer:
The work required to turn an electric dipole 180° in a uniform electric field is -4.89 × 10^-24 J.
Explanation:
To calculate the work required to turn an electric dipole 180° in a uniform electric field, we can use the formula:
W = -pE(1 - cosθ)
where W is the work done, p is the dipole moment, E is the electric field strength, and θ is the angle between the dipole moment and the electric field.
Plugging in the given values:
W = - (3.02 × 10-25 C·m)(46.0 N/C)(1 - cos(180° - 64°))
Simplifying the equation gives the work done to be -4.89 × 10-24 J.
Learn more about Work done on an electric dipole here:
#SPJ3
Answers
Explanation:
Potential Energy = mg h mg = 240 N
80 = 240 h
h = 80 / 240 = 1/3 meter ( 33.3 cm)