MATHEMATICS MIDDLE SCHOOL

Suppose a circle has its center at the origin. What is the equation of the circlein this case?
Pleassee answer this quickk

Answers

Answer 1

Answer:

Answer:

hey

Step-by-step explanation:

(x-h)²+(y-k)²=r²

here (h,k) =(0,0)

Equation of circle will be

x²+y²= r²

Answer 2

Answer:

Answer:

We know that the general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius.

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A car is moving at a constant acceleration of 7.0 m/s/s. How fast (velocity) is it going after 4.0 seconds, if it starts from rest.? Show work using ESA format.

Answers

28 m/s is the velocity , when it is going after 4.0 seconds.

What is Acceleration?

When a point or an object moving in a straight line , the acceleration is the rate at which velocity changes with time, in terms of both speed and direction.

Here, given that,

A car is moving at a constant acceleration of 7.0 m/s/s

Now, we have,

Velocity = acceleration * time

After 4 sec. = 7*4 = 28 m/s

Hence, 28 m/s is the velocity , when it is going after 4.0 seconds.

To learn more on Acceleration click:

brainly.com/question/2303856

#SPJ2

28 m/s. 7 x 4 hope this helps:)

What is straight part of a line and has two end points

Answers

This is called a line segment

It could be ling segments or just lines. Line segments have two end points and lines have two arrows

What is the product of (-6.8)^2

Answers

Answer

46.24

Explanation

n² = n × n

∴ (-6.8)² = (-6.8) × (-6.8)

= 46.24

The answer is positive since (-1)×(-1) = 1.

-6.8^2

You can do this with a calculator or pen and paper.

With a calculator;

-6.8 squared = 46.24 (Notice that the answer is positive!)

PLEASE HELP ASAP I NEED THIS NOW Sara graphs a line passing through points that represent a proportional relationship. Which set of points could be on the line that Sara graphs?A). (2,4),(0,2),(3,9)
B). (6,8),(0,0),(18,24)
C). (3,6),(4,8),(9,4)
D). (1,1),(2,1),(3,3)

Answers

Answer: Option B.

Step-by-step explanation:

By definition, the graph of a proportional relationships is a straight line that passes through the origin (Remember the the origin is at $(0,0)$ ).

Then, the equation have the following form:

$y=kx$

Where "k" is the constant of proportionality (or its slope)

Then, since the Sara graphs a line that represent a proportional relationship, you can conclude that the line must pass through the point $(0,0)$ .

Then:

The set of points in Option A could not be on that line, because when $x=0,y=2$

The set of points $(6,8),(0,0),(18,24)$ (Given in Option B) could be on the line that Sara graphs, because it has the point $(0,0)$

For the set of points shown in Option C and Option D, you can check if the slope is constant:

$C)\ slope=(y)/(x)\n\na)\ slope=(6)/(3)=2\n\nb)\ slope=(8)/(4)=2\n\nc)\ slope=(4)/(9)$

Since the slope is not constant, this set of ponts could not be on the line.

$D)\ slope=(y)/(x)\n\na)\ slope=(1)/(1)=1\n\nb)\ slope=(1)/(2)$

Since the slope is not constant, this set of ponts could not be on the line.

Set of points that could be on the line that Sara graphs are:

Option B). (6,8) , (0,0) , (18,24)

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

$\large {\boxed{m = (y_2 - y_1)/(x_2 - x_1)}}$

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

$\large {\boxed{y - y_1 = m ( x - x_1 )}}$

Let us tackle the problem.

$\texttt{ }$

This problem is about Directly Proportional.

If (x₁ , y₁ ) and (x₂ , y₂) are on the line that represent a proportional relationship, then :

$\large {\boxed { y_1 : x_1 = y_2 : x_2 } }$

Option A

Let:

(2,4) ⇒ (x₁ , y₁)

(3,9) ⇒ (x₂ , y₂)

$4 : 2 \ne 9 : 3$

$2 : 1 \ne 3 : 1$

$2 \ne 3$ → not proportional

$\texttt{ }$

Option B

Let:

(6,8) ⇒ (x₁ , y₁)

(18,24) ⇒ (x₂ , y₂)

$8 : 6 = 24 : 18$

$4 : 3 = 4 : 3$ → proportional

$\texttt{ }$

Option C

Let:

(3,6) ⇒ (x₁ , y₁)

(9,4) ⇒ (x₂ , y₂)

$6 : 3 \ne 4 : 9$

$3 : 1 \ne 4 : 9$ → not proportional

$\texttt{ }$

Option D

Let:

(1,1) ⇒ (x₁ , y₁)

(2,1) ⇒ (x₂ , y₂)

$1 : 1 \ne 1 : 2$ → not proportional

$\texttt{ }$

Learn more

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

#LearnWithBrainly

F(x) = 4x - 1g(x) = x2 - 2
(f + g)(9) = ?
A. 118
B. 112
C. 119
D. 114
E. 116
F. 111
G. 110
H. 115
I. 113
J. 117

Answers

Answer:

Step-by-step explanation:

Find (f + g)(x) then evaluate (f + g)(9)

(f + g)(x) = f(x) + g(x)

= 4x - 1 + x² - 2 = x² + 4x - 3

Now substitute x = 9 into the expression

(f + g)(9) = 9² + 4(9) - 3 = 81 + 36 - 3 = 114 → D

Answer:

J.117

Step-by-step explanation:

f(x) =4x-1

if f(2)= 4(2)-1

f(2)= 8-1 = 7

f(2) = 7 equation 1

g(x) =x2-2

if g(4)= (4)2-2

g(4) = 8-2 = 6 equation 2

Now,

(f+g)(9) =?

subtitute equation 1 and 2

(7+6)(9)=?

(13)(9)=?

13×9= 117

Hence, the answer is 117

I have no idea how to do this stuff.

Answers

Answer: $y=2x^(2)-5x+7$

Step-by-step explanation:

The quadratic equation in its standard form is:

$y=ax^(2)+bx+c$

Now, we are given 5 points of the parabola (if you graph a quadratic equation you will have a parabola), however we only need to choose three points to find the coeficients $a$ , $b$ and $c$ in the quadratic equation.