MATHEMATICS HIGH SCHOOL

What’s the potential difference across a 5.0 resistor that carries a current of 5.0A

Answers

Answer 1
Answer:

Answer:

25

Step-by-step explanation:

Potential difference

make use of the formula:

V = IR

where :

v--- potential difference

I ---- current

R --- resistance

place the values into the formula

V = 5 * 5

= 25

The potential difference is 25

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What is the product of 2p + q and –3q – 6p + 1?–12p2 – 6pq – 4p – 3q + 1
–12p2– 12pq + 2p – 3q2 + q
–9p2q2 + 12pq – 2p + q
12p2 + 12pq +2p + 3q2 + q

Answers

The product of the 2p + q and –3q – 6p + 1 is \rm -12p^2-12pq+2p-3q^2+q.

Given

The given terms are;

2p + q and –3q – 6p + 1

How to calculate the product of given terms?

To find a product, you'll need to multiply at least two numbers together following all the steps given below.

The product of the terms is;

\rm = (2p+q) * (-3q-6p+1)\n\n= 2p* (-3q-6p+1) + q* (-3q-6p+1)\n\n= 2p* (-3q) +2p* (-6p)+2p* (1) + q* (-3q) + q*(-6p) +q* (1)\n\n=-6pq-12p^2+2p-3q^2-6pq+q\n\n= -12p^2-12pq+2p-3q^2+q

Hence, the product of the 2p + q and –3q – 6p + 1 is \rm -12p^2-12pq+2p-3q^2+q.

To know more about Product click the link given below.

brainly.com/question/4281741

Answer:  Second option is correct.

Step-by-step explanation:

Since we have given that

(2p+q)\ and\ (-3q-6p+1)

We need to product the two polynomials .

Here it is :

(2p+q)(-3q-6p+1)\n\n=2p(-3q-6p+1)+q(-3q-6p+1)\n\n=-6pq-12p^2+2p-3q^2-6pq+q\n\n=-12p^2-3q^2+2p+q-12pq

Hence, Second option is correct.

noah has 72 collecters flags he is going to put 6 flags in each row how many rows of flags will he have in his display

Answers

If you would like to know how many rows of flags will Noah have in his display, you can calculate this using the following steps:

72 flags / 6 flags = 12 rows

The correct result would be 12 rows.
12 
because....
72/6= 12

A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.

Answers

w-width\nl-length\n\n2w+2l=50\to w+l=25\nw=(2)/(3)l\n\nsubstitute:\n\n(2)/(3)l+l=25\n\n(5)/(3)l=25\ \ \ \ /\cdot(3)/(5)\n\nl=15\ (m)\n\nw=(2)/(3)\cdot15=10\ (m)\n\nArea:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)

Which polynomial represents the area of the rectangle?a. 3x2+2x−5
b. 3x2−5
c. 3x2−2x−5
d. 3x2−8x−5

Answers

Answer:

Step-by-step explanation:

The correct option is C.

Step-by-step explanation:

The width of the rectangular pen is

The length of the rectangular pen is

The perimeter of a rectangle is

Therefore the correct option is C.

Final answer:

Without specific dimensions for the rectangle, it's impossible to definitively determine which polynomial represents its area. If we knew the length and width in terms of x, we could then form a polynomial by multiplying them.

Explanation:

This question is based on the concept of polynomials and their application in representing areas. From the provided question, we don't have specific dimensions of the rectangle, thus making it impossible to definitively determine which polynomial represents its area.

If the length and width of the rectangle were expressed in terms of x (e.g., 3x and x, or some other terms x and 2x-5), then we could put these expressions in the form of a polynomial by multiplying them together. For example, if we suppose our rectangle has sides of 3x and x, then the area would be represented by the polynomial 3x2, which equals to 3x*x.

However, without specific rectangular dimensions, we can't accurately choose between the provided options: 3x2+2x−5, 3x2−5, 3x2−2x−5, and 3x2−8x−5.

Learn more about Polynomials in Area Calculation here:

brainly.com/question/12723489

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2a2b3 and -4a2b3 are like terms.
a. True
b. False

Answers

2a²b³ and -4a²b³ are like terms as they both have the same variables with the same degrees.

Your final answer is a. True.

Round each fraction to the nearest half and find the estimate. 2/6 + 1/6 one half 1 one and one half 2

Answers

Answer:

one half

Step-by-step explanation:

Given the expression

2/6 + 1/6

Find the LCM

= (2+1)/(6) \n= (3)/(6) \n= (3*1)/(3*2)\n= (3)/(3) * (1)/(2) \n= 1 * (1)/(2)\n= (1)/(2)

Hence the required result is one half
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