Suppose that a digitized TV picture is to be transmitted from a source that uses a matrix of 480 * 500 picture elements (pixels), where each pixel can take on one of 32 intensity values. Assume that 30 pictures are sent per second. (This digital source is roughly equivalent to broadcast TV standards that have been adopted.) Find the source rate R (bps).

Answers

Answer 1
Answer:

Answer:

36,000,000 bps

Step-by-step explanation:

Matrix of 480 by 500 = 480 X 500 = 240,000 pixels

Intensity values per pixel = 32. This simply means the color variations in this TV.

The bit per pixel for an intensity value of 32 is 5 (That's 2 raised to the power of 5)

Pictures sent per second = 30

Source rate R (bps) = Total number of pixels in the matrix X bit per pixel X Number of pictures sent per second.

Source rate R (bps) = 240,000 X 5 X 30 = 36,000,000 bps

Answer 2
Answer:

Final answer:

The source rate for the digitized TV picture is 230,400,000 bps.

Explanation:

The source rate can be calculated by multiplying the number of pixels per picture element by the number of intensity values per pixel and by the number of pictures sent per second.

So, the source rate R (bps) is given by:

R = (480 * 500) * 32 * 30

Calculating this, we find that the source rate is 230,400,000 bps.

Learn more about Calculating the source rate for a digitized TV picture transmission here:

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Answers

Answer:

\bf \phi (9)=5

\bf \phi (15)=8

\bf \phi (75)=40

Step-by-step explanation:

Positive integers relative primes to 9 which are less or equal than 9

{1,2,4,5,7}

so

\bf \phi (9)=5

Positive integers relative primes to 15 which are less or equal than 15

{1,2,4,7,8,11,13,14}

and

\bf \phi (15)=8

Positive integers relative primes to 75 which are less or equal than 75

{1,2,4,7,8,11,13,14,16,17,19,22,23,26,28,29,31,32,34,37,38,41,43,44,46,47,49,52,53,56,58,59,61,62,64,67,68,71,73,74}

and

\bf \phi (75)=40

Line p is parallel to line q. Parallel lines p and q are crossed by lines a and b to form 2 triangles. At parallel line p, angle 4 is formed by line b and angle 5 is formed by line a. Angle 6 is the third angle. At parallel line q, angle 3 is formed by line 3 and angle 2 is formed by line b. Angle 1 is the third angle. Which set of statements about the angles is true? Angle 1 is congruent to angle 6, angle 5 is congruent to angle 4, angle 3 is congruent to angle 2 Angle 2 is congruent to angle 4, angle 3 is congruent to angle 6, angle 1 is congruent to angle 5 Angle 3 is congruent to angle 6, angle 1 is congruent to angle 2, angle 5 is congruent to angle 4 Angle 6 is congruent to angle 1, angle 5 is congruent to angle 3, angle 4 is congruent to angle 2

Answers

Answer:

a

Step-by-step explanation:

Answer:

add all angles

Step-by-step explanation:

Solve the equation. And write all solutions in general form.

Answers

Answer:

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Step-by-step explanation:

8 cos^2 x + 4 cos x-4 = 0

Divide by 4

2 cos^2 x +  cos x-1 = 0

Let u = cos x

2 u^2 +u -1 =0

Factor

(2u -1) ( u+1) = 0

Using the zero product property

2u-1 =0    u+1 =0

u = 1/2      u = -1

Substitute cosx for u

cos x = 1/2    cos x = -1

Take the inverse cos on each side

cos ^-1(cos x) = cos ^-1(1/2)   cos ^-1( cos x) =cos ^-1( -1)

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Can someone help me? Please i need this done

Answers

Your answer is y=-10x+8b I think. This is because on the x axis it hits -10 and on the y axis it’s 8

Which recursive formula defines this sequence for n > 1?3, 6, 9, 12, 15, 18, ...


Question 4 options:


an=3an−1


an=an−1+3


an=13an−1


an=an−1−3

Answers

Answer:

(B)a_n=a_(n-1)+3

Step-by-step explanation:

Given the sequence: 3, 6, 9, 12, 15, 18, ...

6=3+3

9=6+3

12=9+3

If we continue in like manner, we notice that the nth term (a_n) is an addition of 3 to the previous term (a_(n-1)).

Therefore (for n>1), the recursive formula which defines the sequence is:

a_n=a_(n-1)+3

The correct option is B

I NEED HELP WITH #5 PLZ ! Need by midnight and plz tell me how you solved it. Thank you in advance.

Answers

Answer:

Perimeter A  = 122.5

Step-by-step explanation:

Set up the following proportion

The Perimeter of B = 12 + 9 + 9 + 5

The Perimeter of B = 35

7/2 = x/PerimeterB

7/2 = x / 35                   Cross multiply

7*35 = 2x                      Combine the left side

245  = 2x                      Divide by 2

245/2 = 2x/2                Do the division

122.5 = x

The Perimeter of A = 122.5

Problem 3

If you compare the sides opposite the angle marked with a single arc, you will get the scale factor.

If these triangles are similar, and one of the sides opposite their markings will give you the scale factor

18/7.2 = x/1 where x is the scale factor going from the larger to the smaller triangle.

2.5 = x

So if you multiply the smaller triangle's sides by 2.5 you get the larger triangle.